package airycode_java8.nice7;

import airycode_java8.nice1.Employee;
import org.junit.Test; import java.util.Arrays;
import java.util.List;
import java.util.Optional;
import java.util.stream.Collectors; /**
* Created by admin on 2019/1/3.
*/
public class TestStramAPI { /***
* 1.给定一个数字列表,如何返回一个由每一个数字的平方构成的列表,给定【1,2,3,4,5】返回[1,4,9,16,25]
*/
@Test
public void test1(){
List<Integer> list = Arrays.asList(1,2,3,4,5);
List<Integer> collect = list.stream().map((x) -> x * x).collect(Collectors.toList());
collect.forEach(System.out::println);
} /***
* 2.用map和reduce方法数数流中有多少个emplloyee
*
*/
//准备数据
static List<Employee> employeeList = Arrays.asList(
new Employee("张三",18,9999.99, Employee.Status.FREE),
new Employee("李四",38,5555.55,Employee.Status.BUSY),
new Employee("王五",50,6666.66,Employee.Status.VOCATION),
new Employee("赵六",16,3333.33,Employee.Status.FREE),
new Employee("田七",8,7777.77,Employee.Status.BUSY) );
@Test
public void test2(){
Optional<Integer> sum = employeeList.stream().map((e) -> 1).reduce(Integer::sum);
System.out.println(sum.get());
} }

  交易员和交易练习:

package airycode_java8.nice7;

