《算法》第四章部分程序 part 9

▶ 书中第四章部分程序，包括在加上自己补充的代码，两种拓扑排序的方法

● 拓扑排序 1

 package package01;
 
 import edu.princeton.cs.algs4.Digraph;
 import edu.princeton.cs.algs4.SymbolDigraph;
 import edu.princeton.cs.algs4.DirectedCycle;
 import edu.princeton.cs.algs4.DepthFirstOrder;
 import edu.princeton.cs.algs4.EdgeWeightedDigraph;
 import edu.princeton.cs.algs4.EdgeWeightedDirectedCycle;
 
 public class class01
 {
     private Iterable<Integer> order;    // 拓扑排序的结果
     private int[] rank;                 // 顶点 v 在拓扑排序中的序号为 rank[v]
 
     public class01(Digraph G)           // 从有向图生成拓扑排序
     {
         DirectedCycle finder = new DirectedCycle(G);        // 存在环则不能排序
         if (!finder.hasCycle())
         {
             DepthFirstOrder dfs = new DepthFirstOrder(G);   // 做 G 的深度优先搜索
             order = dfs.reversePost();                      // 取逆后序依次标号
             rank = new int[G.V()];
             int i = 0;
             for (int v : order)
                 rank[v] = i++;
         }
     }
 
     public class01(EdgeWeightedDigraph G)                   // 从加权边有向图生成拓扑排序（算法一样，只是数据结构不同）
     {
         EdgeWeightedDirectedCycle finder = new EdgeWeightedDirectedCycle(G);
         if (!finder.hasCycle())
         {
             DepthFirstOrder dfs = new DepthFirstOrder(G);
             order = dfs.reversePost();
             rank = new int[G.V()];
             int i = 0;
             for (int v : order)
                 rank[v] = i++;
         }
     }
 
     public Iterable<Integer> order()
     {
         return order;
     }
 
     public boolean hasOrder()
     {
         return order != null;
     }
 
     public int rank(int v)
     {
         return hasOrder() ? rank[v] : -1;
     }
 
     public static void main(String[] args)
     {
         String filename = args[0];
         String delimiter = args[1];                                 // 分隔符
         SymbolDigraph sg = new SymbolDigraph(filename, delimiter);
         class01 topological = new class01(sg.digraph());
         for (int v : topological.order())
             System.out.println(sg.nameOf(v));
     }
 }

● 拓扑排序 2

 package package01;
 
 import edu.princeton.cs.algs4.StdOut;
 import edu.princeton.cs.algs4.StdRandom;
 import edu.princeton.cs.algs4.DigraphGenerator;
 import edu.princeton.cs.algs4.Digraph;
 import edu.princeton.cs.algs4.Queue;
 import edu.princeton.cs.algs4.DirectedEdge;
 import edu.princeton.cs.algs4.EdgeWeightedDigraph;
 
 public class class01
 {
     private Queue<Integer> order;
     private int[] rank;
 
     public class01(Digraph G)
     {
         order = new Queue<Integer>();
         rank = new int[G.V()];
         int[] indegree = new int[G.V()];
         for (int v = 0; v < G.V(); v++)
             indegree[v] = G.indegree(v);
         int count = 0;
         Queue<Integer> queue = new Queue<Integer>();
         for (int v = 0; v < G.V(); v++)                 // 收集所有没有前提条件的顶点
         {
             if (indegree[v] == 0)
                 queue.enqueue(v);
         }
         for (; !queue.isEmpty();)
         {
             int v = queue.dequeue();
             order.enqueue(v);                           // 事件 v 完成，将其放入输出队列， 并给一个序号
             rank[v] = count++;
             for (int w : G.adj(v))                      // 所有紧接着 v 的事件的前提条件减少 1
             {
                 indegree[w]--;
                 if (indegree[w] == 0)                   // 收集此时没有前提条件的事件
                     queue.enqueue(w);
             }
         }
         if (count != G.V())                             // 遍历结束，还有顶点有入度，说明存在环
             order = null;
     }
 
     public class01(EdgeWeightedDigraph G)
     {
         order = new Queue<Integer>();
         rank = new int[G.V()];
         int[] indegree = new int[G.V()];
         for (int v = 0; v < G.V(); v++)
             indegree[v] = G.indegree(v);
         int count = 0;
         Queue<Integer> queue = new Queue<Integer>();
         for (int v = 0; v < G.V(); v++)
         {
             if (indegree[v] == 0)
                 queue.enqueue(v);
         }
         for (; !queue.isEmpty();)
         {
             int v = queue.dequeue();
             order.enqueue(v);
             rank[v] = count++;
             for (DirectedEdge e : G.adj(v))
             {
                 int w = e.to();
                 indegree[w]--;
                 if (indegree[w] == 0)
                     queue.enqueue(w);
             }
         }
         if (count != G.V())
             order = null;
     }
 
     public Iterable<Integer> order()
     {
         return order;
     }
 
     public boolean hasOrder()
     {
         return order != null;
     }
 
     public int rank(int v)
     {
         return hasOrder() ? rank[v] : -1;
     }
 
     public static void main(String[] args)
     {
         int V = Integer.parseInt(args[0]);                  // 生成DAG G(V,E)，再添加 F 条边
         int E = Integer.parseInt(args[1]);
         int F = Integer.parseInt(args[2]);
         Digraph G1 = DigraphGenerator.dag(V, E);            // G1 是无边圈的
         EdgeWeightedDigraph G2 = new EdgeWeightedDigraph(V);// G2 有边权的
         for (int v = 0; v < G1.V(); v++)
         {
             for (int w : G1.adj(v))
                 G2.addEdge(new DirectedEdge(v, w, 0.0));
         }
         for (int i = 0; i < F; i++)
         {
             int v = StdRandom.uniform(V);
             int w = StdRandom.uniform(V);
             G1.addEdge(v, w);
             G2.addEdge(new DirectedEdge(v, w, 0.0));
         }
         StdOut.println(G1);
         StdOut.println();
         StdOut.println(G2);
         class01 topological1 = new class01(G1);             // 分别计算 G1 和 G2 的
         if (!topological1.hasOrder())
             StdOut.println("Not a DAG");
         else
         {
             StdOut.print("Topological order: ");
             for (int v : topological1.order())
                 StdOut.print(v + " ");
             StdOut.println();
         }
         class01 topological2 = new class01(G2);
         if (!topological2.hasOrder())
             StdOut.println("Not a DAG");
         else
         {
             StdOut.print("Topological order: ");
             for (int v : topological2.order())
                 StdOut.print(v + " ");
             StdOut.println();
         }
     }
 }