[golang]内存不断增长bytes.makeSlice
------------------------------------------
2015.7月更新
后面发现这里其实有一个sb的问题,在于内存回收和释放。
每个http请求,都会带一个http.Request, 当请求并发数上来的时候,若不主动进行释放。垃圾回收机制会认为这个对象还不能回收。
其实这里的本质问题,是一个http连接的生命周期是如何管理的,代码封装的太好,也需要知道里面如何实现啊(后面有空研究一下源码),不然还是会踩坑。
func Action(w http.ResponseWriter, r *http.Request) { var result string
// handle func
// do something
w.Write([]byte(result))
r.Body.Close()
} func (h *XXXXHandler) ServeHTTP(w http.ResponseWriter, r *http.Request) {
Action(w, r)
}
------------------------------------
golang写的一个图片服务器,在批量下载压缩时候发现内存不断增长。。。。
幸好golang自带内存占用日志结合分析工具可以方便看到内存分布。
详细可参考:
http://blog.golang.org/profiling-go-programs
可以实时统计CPU\内存信息。
这里主要说一下内存怎么搞。CPU分析的参考之前的一篇文章。
//需要包含这个pprof包
import "runtime/pprof" //这里接收内存统计信息保存文件
var memprofile = flag.String("memprofile", "", "write memory profile to this file") //这里是判断是否需要记录内存的逻辑
if *memprofile != "" {
var err error
memFile, err = os.Create(*memprofile)
if err != nil {
log.Println(err)
} else {
log.Println("start write heap profile....")
pprof.WriteHeapProfile(memFile)
defer memFile.Close()
}
} //这里还有一个比较灵活的办法,把开启记录和关闭记录作为http请求,需要的时候开启\不需要的时候关闭。记得加上token
全部代码如下:
// GODEBUG=schedtrace=1000 ./trace_example
// GOMAXPROCS=2 GODEBUG=schedtrace=1000 ./trace_example
// GOMAXPROCS=2 GODEBUG=schedtrace=1000,scheddetail=1 ./trace_example package main import (
"flag"
"log"
"os"
"runtime/pprof"
// "net/http"
// _ "net/http/pprof"
"sync"
"time"
) //http://www.graphviz.org/Download_macos.php // var cpuprofile = flag.String("cpuprofile", "", "write cpu profile to file")
var memprofile = flag.String("memprofile", "", "write memory profile to this file") var memFile *os.File func main() {
flag.Parse()
// if *cpuprofile != "" {
// f, err := os.Create(*cpuprofile)
// if err != nil {
// log.Fatal(err)
// }
// pprof.StartCPUProfile(f)
// defer pprof.StopCPUProfile()
// } if *memprofile != "" {
var err error
memFile, err = os.Create(*memprofile)
if err != nil {
log.Println(err)
} else {
log.Println("start write heap profile....")
pprof.WriteHeapProfile(memFile)
defer memFile.Close()
}
} // go func() {
// log.Println(http.ListenAndServe("localhost:6060", nil))
// }() var wg sync.WaitGroup
wg.Add(10)
for i := 0; i < 10; i++ {
go work(&wg)
} wg.Wait()
// Wait to see the global run queue deplete.
