LeetCode Reverse Words in a String II
原题链接在这里:https://leetcode.com/problems/reverse-words-in-a-string-ii/
题目:
Given an input string , reverse the string word by word.
Example:
Input: ["t","h","e"," ","s","k","y"," ","i","s"," ","b","l","u","e"]
Output: ["b","l","u","e"," ","i","s"," ","s","k","y"," ","t","h","e"]
Note:
- A word is defined as a sequence of non-space characters.
- The input string does not contain leading or trailing spaces.
- The words are always separated by a single space.
Follow up: Could you do it in-place without allocating extra space?
题解:
input变成 char array.
先reverse 全部 char array. 从头往后走,遇到空格或者array尾部,就reverse中间的单词.
Note: Do NOT forget i == n, reverse.
Time Compelxity: O(s.length()). Space: O(1).
AC Java:
public class Solution {
public void reverseWords(char[] s) {
if(s == null || s.length == 0){
return;
}
reverse(s, 0, s.length-1);
int lo = 0;
for(int i = 1; i<=s.length; i++){
if(i == s.length || s[i] == ' '){
reverse(s, lo, i-1);
lo = i+1;
}
}
}
private void reverse(char [] s, int i, int j){
while(i < j){
swap(s, i++, j--);
}
}
private void swap(char [] s, int i , int j){
char temp = s[i];
s[i] = s[j];
s[j] = temp;
}
}
跟上Reverse Words in a String III, Rotate Array.
LeetCode Reverse Words in a String II的更多相关文章
- [LeetCode] Reverse Words in a String II 翻转字符串中的单词之二
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
- [LeetCode] Reverse Vowels of a String 翻转字符串中的元音字母
Write a function that takes a string as input and reverse only the vowels of a string. Example 1:Giv ...
- [LeetCode] Reverse Words in a String 翻转字符串中的单词
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue ...
- [LeetCode] Reverse Words in a String III 翻转字符串中的单词之三
Given a string, you need to reverse the order of characters in each word within a sentence while sti ...
- LeetCode: Reverse Words in a String:Evaluate Reverse Polish Notation
LeetCode: Reverse Words in a String:Evaluate Reverse Polish Notation Evaluate the value of an arithm ...
- [LeetCode] 186. Reverse Words in a String II 翻转字符串中的单词 II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
- Reverse Words in a String I & Reverse Words in a String II
Reverse Words in a String I Given an input string, reverse the string word by word. For example,Give ...
- LeetCode Reverse Words in a String III
原题链接在这里:https://leetcode.com/problems/reverse-words-in-a-string-iii/#/description 题目: Given a string ...
- [Swift]LeetCode186. 翻转字符串中的单词 II $ Reverse Words in a String II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...
随机推荐
- 【CF】148D Bag of mice
http://codeforces.com/problemset/problem/148/D 题意:w个白b个黑,公主和龙轮流取,公主先取,等概率取到一个.当龙取完后,会等概率跳出一只.(0<= ...
- BZOJ3442: 学习小组
Description [背景] 坑校准备鼓励学生参加学习小组. [描述] 共有n个学生,m个学习小组,每个学生有一定的喜好,只愿意参加其中的一些学习小组,但是校领导为学生考虑,规定一个学生最 ...
- osg中的视点控制
osg中的视点控制 osg的视点控制基类是CameraManipulator, 它是一个虚基类, 有用的方法都跟home有关. 在这个类里面有三个重要的成员变量: osg::Vec3d _homeEy ...
- spring源码学习之路---深入AOP(终)
作者:zuoxiaolong8810(左潇龙),转载请注明出处,特别说明:本博文来自博主原博客,为保证新博客中博文的完整性,特复制到此留存,如需转载请注明新博客地址即可. 上一章和各位一起看了一下sp ...
- poj 2239 二分图最大匹配,基础题
1.poj 2239 Selecting Courses 二分图最大匹配问题 2.总结:看到一个题解,直接用三维数组做的,很巧妙,很暴力.. 题意:N种课,给出时间,每种课在星期几的第几节课上 ...
- IOS 蓝牙相关-BabyBluetooth蓝牙库介绍(4)
BabyBluetooth 是一个最简单易用的蓝牙库,基于CoreBluetooth的封装,并兼容ios和mac osx. 特色: 基于原生CoreBluetooth框架封装的轻量级的开源库,可以帮你 ...
- 转载:C# this.invoke()作用 多线程操作UI 理解二
Invoke()的作用是:在应用程序的主线程上执行指定的委托.一般应用:在辅助线程中修改UI线程( 主线程 )中对象的属性时,调用this.Invoke(); //测试的窗体 public class ...
- 对AFN的二次封装
.h .m
- 快排java实现
package sort; public class QuickSort { public static final int cutoff = 3; /** * insertion sort * * ...
- 已知树的前序、中序,求后序的java实现&已知树的后序、中序,求前序的java实现
public class Order { int findPosInInOrder(String str,String in,int position){ char c = str.charAt(po ...