/**
* 交易员对象
* Created by admin on 2019/1/3.
*/
public class Trader { private String name;
private String city; public Trader(String name, String city) {
this.name = name;
this.city = city;
} public String getName() {
return name;
} public void setName(String name) {
this.name = name;
} public String getCity() {
return city;
} public void setCity(String city) {
this.city = city;
} @Override
public String toString() {
return "Trader{" +
"name='" + name + '\'' +
", city='" + city + '\'' +
'}';
}
} package airycode_java8.nice7; /**
* 交易对象
* Created by admin on 2019/1/3.
*/
public class Transaction { private Trader trader;
private int year;
private int value;
private String currency; public Transaction(Trader trader,int year,int value,String currency){
this.trader = trader;
this.year = year;
this.value = value;
this.currency = currency;
} public Trader getTrader(){
return trader;
}
public int getYear(){
return year;
}
public int getValue(){
return value;
}
public String getCurrency(){
return currency;
} @Override
public String toString(){
return "i am transaction : my trader is : "
+ trader.getName()
+ " ; my year is : "
+ year
+ " ; my value is : "
+ value
+ " ; my currency is : "
+ currency;
}
} package airycode_java8.nice7; import org.junit.Before;
import org.junit.Test; import java.util.*;
import java.util.function.Function;
import java.util.stream.Collectors; import static java.util.Comparator.comparingInt;
import static java.util.stream.Collectors.*;
/**
* Created by admin on 2019/1/3.
*/
public class TraderExercise { List<Trader> traders = new LinkedList<>();
List<Transaction> transactions = new LinkedList<>(); @Before
public void init(){ Trader t1 = new Trader("trader1","剑桥");
Trader t2 = new Trader("trader2","米兰");
Trader t3 = new Trader("trader3","剑桥");
Trader t4 = new Trader("trader4","剑桥");
traders.addAll(Arrays.asList(t1,t2,t3,t4)); Transaction tran1 = new Transaction(t4,2011,300,"$");
Transaction tran2 = new Transaction(t1,2012,1000,"$");
Transaction tran3 = new Transaction(t1,2011,400,"¥");
Transaction tran4 = new Transaction(t2,2012,710,"¥");
Transaction tran5 = new Transaction(t2,2012,700,"$");
Transaction tran6 = new Transaction(t3,2012,950,"¥");
transactions.addAll(Arrays.asList(tran1,tran2,tran3,tran4,tran5,tran6));
} /***
* 1.2011年的所有交易并按照金额由小到大排序
*/
@Test
public void test1(){
transactions.stream()
.filter((t)->t.getYear() == 2011)
.sorted((t1,t2)->Integer.compare(t1.getValue(),t2.getValue()))
.forEach(System.out::println);
} /***
*2.交易员都在哪些不同的城市生活
*/
@Test
public void test2(){ traders.stream()
.map(Trader::getCity)
.distinct()
.forEach(System.out::println); } /***
*3.查找所有来自剑桥的交易员,并按姓名排序
*/
@Test
public void test3(){ // traders.stream()
// .filter((t)->"剑桥".equals(t.getCity()))
// .sorted((e1,e2)->e1.getName().compareTo(e2.getName()))
// .forEach(System.out::println);
traders.stream()
.filter((t)->"剑桥".equals(t.getCity()))
.sorted(Comparator.comparing(Trader::getName))
.forEach(System.out::println); } /***
*4.查询所有交易员的姓名字符串,并按字母排序
*/
@Test
public void test4(){ traders.stream()
.filter((t)->"剑桥".equals(t.getCity()))
.sorted(Comparator.comparing(Trader::getName))
.forEach(System.out::println); } /***
*5.有没有交易员在米兰
*/
@Test
public void test5(){ boolean any = traders.stream()
.filter((t) -> "米兰".equals(t.getCity()))
.findAny()
.isPresent();
System.out.println(any); } /***
* 6.打印在剑桥生活的交易员的所有交易金额
*/
@Test
public void test6(){ Integer sum = transactions.stream()
.filter(tran -> "剑桥".equals(tran.getTrader().getCity()))
.map(Transaction::getValue)
.reduce(0, (val1, val2) -> val1 + val2);
System.out.println(sum); } /***
* 7.所有交易中,最高的交易额是多少
*/
@Test
public void test7(){
transactions.stream()
.sorted(Comparator.comparing(Transaction::getValue).reversed())
.findFirst()
.ifPresent(System.out::println); transactions.stream()
.map(Transaction::getValue)
.reduce(Integer::max)
.ifPresent(System.out::println);
} /***
* 8.找到交易额中最小的金额
*/
@Test
public void test8(){
transactions.stream()
.map(Transaction::getValue)
.reduce(Integer::min)
.ifPresent(System.out::println); transactions.stream()
.min(Comparator.comparing(Transaction::getValue))
.ifPresent(System.out::println); transactions.stream()
.min(Comparator.comparing((Transaction t1) -> t1.getValue()))
.ifPresent(System.out :: println); } /***
* 9.统计每个交易员的记录
*/
@Test
public void test9(){
transactions.stream()
.collect(groupingBy(Transaction::getTrader))
.entrySet().stream()
.forEach(System.out::println); } /***
* 10.找到单笔交易最高的交易员
*/
@Test
public void test10(){
transactions.stream()
.max(Comparator.comparing(Transaction::getValue))
.ifPresent(tran->{
System.out.println(tran.getTrader());
});
} /***
* 11.统计交易总额最高的交易员(排序)
*/
@Test
public void test11(){
transactions.stream().collect(groupingBy(Transaction::getTrader))
.entrySet().stream().map(t->{
Map<String,Object> result = new HashMap<>();
int sum = t.getValue().stream().mapToInt(Transaction :: getValue).sum();
result.put("sum",sum);
result.put("trader",t.getKey());
return result; }).sorted(comparingInt((Map m) -> (int)m.get("sum")).reversed()).findFirst().ifPresent(System.out::println);
} /***
* 12.使用方法引用对transaction排序
*/
@Test
public void test12(){
transactions.stream().sorted(Comparator.comparing(Transaction::getValue)).forEach(System.out::println); System.out.println("--------------------------------------------------------------------------------"); //声明接口的实现方式
Function<Transaction,Integer> function = Transaction :: getValue;
Transaction[] transactionsArray = new Transaction[transactions.size()];
Arrays.sort(transactions.toArray(transactionsArray),Comparator.comparing(function));
Arrays.asList(transactionsArray).stream().forEach(System.out :: println);
} /***
* 13.根据trader(对象)将transaction分组
*/
@Test
public void test13(){
transactions.stream()
.collect(groupingBy(Transaction :: getTrader))
.entrySet().stream()
.forEach(System.out :: println);
} //【14.根据货币(字符串)类型分组
@Test
public void exercise14(){
transactions.stream()
.collect(groupingBy(Transaction :: getCurrency))
.entrySet().stream()
.forEach(System.out :: println);
}
//【15.获取交易总金额
@Test
public void exercise15(){
int sum1 = transactions.stream().mapToInt(Transaction::getValue).sum();
System.out.println("通过map转换求和sum1 = " + sum1);
int sum2 = transactions.stream().collect(Collectors.summingInt(Transaction::getValue));
System.out.println("通过collect汇总求和sum2 = " + sum2);
//规约操作都需要使用map将对象映射为返回值的类型
int sum3 = transactions.stream().map(Transaction::getValue).reduce(0,(t1,t2) -> t1 + t2);
System.out.println("通过reduce规约求和sum3 = " + sum3);
}
//【16.二级分类,先按照交易员分类,然后交易金额大于800归为high,低于800归为low
@Test
public void exercise16(){
transactions.stream()
.collect(groupingBy(Transaction :: getTrader,groupingBy(t -> {
if(t.getValue()< 800 ){
return "low";
}else {
return "heigh";
}
})))
.entrySet().stream()
.forEach(System.out :: println);
}
//【17.获取每个交易员,交易最大的一笔
@Test
public void exercise17(){
transactions.stream()
.collect(groupingBy(Transaction::getTrader,maxBy(Comparator.comparingInt(Transaction::getValue))))
.entrySet().stream()
.distinct()
.sorted(Comparator.comparing((Map.Entry m) -> {
Trader t = (Trader) m.getKey();
return t.getName();
}))
.forEach(System.out :: println);
} }

