[Wc2009]shortest
终于把这题过了,了了我两年前写堵塞的交通一晚上无果的心结
因为是6要注意蛇皮走位啊!!这种-> S
- //Achen
- #include<bits/stdc++.h>
- #define For(i,a,b) for(int i=(a);i<=(b);i++)
- #define Rep(i,a,b) for(int i=(a);i>=(b);i--)
- #define Formylove return 0
- const int N=1e5+;
- typedef long long LL;
- typedef double db;
- using namespace std;
- int n,q,a[][N],tpa[],mx;
- template<typename T> void read(T &x) {
- char ch=getchar(); T f=; x=;
- while(ch!='-'&&(ch<''||ch>'')) ch=getchar();
- if(ch=='-') f=-,ch=getchar();
- for(;ch>=''&&ch<='';ch=getchar()) x=x*+ch-''; x*=f;
- }
- #define inf 1e15
- LL dl[N<<][][],dr[N<<][][],dm[N<<][][];
- void copyit(int x,int y) {
- For(i,,) For(j,,) dl[y][i][j]=dl[x][i][j],dr[y][i][j]=dr[x][i][j],dm[y][i][j]=dm[x][i][j];
- }
- void upd(int y,int ll,int rr) {
- int x=mx+,lc=mx+,rc=mx+;
- copyit(ll,lc); copyit(rr,rc);
- For(i,,) For(j,,) For(k,,) {
- dm[lc][i][j]=min(dm[lc][i][j],dm[lc][i][k]+dl[rc][k][j]);
- dm[rc][i][j]=min(dm[rc][i][j],dm[rc][k][j]+dr[lc][k][i]);
- }
- For(i,,) For(j,,) {
- dm[x][i][j]=inf;
- For(k,,) dm[x][i][j]=min(dm[x][i][j],dm[lc][i][k]+dm[rc][k][j]);
- }
- For(i,,) For(j,,) {
- dl[x][i][j]=dl[lc][i][j];
- dr[x][i][j]=dr[rc][i][j];
- For(k,,) dl[x][i][j]=min(dl[x][i][j],dm[lc][i][k]+dm[lc][j][k]);
- For(k,,) dr[x][i][j]=min(dr[x][i][j],dm[rc][k][i]+dm[rc][k][j]);
- }
- copyit(x,y);
- }
- #define lc (x<<1)
- #define rc ((x<<1)|1)
- #define mid ((l+r)>>1)
- void updone(int x,int l) {
- For(i,,) tpa[i]=(i?tpa[i-]:)+a[i][l];
- For(i,,) For(j,,) {
- LL ds=i>j?(tpa[i]-(j?tpa[j-]:)):(tpa[j]-(i?tpa[i-]:));
- dl[x][i][j]=dr[x][i][j]=dm[x][i][j]=ds;
- }
- }
- void build(int x,int l,int r) {
- if(l==r) { updone(x,l); return ; }
- build(lc,l,mid); build(rc,mid+,r);
- upd(x,lc,rc);
- }
- void change(int x,int l,int r,int pos) {
- if(l==r) { updone(x,l); return; }
- if(pos<=mid) change(lc,l,mid,pos);
- else change(rc,mid+,r,pos);
- upd(x,lc,rc);
- }
- int fl;
- void qry(int x,int l,int r,int ql,int qr,int t) {
- if(ql>qr) return ;
- if(l>=ql&&r<=qr) {
- if(!fl) copyit(x,t),fl=;
- else upd(t,t,x); return ;
- }
- if(ql<=mid) qry(lc,l,mid,ql,qr,t);
- if(qr>mid) qry(rc,mid+,r,ql,qr,t);
- }
- int main() {
- //freopen("2104.in","r",stdin);
- //freopen("2104.out","w",stdout);
- read(n); mx=(n<<);
- For(i,,) For(j,,n) read(a[i][j]);
- build(,,n);
- read(q);
- For(i,,q) {
- int op,x,y,v,sx,sy,tx,ty;
- read(op);
- if(op==) {
- read(x); read(y); read(v);
- a[x-][y]=v; change(,,n,y);
- }
- else {
- read(sx); read(sy); sx--;
- read(tx); read(ty); tx--;
- if(sy>ty) swap(sx,tx),swap(sy,ty);
- fl=; qry(,,n,sy,ty,mx+);
- fl=; qry(,,n,,sy-,mx+);
- fl=; qry(,,n,ty+,n,mx+);
- LL ans=dm[mx+][sx][tx];
- if(sy!=) {
- For(j,,) For(k,,) dr[mx+][sx][j]=min(dr[mx+][sx][j],dl[mx+][sx][k]+dr[mx+][k][j]-dl[mx+][sx][sx]);
- For(k,,) ans=min(ans,dl[mx+][sx][sx]+dr[mx+][sx][k]+dm[mx+][k][tx]);
- }
- if(ty!=n) {
- For(j,,) For(k,,) dl[mx+][j][tx]=min(dl[mx+][j][tx],dr[mx+][k][tx]+dl[mx+][j][k]-dr[mx+][tx][tx]);
- For(k,,) ans=min(ans,dm[mx+][sx][k]+dl[mx+][k][tx]+dr[mx+][tx][tx]);
- }
- if(sy!=&&ty!=n) {
- For(k,,) For(l,,)
- ans=min(ans,dr[mx+][sx][k]+dm[mx+][k][l]+dl[mx+][l][tx]+dl[mx+][sx][sx]+dr[mx+][tx][tx]);
- }
- printf("%lld\n",ans);
- }
- }
- Formylove;
- }
[Wc2009]shortest的更多相关文章
- bzoj AC倒序
Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem ...
