sdut 2413:n a^o7 !(第三届山东省省赛原题,水题,字符串处理)
n a^o7 !
Time Limit: 1000MS Memory limit: 65536K
题目描述
All brave and intelligent fighters, next you will step into a distinctive battleground which is full of sweet and happiness. If you want to win the battle, you must do warm-up according to my instructions, which can make you in the best state preparing to fight. Now please relax yourself and enjoy the good moment. Before you raise your sharp sword to the enemy who guards the battleground, please allow me to tell you a true and romantic story about a samurai like you.
Samurai hh fell in love with girl ss, who is charming and demure. He realized the truth that he must spend his remaining life with ss, and resolved to pursue the hard-won affection. One day hh wrote a letter to ss, when she opens the letter with excitement her mind was in tangle. She found herself completely not to figure out the meaning about the letter, which said that "n 55!w ! pue n a^o7 ! n paau !". ss also immersed herself in guessing the meaning of that letter for a long time because of her adore to hh. Finally she called hh to ask the meaning of the letter. On the other side of the phone, hh was too nervous to say. Gradually he calmed down himself and told ss to reverse the letter and read it. Then on both ends of the phone comes the voice at the same time "i need u i love u and i miss u".
ss wants to tell each of you however you are Brave And Skilled, you shouldn't forget to express your loyal love and romantic feelings to your prince or princess.
Now the horn sounds for battle,do it by the following input and output. I think each of you will get an "Accepted" in this battle with pleasant mood.
输入
Input contains an integer T in the first line, and then T lines follow .Each line contains a message (only contain 'n5!wpuea^o7!' and
' '(space)), the message's length is no more than 100.
输出
Output the case number and the message. (As shown in the sample output)
示例输入
2
n 55!w ! pue n a^o7 ! n paau !
n5!wpuea^o7
示例输出
Case 1: i need u i love u and i miss u
Case 2: loveandmisu
提示
来源
#include <iostream>
#include <stdio.h>
#include <string.h>
using namespace std;
void work(char a[])
{
int i;
for(i=;a[i];i++){
switch(a[i]){
case 'n':a[i]='u';break;
case '':a[i]='s';break;
case 'w':a[i]='m';break;
case 'p':a[i]='d';break;
case 'u':a[i]='n';break;
case 'e':a[i]='a';break;
case 'a':a[i]='e';break;
case '^':a[i]='v';break;
case 'o':a[i]='o';break;
case '':a[i]='l';break;
case '!':a[i]='i';break;
default:break;
}
}
}
int main()
{
int n,cnt = ;
cin>>n;
getchar();
while(n--){
char a[];
cin.getline(a,,'\n');
work(a);
cout<<"Case "<<cnt++<<": ";
int len = strlen(a)-;
for(;len>=;len--)
cout<<a[len];
cout<<endl;
}
return ;
} /**************************************
Problem id : SDUT OJ D
User name : Miracle
Result : Accepted
Take Memory : 472K
Take Time : 0MS
Submit Time : 2014-04-27 09:16:04
**************************************/
Freecode : www.cnblogs.com/yym2013
sdut 2413:n a^o7 !(第三届山东省省赛原题,水题,字符串处理)的更多相关文章
- sdut 2411:Pixel density(第三届山东省省赛原题,字符串处理)
Pixel density Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 Pixels per inch (PPI) or pi ...
- sdut 2163:Identifiers(第二届山东省省赛原题,水题)
Identifiers Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 Identifier is an important c ...
- sdut 2154:Shopping(第一届山东省省赛原题,水题)
Shopping Time Limit: 1000MS Memory limit: 65536K 题目描述 Saya and Kudo go shopping together.You can ass ...
- sdut 2416:Fruit Ninja II(第三届山东省省赛原题,数学题)
Fruit Ninja II Time Limit: 5000MS Memory limit: 65536K 题目描述 Have you ever played a popular game name ...
- sdut 2610:Boring Counting(第四届山东省省赛原题,划分树 + 二分)
Boring Counting Time Limit: 3000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 In this problem you a ...
- sdut 2153:Clockwise(第一届山东省省赛原题,计算几何+DP)
Clockwise Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 Saya have a long necklace with ...
- sdut 2152:Balloons(第一届山东省省赛原题,DFS搜索)
Balloons Time Limit: 1000MS Memory limit: 65536K 题目描述 Both Saya and Kudo like balloons. One day, the ...
- sdut 2603:Rescue The Princess(第四届山东省省赛原题,计算几何,向量旋转 + 向量交点)
Rescue The Princess Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 Several days ago, a b ...
- sdut 2162:The Android University ACM Team Selection Contest(第二届山东省省赛原题,模拟题)
The Android University ACM Team Selection Contest Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里 ...
随机推荐
- tp auth 转载保存
PS:最近需要做一个验证用户权限的功能,在官方和百度看了下,发现大家都是用auth来做验证,官方有很多auth的使用教程,但是都不全面,我也提问了几个关于auth的问题 也没人来回答我,无奈只好一步步 ...
- 通用跨站脚本攻击(UXSS)
有同学问,用百度搜索了下,发现国内相关介绍基本是没有,就写篇文章来介绍下.不过看到有现成的介绍,就拿来翻译修改下.本文的内容主要翻译来自该文章,把一些没必要的话给删了,做了一些整理修改,然后补充一些案 ...
- DOS中如何删除文件夹
可以使用rd命令.如果目录是空的,那么可以用 rd 目录删除目录.如下图:输入Y之后系统就会删除整个目录. 如果目录是非空,那么使用rd 目录 /s来删除目录(目录下的文件也会删除一同).如果没有加/ ...
- 2013 ACM/ICPC Asia Regional Chengdu Online 1004 Minimum palindrome
Minimum palindrome Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Other ...
- Internet信息服务找不到
最近我的电脑也出现了Internet信息服务找不到的情况,在网络上查了很多方法都没一个正确的,后面通过下面的方法我成功了,故此我把这个经历也分享给大家,希望能够帮到您. 控制面板里“->添加/删 ...
- error LNK2038: 检测到“_ITERATOR_DEBUG_LEVEL”的不匹配项:值“0”不匹配值“2”
error: vtkCommon.lib(vtkSmartPointerBase.obj) : error LNK2038: 检测到“_ITERATOR_DEBUG_LEVEL”的不匹配项:值“0”不 ...
- 技术分享:WIFI钓鱼的入门姿势
简介 该实验先是搭建一个测试环境,然后创建一个假的无线接入点,把网络连接连接到假的接入点并且强迫用户连接假的无线点. 事先准备 1.无线网卡:无线网卡用于数据包的嗅探和注入. 2. Backtrack ...
- POJ 1456 Supermarket 区间问题并查集||贪心
F - Supermarket Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Sub ...
- 坚持不懈之linux haproxy的配置文件关键字查询手册
1.关键词balance balance用于定义负载均衡的算法,可用于defaults.listen和backend中. balance使用方法如下: balance <algorithm> ...
- map遍历
Set<Map.Entry<String,String>> ss = params.entrySet(); for(Map.Entry<String,String> ...