C语言 cgi(2)
1
Columbia University
cs3157 – Advanced Programming
Summer 2014, Lab #3, 40 points
June 10, 2014
This lab is due June 23rd 11:59 pm.
• lab in C. We will be using Makefiles.
• Don’t forget to FREE up any memory you request!!
• Make sure you complete the relevant reading on pointers.
• This is a long lab, please start early. Please also work on the homework project concurrently.
• Please make sure to run the debugger when you run into issues.
• Some code was developed in class, please indicate in the README etc
Step 1 - Puzzles (35 points)
In this step, you will develop code that computes a magic square. A magic square is a n× nmatrix filled
with integers in the range [1 – n2] so that each entry in the matrix has a unique value. The sum of each of
the rows and each of the columns and each of the two diagonals must be equal the same number. The
number is known as the magic constant Example for n=3 the magic
constant is 15, for n=4 it will be 34 etc. Also Note that there not a single unique solution to the magic
square problem.
think of Typedef as a shortcut so instead of having to type out a full type you can use the shortcut. For
example
typedef int XX[15];
XX yyy;
will make yyy a shortcut for a 15 array int. So can say yyy[0] etc
Create a file called Maintest1.c/Magicsquare1.c/Magicsquare.h and (to help you get started) start by
putting the following code/declarations in each file (where appropriate):
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define MAGICSIZE 3
typedef int MSQUARE_TYPE[MAGICSIZE][ MAGICSIZE];
typedef MSQUARE_TYPE * MagSquare_PTR;
void initSquare( MagSquare_PTR, int magicsquaresize );
void printSquare( MagSquare_PTR, int magicsquaresize );
2
int main() {
srand( time( NULL )); /* seed the random number gen */
MagSquare_PTR mptr = /* replace with something with malloc to create
space to point at*/;
initSquare( mptr, MAGICSIZE );
printSquare( mptr , MAGICSIZE);
} // end of main()
Define the function initSquare(MagSquare_PTR, int size) which takes the magic square pointer
argument (as above) and the size of the n by n array and fills it with values in the range [1 - 9]. These
values must be assigned RANDOMLY, but make sure that no number appears more than once in the
array.
Also Define the function printSquare(MagSquare_PTR, int size) which takes the magic square
pointer argument (as above) and the n for the n by n size, and prints out its contents to the screen in a nice
n rows by n columns format.
You should test your code with just these 2 functions to make sure each is working (before adding the rest
of the functions).
Hint: To get random numbers look up lookup rand() and srand() from the stdlib libary.
1. maintest1.c – this will contain the main function
2. magicsquare.h – this will contain the functions declarations that you will be using.
3. magicsquare.c – this will contain the function definitions from above including the following
methods:
a. void initSquare(MagSquare_PTR, int)
(see above)
b. void printSquare(MagSquare_PTR, int)
(see above)
c. int sumColumn( int column, MagSquare_PTR, int size )
The function takes the 2-dimensional magic square array and a column number and returns
the sum of the 3 values in that column
d. int sumRow(int row, MagSquare_PTR, int size)
see above.
e. int sumDiagonal( int diagonal, MagSquare_PTR, int size )
The function takes the 2-dimensional magic square array and a diagonal number and
returns the sum of the n values in that diagonal. Use diagonal = 0 to refer to the diagonal
that runs from the northwest corner down to the southeast corner. Use diagonal = 1 to refer
to the diagonal that runs from the northeast corner down to the southwest corner.
f. Create a function called int isMagic(MagSquare_PTR, int size) which takes the
magic square pointer as an argument and checks each of the rows and columns and
diagonals to see if all the sums equal 15. The function should return 0 if the argument is
not a magic square and 1 if it is a magic square.
3
g. Modify the above main() so that it calls isMagic and prints out whether the square is a
magic square or not.
h. Modify the main() program so that after it prints out the square, it computes (using the
functions above) and prints out the sum of each of the 3 rows and each of the 3 columns
and each of the 2 diagonals.
Compile and test your program.
Here's a sample output:
the square is not a magic square of size 3
here is your square:
2 8 3
1 4 5
7 9 6
sum of row 1 = 13
sum of row 2 = 10
sum of row 3 = 22
sum of column 1 = 10
sum of column 2 = 21
sum of column 3 = 14
sum of diagonal 0 = 12
sum of diagonal 1 = 14
Note: you will need to create a makefile for this lab too. For example
make step1_run
would compile and execute the step1 code.
Hint: here is a sample of a more complicated Makefile:
CC = gcc
CCFLAGS = -Wall –lm
step1_run: maintest1.c magicsquare1.o
$(CC) $(CCFLAGS) -o test1 maintest1.c magicsquare1.o
./test1
magicsquare1.o: magicsquare1.c magicsquare1.h
$(CC) $(CCFLAGS) –c magicsquare1.c
clean:
rm –f *.o test1
(make clean
will just clean up all the temp .o files and executables, should run it before submission, if you used emacs,
you should probably include *~ also).
