题目&题意:

倒着找处于最后位置的等差数列的开头的位置。

例:

1 5 3 4 5 6

3 4 5 6是等差数列,它的开头的位置是3

PS:

读题真的很重要!!!!多组输入,上来就读错了!!

代码:

#include <bits/stdc++.h>
#define inf 0x3f3f3f3f
#define FRE() freopen("in.txt","r",stdin)
using namespace std;
typedef long long ll;
const int maxn = 5e3+;
int dp[maxn][maxn];
int a[maxn]; int main(){
//FRE();
int n;
while(scanf("%d",&n)!=EOF){
for(int i=; i<=n; i++){
scanf("%d",&a[i]);
}
int d = a[n] - a[n-],index = ,ok = ;
for(int i = n-; i>=; i--){
if(a[i+]-a[i] != d){
index = i;
ok = ;
break;
}
}
if(ok)
printf("%d\n",index+);
else
printf("%d\n",index);
}
return ;
}
/*
PutIn:
5
1 2 3 4 5
7
1 2 3 4 5 8 8
3
7 5 2
PutOut:
1
6
2
*/

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