- [LeetCode] Encode String with Shortest Length 最短长度编码字符串
Given a non-empty string, encode the string such that its encoded length is the shortest. The encodi ...
- [LeetCode] Shortest Distance from All Buildings 建筑物的最短距离
You want to build a house on an empty land which reaches all buildings in the shortest amount of dis ...
- [LeetCode] Shortest Word Distance III 最短单词距离之三
This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as ...
- [LeetCode] Shortest Word Distance II 最短单词距离之二
This is a follow up of Shortest Word Distance. The only difference is now you are given the list of ...
- [LeetCode] Shortest Word Distance 最短单词距离
Given a list of words and two words word1 and word2, return the shortest distance between these two ...
- [LeetCode] Shortest Palindrome 最短回文串
Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. ...
- Leetcode: Encode String with Shortest Length && G面经
Given a non-empty string, encode the string such that its encoded length is the shortest. The encodi ...
- LeetCode 214 Shortest Palindrome
214-Shortest Palindrome Given a string S, you are allowed to convert it to a palindrome by adding ch ...
随机推荐
- Kattis - pseudoprime 【快速幂】
题意 给出两个数字 P 和 A 当p 不是素数 并且 满足a^p≡a(mod p) 就输出 yes 否则 输出 no 思路 因为 数据范围较大,用快速幂 AC代码 #include <cstdi ...
- iOS 快速遍历 效率分析 for loop for in enumerateBlock 适用条件
test1 简单遍历 结论: 当数组数据量很小 时候 for loop 和 for in 效率不相上下,随着数据量增长for in 快速枚举的优势 明显 如果需要知道 索引可用 enumrateBlo ...
- 机器学习算法之:KNN
基于实例的学习方法中,最近邻法和局部加权回归法用于逼近实值或离散目标函数,基于案例的推理已经被应用到很多任务中,比如,在咨询台上存储和复用过去的经验:根据以前的法律案件进行推理:通过复用以前求解的问题 ...
- 【HackerRank】Bus Station
有n组好朋友在公交车站前排队.第i组有ai个人.还有一辆公交车在路线上行驶.公交车的容量大小为x,即它可以同时运载x个人. 当车站来车时(车总是空载过来),一些组从会队头开始走向公交车. 当然,同一组 ...
- 【HackerRank】Gem Stones
Gem Stones John has discovered various rocks. Each rock is composed of various elements, and each el ...
- iMX6 yocto平台QT交叉编译环境搭建
转:https://blog.csdn.net/morixinguan/article/details/79351909 . /opt/fsl-imx-fb/4.9.11-1.0.0/environm ...
- python:格式化输出 str.format()
官网说明:https://docs.python.org/2/library/string.html#formatstrings python的格式输出有两种方法: 1.“ %s”.(variant) ...
- C#多线程学习之Thread
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.T ...
- POI实现数据的导入
1.POI技术的概述? POI技术:apache POI是可以对微软office文档进行读和写的工具. l HSSF:操作97格式的excel,扩展名:.xls 纯二进制,最大行数65535. l X ...
- 使用shell自动备份数据库
全备份 #!/bin/sh #mysql地址 #检测用户是否手动输入了密码 mysql_host="" #mysql用户 mysql_user="" #mysq ...