4
Step 2 create a running program (20 points)
Now copy maintest1.c to maintest2.c and magicsquare1.c to magicsquare2.c, and magicsquare1.h to
magicsquare1.h modify them as follows:
1. Create a function called permuteSquare(MagSquare_PTR) which takes the magic square
pointer as an argument and randomly switches two entries in the array. Do this by randomly
picking two sets of row and column indices (in the range [0 - 2]) and then swapping the entries
located at each pair of indices. Check to make sure you aren’t picking the same spot .. that is
swapping the same location with itself J
2. Modify the main() so that after it calls isMagic(), if the square is not magic, then it calls
permuteSquare() to switch around two entries in the square and then test again to see if the
square is magic. Do this repeatedly until a magic square is found. When a magic square is found,
call printSquare() again to print out the magic square.
3. Have the program count the number of times it has to permute the square in order to find a magic
square. Print that out too (Hint: count it where you call method permutesquare).
Compile and test your code. Please ask for help as you need etc
Good luck.
C语言 cgi(2)的更多相关文章
- 搭建简易的c语言与python语言CGI和Apache服务器的开发环境
搭建简易的c语言CGI和Apache服务器的开发环境 http://www.cnblogs.com/tt-0411/archive/2011/11/21/2257203.html python配置ap ...
- 基于windows IIS的C语言CGI WEB服务器环境搭建
网页编程对我来说特别亲切,因为我就是从html.ASP.PHP一步步接触编程的.自己的编程爱好也是从那里一点一点被满足.不过离开大学之后很久没有碰过WEB了,最近看到嵌入式中的涉及到的web服务器,了 ...
- C语言 cgi(3)
1cs3157 – Advanced ProgrammingSummer 2014, Project 1, 150 pointsJune 17, 2014Follow these step-by-st ...
- C语言cgi(1)
1Columbia Universitycs3157 – Advanced ProgrammingSummer 2014, Lab #2, 60ish pointsJune 9, 2014Follow ...
- c语言cgi笔记
直接输出接收的数据 #include <stdio.h>#include <stdlib.h>main(){int i,n;printf ("Content-type ...
- 几种语言的CGI编程
为了了解PHP.JSP.ASP出现之前人们写网站的方法,洒家研究了一波CGI,使用C.Python.batch.shell script语言写了几个简单的网页. CGI即通用网关接口,指web服务器调 ...
- CGI(通用网关接口)
公共网关接口 CGI(Common Gateway Interface) 是WWW技术中最重要的技术之一,有着不可替代的重要地位.CGI是外部应用程序(CGI程序)与Web服务器之间的接口标准,是在C ...
- cgic 写CGI程序
CGIC是C语言CGI库函数,用于编写CGI程序 CGIC 主要完成以下功能: * 对数据进行语法分析 * 接收以 GET 和 PSOT 两种方式发送的数据 * 把 FORM 中的不同域连接成连续的串 ...
- libctemplate——C语言模块引擎简介及使用
前言 由先声明此libctemplate不是Google那个ctemplate.这个库是用C语言实现的,只有一个实现文件和一个头文件.Gooogl的ctemplate是C++实现的,和线程还扯上了关系 ...
随机推荐
- [读书笔记]设计原本[The Design of Design]
第1章 设计之命题 1.设计首先诞生于脑海里,再慢慢逐步成形(实现) 2.好的设计具有概念完整性:统一.经济.清晰.优雅.利落.漂亮... 第2章 工程师怎样进行设计思维——理性模型 1.有序模型的有 ...
- C++中的常对象和常对象成员
常对象 常对象必须在定义对象时就指定对象为常对象. 常对象中的数据成员为常变量且必须要有初始值,如 Time const t1(12,34,36); //定义t1为常对象 这样的话,在所有的场合中,对 ...
- Spring Security Source Code -- 验证标准流程
除了初始阶段: 主干验证流程链: MyInvocationSecurityMetadataSource.getAttributes(Object) line: 43 MyFilterSecur ...
- lua 函数回调技巧
技巧1: local a = {}; function b() print("Hello World") end a["sell"] = {callFunc = ...
- 九度OJ 1179 阶乘(模拟)
题目1179:阶乘 时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:4526 解决:1315 题目描写叙述: 输入n, 求y1=1!+3!+...m!(m是小于等于n的最大奇数) y2=2! ...
- 生产者、消费者 C源码,gcc编译通过
/*生产者.消费者*/ #include<stdio.h> #include<pthread.h> #define BUFFER_SIZE 16 /***struct prod ...
- HDU 1007 近期点对
分治法求近期点对 递归将点不断分成小组.计算最短距离.此时的最短距离不过两点都属两块的某一块(这里的切割点是mid点). 还须要考虑两点分属两块的情况. 这时对于选点则把范围缩小到了以mid为中心. ...
- sql plus 抢救数据(測)
有索引 --运行plsql脚本 DECLARE TYPE RowIDTab ISTABLE OF ROWID INDEXBY BINARY_INTEGER; CURSORc1 IS selec ...
- sql连接错误(Microsoft SQL Server,错误:2)
昨天用SQL语句建表的时候写了一段代码,对于代码的逻辑和内容我不太肯定对不正确.反正是毫不犹豫的让它运行了,过程中出现好几个错误,当时没有太在意,想着大不了出错了再重写一个.结果--玩坏了,从昨天到如 ...
- Hibernate学习之createSQLQuery与createQuery的区别及使用
hibernate中createQuery与createSQLQuery:前者用的hql语句进行查询,后者可以用sql语句查询,前者以hibernate生成的Bean为对象装入list返回,后者则是以 ...