  

JAVA_Stream_练习的更多相关文章

随机推荐

  1. angular ajax请求 结果显示显示两次的问题

    angular 项目中,由于用到ajax 请求,结果显示如下情况 同样的接口,显示两次,其中第一次请求情况为 request method 显示为opttions 第二次的情况是 为啥会出现如此的情况 ...

  2. prometheus: celery, redis-export

    https://github.com/nlighten/tomcat_exporter https://github.com/prometheus/jmx_exporter https://vexxh ...

  3. P3292 [SCOI2016]幸运数字 线性基

    正解:线性基+倍增 解题报告: 先放下传送门QAQ 然后这题,其实没什么太大的技术含量,,,?就几个知识点套在一起,除了代码长以外没任何意义,主要因为想复习下线性基的题目所以还是写下,,, 随便写下思 ...

  4. fork多线程进程时的坑(转)

    add : 在fork多线程的进程时,创建的子进程只包含一个线程,该线程是调用fork函数的那个线程的副本.在man fork中,有The child process is created with ...

  5. mysql大表更新sql的优化策略(转)

    看了该文章之后,很受启发,mysql在update时,一般也是先select.但注意,在Read Committed隔离级别下,如果没有使用索引,并不会锁住整个表, 还是只锁住满足查询条件的记录而已. ...

  6. nodejs 学习五 单元测试一

    一. chai chai 自身是依赖nodejs的 assert,让检测更加语义化. chai 采用两种模式,TDD和BDD, TDD是类似自然语言方式 BDD是结构主义 chai文旦地址 二.moc ...

  7. C++的类大小

    有以下C++类 #pragma pack(push) #pragma pack(1) class task /*:public OSThread*/{ //public: // void Entry( ...

  8. wc 统计命令

    [root@localhost ~]# wc /etc/passwd // 统计行数.单词数.字符数 /etc/passwd [root@localhost ~]# wc -l /etc/passwd ...

  9. VMware Workstation 不可恢复错误 解决方法

    问题: VMware Workstation 不可恢复错误: (vcpu-0) vcpu-0:VERIFY vmcore/vmm/main/cpuid.c:386 bugNr=1036521 日志文件 ...

  10. 20170731 培训Bootstrap

    Bootstrap使用 涉及培训内容框架:--1 html html为标记语言,可以理解为容器,就是用来承载你想要展示到网页的内容的容器.版本也有很多,不同版本表示不同的标记的新增或者取代. Boot ...