2018 Arab Collegiate Programming Contest (ACPC 2018) E - Exciting Menus AC自动机
建个AC自动机求个fail指针就好啦。
#include<bits/stdc++.h>
#define LL long long
#define fi first
#define se second
#define mk make_pair
#define PLL pair<LL, LL>
#define PLI pair<LL, int>
#define PII pair<int, int>
#define SZ(x) ((int)x.size())
#define ull unsigned long long using namespace std; const int N = 1e5 + ;
const int M = 1e6 + ;
const int inf = 0x3f3f3f3f;
const LL INF = 0x3f3f3f3f3f3f3f3f;
const int mod = 1e9 + ;
const double eps = 1e-;
const double PI = acos(-); int n, a[N];
string s[N]; struct Ac {
int ch[N][], val[N], f[N], mx[N], depth[N], deg[N], tot, sz;
inline int newNode() {
tot++; f[tot] = ; val[tot] = ; mx[tot] = , deg[tot] = ;
memset(ch[tot], , sizeof(ch[tot]));
return tot;
}
void init(int _sz) {sz = _sz; tot = -; newNode();}
inline int idx(int c) {return c - 'a';}
void addStr(string& s, int *a) {
int u = ;
for(int i = ; i < s.size(); i++) {
int c = idx(s[i]);
if(!ch[u][c]) ch[u][c] = newNode();
u = ch[u][c];
val[u]++;
depth[u] = i + ;
mx[u] = max(mx[u], a[i]);
}
}
void build() {
queue<int> que;
for(int c = ; c < sz; c++) {
int v = ch[][c];
if(!v) ch[][c] = ;
else f[v] = , que.push(v);
}
while(!que.empty()) {
int u = que.front(); que.pop();
for(int c = ; c < sz; c++) {
int v = ch[u][c];
if(!v) ch[u][c] = ch[f[u]][c];
else f[v] = ch[f[u]][c], deg[f[u]]++, que.push(v);
}
}
}
void solve() {
init();
cin >> n;
for(int i = ; i <= n; i++) cin >> s[i];
for(int i = ; i <= n; i++) {
for(int j = ; j < s[i].size(); j++) cin >> a[j];
addStr(s[i], a);
}
build();
queue<int> que;
for(int i = ; i <= tot; i++) if(!deg[i]) que.push(i);
while(!que.empty()) {
int u = que.front(); que.pop();
mx[f[u]] = max(mx[f[u]], mx[u]);
deg[f[u]]--;
if(!deg[f[u]]) que.push(f[u]);
}
LL ans = ;
for(int i = ; i <= tot; i++)
ans = max(ans, 1ll*val[i]*mx[i]*depth[i]);
cout << ans << "\n";
}
} ac; int main() {
freopen("exciting.in", "r", stdin);
int T; scanf("%d", &T);
while(T--) {
ac.solve();
}
return ;
} /*
*/
2018 Arab Collegiate Programming Contest (ACPC 2018) E - Exciting Menus AC自动机的更多相关文章
- 2018 Arab Collegiate Programming Contest (ACPC 2018) H - Hawawshi Decryption 数学 + BSGS
H - Hawawshi Decryption 对于一个给定的生成数列 R[ 0 ] 已知, (R[ i - 1 ] * a + b) % p = R[ i ] (p 是 质数), 求最小的 x 使得 ...
- 2018 Arab Collegiate Programming Contest (ACPC 2018) G. Greatest Chicken Dish (线段树+GCD)
题目链接:https://codeforces.com/gym/101991/problem/G 题意:给出 n 个数,q 次询问区间[ li,ri ]之间有多少个 GCD = di 的连续子区间. ...
- 2018 German Collegiate Programming Contest (GCPC 18)
2018 German Collegiate Programming Contest (GCPC 18) Attack on Alpha-Zet 建树,求lca 代码: #include <al ...
- (寒假GYM开黑)2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018)
layout: post title: 2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018) author: &qu ...
- (寒假GYM开黑)2018 German Collegiate Programming Contest (GCPC 18)
layout: post title: 2018 German Collegiate Programming Contest (GCPC 18) author: "luowentaoaa&q ...
- 2018 China Collegiate Programming Contest Final (CCPC-Final 2018)-K - Mr. Panda and Kakin-中国剩余定理+同余定理
2018 China Collegiate Programming Contest Final (CCPC-Final 2018)-K - Mr. Panda and Kakin-中国剩余定理+同余定 ...
- 2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018)- D. Delivery Delays -二分+最短路+枚举
2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018)- D. Delivery Delays -二分+最短路+枚举 ...
- 2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018)-E. Explosion Exploit-概率+状压dp
2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018)-E. Explosion Exploit-概率+状压dp [P ...
- 2019年湖南多校第一场||2018-2019 ACM-ICPC Nordic Collegiate Programming Contest (NCPC 2018)
第一场多校就打的这么惨,只能说自己太菜了,还需继续努力啊- 题目链接: GYM链接:https://codeforces.com/gym/101933 CSU链接:http://acm.csu.edu ...
随机推荐
- springboot中radis配置和使用【进阶二】
1.yml文件配置 #redis哨兵模式配置 redis: namespace: xxx:xxx:redis connection: cacheRedis: database: 0 timeout: ...
- Spring Boot -Shiro配置多Realm
核心类简介 xxxToken:用户凭证 xxxFilter:生产token,设置登录成功,登录失败处理方法,判断是否登录连接等 xxxRealm:依据配置的支持Token来认证用户信息,授权用户权限 ...
- 【uoj428】普通的计数题
Portal --> uoj428 Solution 不会胖子的一个log正解qwq只能怂怂滴写分治了qwq 首先就是一个我想不到的转化qwq 我们将第\(i\)次操作加入的数看成一个编 ...
- HDFS之append数据到已存在文件中
遇到一个问题,想往已存在的hdfs文件中直接添加数据,默认的话应该是被拒绝的.查看了一些资料,可以这样操作: 在pdfs-site.xml中添加append支持: <property> & ...
- xgboost入门与实战(原理篇)
sklearn实战-乳腺癌细胞数据挖掘 https://study.163.com/course/introduction.htm?courseId=1005269003&utm_campai ...
- Nginx的基本配置案例
Nginx的基本配置案例 作者:尹正杰 版权声明:原创作品,谢绝转载!否则将追究法律责任. 一.Nginx配置虚拟主机 .操作系统环境 [root@yinzhengjie ~]# cat /etc ...
- python---django中orm的使用(2)
1.基于对象的正向查询和反向查询 在python---django中orm的使用(1)中也提到了正向和反向查找 表:一对多 书籍和出版社 class Book(models.Model): titl ...
- 数据库类型与JDBC TYPE 和Java类型对应关系
https://blog.csdn.net/seelye/article/details/40105969
- 安装mongodb以及设置为windows服务 详细步骤
我的win7 32的,注意版本要正确! 一.下载mongodb压缩包:mongodb-win32-i386-2.6.9.zip() 二.在D盘新建文件夹mongodb,将压缩我的解压文件放进去(有一个 ...
- [原]Android 初遇Http错误 httpClient.execute
错误源头: HttpResponse response = httpClient.execute(httpget); 错误信息: android.os.NetworkOnMainThreadExcep ...