题目描述

Bessie has wandered off the farm into the adjoining farmer's land. He raises delicious papaya fruit, which is a delicacy for cows. The papaya jungle is partitioned into a grid of squares with R rows and C columns (1 <= R <= 40, 1 <= C <= 40), as is popular in Wisconsin. Bessie can travel from a given square to any existing adjacent square whose route is parallel to the X or Y axis. So in the

following diagram, if Bessie is at the square labeled 'B', she can travel to any of the squares labeled 'T':

.T. TBT .T. Bessie always starts out by munching the papayas in square

(row=1,col=1). After she's done with one square, Bessie always uses her trusty binoculars to count the low-hanging fruit in each of the adjacent squares. She then always moves to the square with the most visible uneaten fruit (a square that happily is always unique).

Sooner or later, following this rule, Bessie always ends up in square (R,C) and eats the fruit there.

Given the dimensions of the papaya jungle and the amount of fruit F_ij in each square (1 <= F_ij <= 100), determine the total number of fruit Bessie consumes for a given papaya jungle.

POINTS: 80

Bessie不小心游荡出Farmer John的田地,而走进了相邻的农民的地里。她举起一个木瓜,木瓜对奶牛来说可是不可多得得美味。这个木瓜林像一般的威斯康星州的田地一样被分割成一个R行C列的网格(1 <= R <= 40, 1 <= C <= 40)。Bessie可以从一个格沿着一条跟X轴或Y轴平行的直线走到邻接的另一个格。Bessie发现一开始她自己在木瓜林的(1,1),也就是第一行第一列慢悠悠地咀嚼着木瓜。

Bessie总是用她最信赖地双筒望远镜去数每一个邻接的格里挂着的木瓜的数目。然后她就游荡到那个有最多没有被吃掉的木瓜的邻接的格子(保证这样的格子只有一个)。

按照这种移动方法,最终Bessie总是会在(R,C)停止然后吃掉那里的木瓜。

给定这个木瓜林的大小及每个格的木瓜数F_ij(1 <= F_ij <= 100), 要求Bessie一共吃了多少个木瓜。

输入输出格式

输入格式:

  • Line 1: Two space-separated integers: R and C

  • Lines 2..R+1: Line i+1 describes row i of the jungle with C

space-separated integers that tell how many fruit are in each square: F_i1, F_i2, ..., F_iC

输出格式:

  • Line 1: A single integer that is the total number of papayas that Bessie eats by the time she finishes off the papayas at the barn in the lower right corner at coordinate (R,C).

输入输出样例

输入样例#1: 复制

3 4
3 3 4 5
4 5 3 2
1 7 4 2
输出样例#1: 复制

39

说明

Three rows; four columns. Bessie starts in upper left corner at the '3'.

Bessie eats the papayas in the order given by the letters next to the numbers below:

(1,1) ---> (1,C)

(1,1) 3a 3 4g 5h (1,C)

| 4b 5c 3f 2i |

(R,1) 1 7d 4e 2j (R,C)

(R,1) ---> (R,C)

She declines to eat 4 of the papayas but consumes 39 (visiting all but two squares of the grid).

思路:模拟。

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
int n,m,ans;
int map[][],vis[][];
void dfs(int x,int y){
ans+=map[x][y];
map[x][y]=;
if(x==n&&y==m){
cout<<ans;
exit();
}
int dx=map[x-][y];
int dy=map[x+][y];
int dz=map[x][y+];
int dc=map[x][y-];
if(dx>dy&&dx>dz&&dx>dc) dfs(x-,y);
if(dy>dx&&dy>dz&&dy>dc) dfs(x+,y);
if(dz>dy&&dz>dx&&dz>dc) dfs(x,y+);
if(dc>dy&&dc>dz&&dc>dx) dfs(x,y-);
}
int main(){
scanf("%d%d",&n,&m);
for(int i=;i<=n;i++)
for(int j=;j<=m;j++)
scanf("%d",&map[i][j]);
dfs(,);
return ;
}

洛谷 P2958 [USACO09OCT]木瓜的丛林Papaya Jungle的更多相关文章

  1. 洛谷——P2958 [USACO09OCT]木瓜的丛林Papaya Jungle

    P2958 [USACO09OCT]木瓜的丛林Papaya Jungle 题目描述 Bessie has wandered off the farm into the adjoining farmer ...

