A

A - Water~melon

Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u

Submit

Status

Practice

CodeForces 4A

Description

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that’s why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that’s why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

Input

The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

Output

Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

Sample Input

Input

8

Output

YES

Hint

For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

AC代码:

#include <stdio.h>
int main (){
int n;
scanf("%d",&n);
if(n==2) printf("NO");
else if (n%2==0) printf("YES");
else printf("NO");
return 0;
}

题意:如果一个数可以被拆成两个偶数相加,即输出YES,等价于输入一个数,如果这个数是偶数,输出YES,否则输出NO

注意:2 要单独考虑输出NO

zsy:

题意:给出一个1-100的数,判断能否拆成两个偶数之和。

思路:所有除二以外的偶数都可拆成两个偶数之和。

//#define LOCAL
#include <stdio.h> int main(){
int w;
#ifdef LOCAL
freopen("input.txt","r",stdin);
// freopen("output.txt","w",stdout);
#endif
while(~scanf("%d",&w)){
if(w==2) { //注意对w==2的情况
printf("NO\n");
continue;
}
if(w%2==0) printf("YES\n");
else printf("NO\n");
}
return 0;
}

CodeForces 4A的更多相关文章

  1. Watermelon -- codeforces

    http://acm.hust.edu.cn/vjudge/contest/view.action?cid=93241#problem/A  (654123) http://codeforces.co ...

  2. codeforces4A

    Watermelon CodeForces - 4A Qingyu有一个简单的问题想让你解决. 输入一个数,如果它是2,或者它是奇数,输出NO,否则输出YES. 很简单吧,因此你应该很快解决. 输入 ...

  3. Codeforces 725B Food on the Plane

    B. Food on the Plane time limit per test:2 seconds memory limit per test:256 megabytes input:standar ...

  4. Codeforces 438E The Child and Binary Tree - 生成函数 - 多项式

    题目传送门 传送点I 传送点II 传送点III 题目大意 每个点的权值$c\in {c_{1}, c_{2}, \cdots, c_{n}}$,问对于每个$1\leqslant s\leqslant ...

  5. Codeforces 488B - Candy Boxes

    B. Candy Boxes 题目链接:http://codeforces.com/problemset/problem/488/B time limit per test 1 second memo ...

  6. Codeforces初体验

    Codeforces印象 这两天抽时间去codeforces体验了一把. 首先,果然有众多大牛存在.非常多名人一直參加每周一次的比赛.积分2000+,并參与出题. 另外.上面题目非常多.预计至少一千题 ...

  7. Codeforces Round #586 (Div. 1 + Div. 2) D. Alex and Julian

    链接: https://codeforces.com/contest/1220/problem/D 题意: Boy Dima gave Julian a birthday present - set ...

  8. [Codeforces 163D]Large Refrigerator (DFS+剪枝)

    [Codeforces 163D]Large Refrigerator (DFS+剪枝) 题面 已知一个长方体的体积为V,三边长a,b,c均为正整数,求长方体的最小表面积S V以质因数分解的形式给出 ...

  9. python爬虫学习(5) —— 扒一下codeforces题面

    上一次我们拿学校的URP做了个小小的demo.... 其实我们还可以把每个学生的证件照爬下来做成一个证件照校花校草评比 另外也可以写一个物理实验自动选课... 但是出于多种原因,,还是绕开这些敏感话题 ...

随机推荐

  1. 如何将两个字段合成一个字段显示(oracle和sqlserver的区别)

    oracle中,如何将两个字段数据合并成一个字段显示,接下来看一下在sql server和pl/sql的区别 sql server中如何合并(用Cast()函数) --1.创建模拟的数据表--- cr ...

  2. latex 公式距离

    \setlength{\abovedisplayshortskip}{0cm} 公式和文本之间的间距 \setlength{\belowdisplayshortskip}{0cm} \setlengt ...

  3. ubuntu shell编程笔记

    and 命令 if  [   A  -a   B ] then else fi while [ ] do done set command set  these are parameters $1 s ...

  4. HTTP上传数据 :表单,二进制数据(multipart/form-data application/octet-stream boundary)

    使用WinINet 一个较简单的例子:上传头像 void CBackstageManager::UpdateAvatarThreadProc(LPVOID params) { stForThread* ...

  5. ckeditor富文本编辑器的基本配置设置:

    原文地址:http://blog.csdn.net/wei365456yin/article/details/54618970?locationNum=5&fps=1 1.首先下载ckedit ...

  6. linux系统管理 启停命令

    mac下Linux的登录命名 'ssh -l root 192.168.10.109' password: xxxx ​ 退出登录 >> logout shutdown命令 要使用这个命令 ...

  7. bootstrap学习参考网站

    ----https://www.     evget    .com   /article /

  8. 玩转X-CTR100 l STM32F4 l 定时器时间测量

    我造轮子,你造车,创客一起造起来!塔克创新资讯[塔克社区 www.xtark.cn ][塔克博客 www.cnblogs.com/xtark/ ] 本文介绍X-CTR100控制器 使用处理器内部硬件定 ...

  9. SharePoint online Multilingual support - Settings

    博客地址:http://blog.csdn.net/FoxDave This post will talk about how to enable sharepoint online site mul ...

  10. synchronized 和 ReentrantLock 区别

    synchronized 使用: 1:当一个线程访问object的一个synchronized(this)同步代码块时,它就获得了这个object的对象锁.结果,其它线程对该object对象所有同步代 ...