time.Sleep(300 * time.Second)
} func work(wg *sync.WaitGroup) {
time.Sleep(time.Second) var counter int
for i := 0; i < 1e10; i++ {
time.Sleep(time.Millisecond * 100)
pprof.WriteHeapProfile(memFile)
counter++
}
wg.Done()
}
OK,加上这个内存分析数据之后,继续跑服务, 跑了一段时候之后,停止程序,采用以下命令进行分析。
go tool pprof image_service memory.log
(pprof) top20
2622.12MB of 4938.25MB total (53.10%)
Dropped 180 nodes (cum <= 24.69MB)
Showing top 20 nodes out of 30 (cum >= 419.23MB)
flat flat% sum% cum cum%
1759.43MB 35.63% 35.63% 1759.43MB 35.63% bytes.makeSlice
203.06MB 4.11% 39.74% 320.58MB 6.49% net/url.parseQuery
166.11MB 3.36% 43.10% 166.11MB 3.36% net/textproto.(*Reader).ReadLine
132.03MB 2.67% 45.78% 132.03MB 2.67% net/textproto.(*Reader).ReadMIMEHeader
117.52MB 2.38% 48.16% 117.52MB 2.38% net/url.unescape
71.02MB 1.44% 49.60% 71.02MB 1.44% mcommoninit
60.50MB 1.23% 50.82% 60.50MB 1.23% fmt.Sprintf
37.51MB 0.76% 51.58% 98.01MB 1.98% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).HandleRedo
35.51MB 0.72% 52.30% 333.65MB 6.76% net/http.ReadRequest
21.37MB 0.43% 52.73% 21.37MB 0.43% github.com/gographics/imagick/imagick._Cfunc_GoBytes
17.57MB 0.36% 53.09% 17.57MB 0.36% bufio.NewReaderSize
0.50MB 0.01% 53.10% 21.58MB 0.44% net/http.(*Transport).dialConn
0 0% 53.10% 21.87MB 0.44% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).CompressWithSizeList
0 0% 53.10% 1781.66MB 36.08% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).DoRecompress
0 0% 53.10% 1759.29MB 35.63% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).httpGetToMagickWand
0 0% 53.10% 17.57MB 0.36% bufio.NewReader
0 0% 53.10% 1759.43MB 35.63% bytes.(*Buffer).ReadFrom
0 0% 53.10% 21.37MB 0.43% github.com/gographics/imagick/imagick.(*MagickWand).GetImageBlob
0 0% 53.10% 419.23MB 8.49% main.(*ImageService).ServeHTTP
0 0% 53.10% 419.23MB 8.49% main.Action
(pprof) quit
初步可以定位到时下载压缩时,分配了太多byteSlice导致。
观察代码,没有发现具体原因,直到在网上发现了这篇文章:
http://openmymind.net/Go-Slices-And-The-Case-Of-The-Missing-Memory/
buffer := bytes.NewBuffer(make([]byte, 0, resp.ContentLength)
buffer.ReadFrom(res.Body)
body := buffer.Bytes()
A Memory Leak
Look, what's a memory leak within the context of a runtime that provides garbage collection? Typically it's either a rooted object, or a reference from a rooted object, which you haven't considered. This is obviously different as it's really extra memory you might not be aware of. Rooting the object might very well be intentional, but you don't realize just how much memory it is you've rooted. Sure, my ignorance is at least 75% to blame. Yet I can't help but shake the feeling that there's something too subtle about all of this. Any code can return something that looks and quacks like an array of 2 integers yet takes gigs of memory. Furthermore, bytes.MinRead
as a global variable is just bad design. I can't imagine how many people think they've allocated X when they've really allocated X*2+512.
大致的意思是说,这个buffer采用最小单位读,若不够,则继续申请2倍大的空间。
可以查看源码:
146 // ReadFrom reads data from r until EOF and appends it to the buffer, growing
147 // the buffer as needed. The return value n is the number of bytes read. Any
148 // error except io.EOF encountered during the read is also returned. If the
149 // buffer becomes too large, ReadFrom will panic with ErrTooLarge.
150 func (b *Buffer) ReadFrom(r io.Reader) (n int64, err error) {
151 b.lastRead = opInvalid
152 // If buffer is empty, reset to recover space.
