Merge Two Sorted Lists 解答
Question
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Solution
The key to the solution here is to create a new linked list by creating a fake head.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l2 == null)
return l1;
if (l1 == null)
return l2;
ListNode fakeHead = new ListNode(0);
ListNode tmp = fakeHead;
ListNode p1 = l1, p2 = l2;
while (p1 != null && p2 != null) {
if (p1.val < p2.val) {
tmp.next = p1;
p1 = p1.next;
} else {
tmp.next = p2;
p2 = p2.next; }
tmp = tmp.next;
}
while (p1 != null) {
tmp.next = p1;
tmp = tmp.next;
p1 = p1.next;
}
while (p2 != null) {
tmp.next = p2;
tmp = tmp.next;
p2 = p2.next;
}
return fakeHead.next;
}
}
Merge Two Sorted Lists 解答的更多相关文章
- Merge k Sorted Lists 解答
Question Merge k sorted linked lists and return it as one sorted list. Analyze and describe its comp ...
- [LeetCode] Merge k Sorted Lists 合并k个有序链表
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这 ...
- LeetCode: Merge k Sorted Lists 解题报告
Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and descr ...
- [LeetCode] 23. Merge k Sorted Lists 合并k个有序链表
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. E ...
- leetCode练题——21. Merge Two Sorted Lists(照搬大神做法)
1.题目 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new l ...
- 刷题21. Merge Two Sorted Lists
一.题目说明 这个题目是21. Merge Two Sorted Lists,归并2个已排序的列表.难度是Easy! 二.我的解答 既然是简单的题目,应该一次搞定.确实1次就搞定了,但是性能太差: R ...
- 刷题23. Merge k Sorted Lists
一.题目说明 这个题目是23. Merge k Sorted Lists,归并k个有序列表生成一个列表.难度为Hard,实际上并不难,我一次提交就对了. 二.我的解答 就是k路归并,思路很简单,实现也 ...
- [LeetCode] Merge Two Sorted Lists 混合插入有序链表
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing t ...
- [LintCode] Merge Two Sorted Lists 混合插入有序链表
Merge two sorted (ascending) linked lists and return it as a new sorted list. The new sorted list sh ...
随机推荐
- Calculate Number Of Islands And Lakes 解答
Question 1 1 1 1 1 01 0 1 0 0 11 0 1 0 0 11 1 0 1 1 1 1 is earth, 0 is water. i) count the number of ...
- poj 3662 Telephone Lines(好题!!!二分搜索+dijkstra)
Description Farmer John wants to set up a telephone line at his farm. Unfortunately, the phone compa ...
- Unity Navigation面板了解
上次讲解了下Navigation的简单使用, 这次来看看Navigation面板的一些参数 NavigationStatic 勾选后表示该对象参与导航网格的烘培. OffMeshLink Genera ...
- pyqt columnView例子学习
# -*- coding: utf-8 -*- # python:2.x __author__ = 'Administrator' from PyQt4.QtGui import * from Py ...
- 二叉排序树的创建删除中序输出&&平衡树
#include<iostream> #include<cstdio> #include<cstring> #include<cmath> #inclu ...
- IOS上 关于状态栏的相关设置(UIStatusBar)
知识普及 ios上状态栏 就是指的最上面的20像素高的部分 状态栏分前后两部分,要分清这两个概念,后面会用到: 前景部分:就是指的显示电池.时间等部分: 背景部分:就是显示黑色或者图片的背景部分: 如 ...
- 该如何关闭thinkphp的缓存呢?有下面几种方法可参考:
该如何关闭thinkphp的缓存呢?有下面几种方法可参考: (1)在配置文件中关闭缓存 在你的配置文件config.php文件中加上如下两句: 复制代码代码如下: 'TMPL_CACHE_ON' ...
- Android应用切换皮肤功能实现(二)
原文地址http://www.apkbus.com/forum.php?mod=viewthread&tid=149034&highlight=%E7%9A%AE%E8%82%A4 上 ...
- nodejs之简介及安装(一)
@[nodejs|个人学习笔记] nodejs简介 什么是node.js Node.js 是一个基于 Chrome V8 引擎的 JavaScript 运行环境. 参考网站 一.nodejs.cn 二 ...
- openssl ans.1编码规则分析及证书密钥编码方式
1 数据编码格式 openssl的数据编码规则是基于ans.1的,ans.1是什么 ? 先上高大上的解释 ASN.1(Abstract Syntax Notation One), 是一种结构化的描述语 ...