Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.

Notes:

    • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is empty operations are valid.
    • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.

You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

代码如下:

class MyQueue {
// Push element x to the back of queue.
Stack<Integer> stack1=new Stack<Integer>();
Stack<Integer> stack2=new Stack<Integer>();
public void push(int x) {
stack1.push(x);
} // Removes the element from in front of queue.
public void pop() {
while(stack1.size()>1) stack2.push(stack1.pop());
stack1.pop();
while(stack2.size()>0) stack1.push(stack2.pop());
} // Get the front element.
public int peek() {
while(stack1.size()>1) stack2.push(stack1.pop());
int x= stack1.peek();
while(stack2.size()>0) stack1.push(stack2.pop());
return x;
} // Return whether the queue is empty.
public boolean empty() {
return stack1.empty();
}
}

  运行结果:

(easy)LeetCode 232.Implement Queue using Stacks的更多相关文章

  1. Leetcode 232 Implement Queue using Stacks 和 231 Power of Two

    1. 232 Implement Queue using Stacks 1.1 问题描写叙述 使用栈模拟实现队列.模拟实现例如以下操作: push(x). 将元素x放入队尾. pop(). 移除队首元 ...

  2. [LeetCode] 232. Implement Queue using Stacks 用栈来实现队列

    Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...

  3. Java [Leetcode 232]Implement Queue using Stacks

    题目描述: Implement the following operations of a queue using stacks. push(x) -- Push element x to the b ...

  4. LeetCode 232 Implement Queue using Stacks

    Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...

  5. Java for LeetCode 232 Implement Queue using Stacks

    Stack<Integer> stack=new Stack<Integer>(); public void push(int x) { stack.push(x); } // ...

  6. Leetcode 232 Implement Queue using Stacks STL

    本题用两个栈实现队列,用栈的基本操作去实现队列的所有基本操作push(),pop(),peek()以及empty() sa作为输入栈,sb作为输出栈,将sa输入元素的反转过来放到sb中 push与sa ...

  7. LeetCode 232 Implement Queue using Stacks 两个栈实现队列

    class MyQueue { public: /** Initialize your data structure here. */ MyQueue() { } /** Push element x ...

  8. leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues

    155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...

  9. 232. Implement Queue using Stacks,225. Implement Stack using Queues

    232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Im ...

随机推荐

  1. EmEditor处理大文本文件

    前段时间新闻网由于用户不当操作.导致三年的报纸栏目内容全部清空.紧急情况下只能求助于SQL数据恢复.但备份的数据文件有500M左右. 首先用的文本编辑器是Notepad++,打开之后软件几乎完全卡死. ...

  2. HTML5服务器推送事件

    目前客户端(浏览器)和服务端交互大致有以下几种方式: 1)form表单提交方式,适合访问量不大,对用户体验要求不高的web系统开发,或者页面整体刷新无伤大雅的场合,通信方向是客户端提交给服务端,是客户 ...

  3. 读取Config文件工具类 PropertiesConfig.java

    package com.util; import java.io.BufferedInputStream; import java.io.FileInputStream; import java.io ...

  4. 目录处理工具类 DealWithDir.java

    package com.util; import java.io.File; /** * 目录处理工具类 * */ public class DealWithDir { /** * 新建目录 */ p ...

  5. @media_screen

    html,body{ margin:0; padding:0; }body{ background:#0f0;} /* @media screen and (min-width: 800px)and( ...

  6. Eclipse换常用的快捷键

    还是喜欢ctrl+tab键来切换窗口,ctrl+f6实在不好使. 修改方法:在eclipse中Window -> Perferences -> General -> Keys -&g ...

  7. (转)textarea去掉右侧滚动条,去掉右下角拖拽

    本文转载自:http://blog.csdn.net/cctv_end/article/details/7946188 代码:  <TEXTAREA   style= "overflo ...

  8. android学习笔记二

    ADT(Android Development Tools)安卓开发工具. android项目目录简介 ==> src==>源代码文件 res==>资源文件 AndroidManif ...

  9. TCP中需要了解的东西

    1.TCP是一个流协议. TCP跟UDP不一样的是,TCP发送过去的东西是stream,也就是说第一次发送的跟第二次发送的数据包可能会粘在一起,即所谓的粘包问题 http://blog.csdn.ne ...

  10. linux awk命令

    简介 awk是一个强大的文本分析工具,相对于grep的查找,sed的编辑,awk在其对数据分析并生成报告时,显得尤为强大.简单来说awk就是把文件逐行的读入,以空格为默认分隔符将每行切片,切开的部分再 ...