153 if b.off >= len(b.buf) {
154 b.Truncate(0)
155 }
156 for {
157 if free := cap(b.buf) - len(b.buf); free < MinRead {
158 // not enough space at end
159 newBuf := b.buf
160 if b.off+free < MinRead {
161 // not enough space using beginning of buffer;
162 // double buffer capacity
163 newBuf = makeSlice(2*cap(b.buf) + MinRead)
164 }
165 copy(newBuf, b.buf[b.off:])
166 b.buf = newBuf[:len(b.buf)-b.off]
167 b.off = 0
168 }
169 m, e := r.Read(b.buf[len(b.buf):cap(b.buf)])
170 b.buf = b.buf[0 : len(b.buf)+m]
171 n += int64(m)
172 if e == io.EOF {
173 break
174 }
175 if e != nil {
176 return n, e
177 }
178 }
179 return n, nil // err is EOF, so return nil explicitly
180 }
解决方案:
//ioutil.ReadAll starts at a very small 512
//it really should let you specify an initial size
buffer := bytes.NewBuffer(make([]byte, 0, 65536))
io.Copy(buffer, r.Body)
temp := buffer.Bytes()
length := len(temp)
var body []byte
//are we wasting more than 10% space?
if cap(temp) > (length + length / 10) {
body = make([]byte, length)
copy(body, temp)
} else {
body = temp
}
稍微测试了以下,内存被垃圾回收了。为啥会出现这样的情况呢?
Entering interactive mode (type "help" for commands)
(pprof) top20
834.66MB of 1599.63MB total (52.18%)
Dropped 175 nodes (cum <= 8MB)
Showing top 20 nodes out of 25 (cum >= 72.01MB)
flat flat% sum% cum cum%
427.45MB 26.72% 26.72% 427.45MB 26.72% bytes.makeSlice
185.80MB 11.62% 38.34% 614.25MB 38.40% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).httpGetToMagickWand
69.01MB 4.31% 42.65% 69.01MB 4.31% net/textproto.(*Reader).ReadMIMEHeader
48MB 3.00% 45.65% 48MB 3.00% net/url.unescape
24.51MB 1.53% 47.18% 24.51MB 1.53% mcommoninit
24.01MB 1.50% 48.68% 72.01MB 4.50% net/url.parseQuery
24MB 1.50% 50.19% 117.02MB 7.32% net/http.ReadRequest
24MB 1.50% 51.69% 24MB 1.50% net/url.parse
7.87MB 0.49% 52.18% 7.87MB 0.49% github.com/gographics/imagick/imagick._Cfunc_GoBytes
0 0% 52.18% 7.87MB 0.49% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).CompressWithSizeList
0 0% 52.18% 622.62MB 38.92% _/home/qingpingzhang/project/createdji_servers/image_service/image.(*Handler).DoRecompress
0 0% 52.18% 427.95MB 26.75% bytes.(*Buffer).ReadFrom
0 0% 52.18% 7.87MB 0.49% github.com/gographics/imagick/imagick.(*MagickWand).GetImageBlob
0 0% 52.18% 72.01MB 4.50% main.(*ImageService).ServeHTTP
0 0% 52.18% 72.01MB 4.50% main.Action
0 0% 52.18% 72.01MB 4.50% net/http.(*Request).ParseForm
0 0% 52.18% 117.02MB 7.32% net/http.(*conn).readRequest
0 0% 52.18% 117.02MB 7.32% net/http.(*conn).serve
0 0% 52.18% 72.01MB 4.50% net/http.func·014
0 0% 52.18% 72.01MB 4.50% net/url.ParseQuery
在golang语言自带的bytes包里面申请的内存,为啥就不会很快被回收?
不解,IO操作这块儿还需要找时间重新学习一下。
[golang]内存不断增长bytes.makeSlice的更多相关文章
- golang内存分配
golang内存分配 new一个对象的时候,入口函数是malloc.go中的newobject函数 func newobject(typ *_type) unsafe.Pointer { flags ...
- Golang内存管理
Golang 内存管理 原文链接[http://legendtkl.com/2017/04/02/golang-alloc/] Golang 的内存管理基于 tcmalloc,可以说起点挺高的.但是 ...
- elasticsearch内存不断增长问题
经过一段时间运行,es的索引已经达到数十G以上.es采用mmap的方式将索引文件映射到内存中,随着检索的次数增加,越来越多的数据被操作系统读入到内存中.这部分内存位于系统中,但是又不归es管理,也就是 ...
- golang 内存监控
golang 内存监控 - 简书 https://www.jianshu.com/p/38dc129b6870
- Golang内存模型
Ref: https://golang.org/ref/mem 简介 golang内存模型,主要说明了如下问题.在一个goroutine中读取变量,而该变量是由其他goroutine赋值的,这种情况下 ...
- 记一次golang内存泄露
记一次golang内存泄露 最近在QA环境上验证功能时,发现机器特别卡,查看系统内存,发现可用(available)内存仅剩200多M,通过对进程耗用内存进行排序,发现有一个名为application ...
- 图解golang内存分配机制 (转)
一般程序的内存分配 在讲Golang的内存分配之前,让我们先来看看一般程序的内存分布情况: 以上是程序内存的逻辑分类情况. 我们再来看看一般程序的内存的真实(真实逻辑)图: Go的内存分配核心思想 G ...
- golang 内存模型
1,是什么 是一套规范.内存操作指导 解决多线程编程的 程序的 原子性,有序性,可见性(主要)的问题. 多核操作系统,会存在缓存不一致的情况,说到底是一个同步的问题. 2, 内容 内存模型,除了定义了 ...
- Golang内存分配内置函数之new函数
new函数用来分配内存,主要分配值类型,比如int.float32.struct等,返回的是指针 package main import ( "fmt" ) func main() ...
随机推荐
- Linux下C语言的调试
调试是每个程序员都会面临的问题. 如何提高程序员的调试效率, 更好更快地定位程序中的问题从而加快程序开发的进度, 是大家共同面对的问题. 可能Windows用户顺口就会说出:用VC呗 :-) , 它提 ...
- 算法图绘制工具Graphviz
graphviz是贝尔实验室设计的一个开源的画图工具,它的强大主要体现在“所思即所得"(WYTIWYG,what you think is what you get),这是和office的“ ...
- oracle 数据库中,应用程序里的连接探測语句的正确使用
oracle 数据库中,应用程序里的连接探測语句的正确使用 本文为原创文章.转载请注明出处:http://blog.csdn.net/msdnchina/article/details/3851376 ...
- gpio 灯的对应关系
1 点灯验证通过: GPIO160 TX1-LED GPIO161 RX1-LED GPIO163 TX2-LED GPIO164 RX2-LED GPIO ...
- Android——Activity中的六个主要函数
Android Activity中的六个主要函数 Android中一个Activity一般都需要实现六个函数: onCreate(), onStart(), onResume(),onPause(), ...
- linux用户空间和内核空间(内核高端内存)_转
转自:Linux用户空间与内核空间(理解高端内存) 参考: 1. 进程内核栈.用户栈 2. 解惑-Linux内核空间 3. linux kernel学习笔记-5 内存管理 Linux 操作系统和驱 ...
- 获取checkbox 组成字符串
<input type="checkbox" id="goods_server_name" name="goods_server_name[]& ...
- javascript 实现java中的Map
javascript实现java中的Map,代码是在国外的一个网站上看到的(http://stackoverflow.com/questions/368280/javascript-hashmap-e ...
- 001servlet的基本知识
servlet的知识: l 1. servlet概念及相关接口简介 l 2. servet 执行过程 l 3. servlet路径映射 l 4. 缺省servlet --应用 ...
- 【BZOJ】1607: [Usaco2008 Dec]Patting Heads 轻拍牛头(特殊的技巧)
http://www.lydsy.com/JudgeOnline/problem.php?id=1607 其实题目描述不清楚,应该是 别人拿的数能整除自己拿的数 数据范围很大,n<=100000 ...