  2. 洛谷 P2376 [USACO09OCT]津贴Allowance 解题报告

    P2376 [USACO09OCT]津贴Allowance 题目描述 作为创造产奶纪录的回报,\(Farmer\) \(John\)决定开始每个星期给\(Bessie\)一点零花钱. \(FJ\)有一 ...

  3. 洛谷—— P1339 [USACO09OCT]热浪Heat Wave

    P1339 [USACO09OCT]热浪Heat Wave 题目描述 The good folks in Texas are having a heatwave this summer. Their ...

  4. 洛谷 P2959 [USACO09OCT]悠闲漫步The Leisurely Stroll

    P2959 [USACO09OCT]悠闲漫步The Leisurely Stroll 题目描述 Bessie looks out the barn door at the beautiful spri ...

  5. 洛谷 P2960 [USACO09OCT]Milkweed的入侵Invasion of the Milkweed

    P2960 [USACO09OCT]Milkweed的入侵Invasion of the Milkweed 题目描述 Farmer John has always done his best to k ...

  6. 洛谷P1339 [USACO09OCT]热浪Heat Wave 题解

    题目传送门 这道题实际非常简单好奇是怎么变黄的... 其实也就是一个SPFA,本人非常懒,不想打邻接表,直接用矩阵就好啦... #include<bits/stdc++.h> using ...

  7. 洛谷 P2639 [USACO09OCT]Bessie的体重问题Bessie's We… 题解

    题目传送门 这也是个01背包,只是装的很... #include<bits/stdc++.h> #define MAXN 45010 using namespace std; int f[ ...

  8. 洛谷 2957 [USACO09OCT]谷仓里的回声Barn Echoes

    题目描述 The cows enjoy mooing at the barn because their moos echo back, although sometimes not complete ...

  9. 洛谷——2639[USACO09OCT]Bessie的体重问题Bessie's We…——01

    题目描述 Bessie像她的诸多姊妹一样,因为从Farmer John的草地吃了太多美味的草而长出了太多的赘肉.所以FJ将她置于一个及其严格的节食计划之中.她每天不能吃多过H (5 <= H & ...

随机推荐

  1. Mooc--五子棋(js)小结

    1. canvas是块级元素吗?? 2. css3 box-shadow属性 语法:box-shadow: h-shadow v-shadow blur spread color inset; 注释: ...

  2. NOIP2013 货车运输 倍增

    问题描述 A 国有 n 座城市,编号从 1 到 n,城市之间有 m 条双向道路.每一条道路对车辆都有重量限制,简称限重.现在有 q 辆货车在运输货物,司机们想知道每辆车在不超过车辆限重的情况下,最多能 ...

  3. django-debug-toolbar 使用

    https://pypi.org/project/django-debug-toolbar/ https://django-debug-toolbar.readthedocs.io/en/latest ...

  4. 题解 P2068 【统计和】

    这是一道单点修改,区间查询的线段树. 需要实现的操作有三个:建树,更新与查询. 首先,线段树用结构体维护,如下: struct node { int l, r; int val; } tree[max ...

  5. mysql查询今天,昨天,近7天,近30天,本月,上一月数据

    近期项目中用到了查询当月数据记录的功能,最初的想法是在逻辑业务里构造好时间段进行查询,当写sql语句时感觉挺麻烦.所以就到网上搜索了一下,看看是不是能有简单的方法.果然.网络资源非常强大.以下结合我的 ...

  6. PHP经常使用功能

    1)字符串 主要方法有:strops().substr().str_split().explode()等.很多其它方法查看PHP官方手冊. <?php /** * 字符串的方法:strpos() ...

  7. nginx和apache

    apache所占用的内存资源较多,并且处理较慢 apache的全部模块都支持动静态编译 apache对Fcgi的支持不好 apache不支持epoll apache相对于nginx是一个庞然大物 ng ...

  8. vue29-vue2.0组件通信_recv

    <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...

  9. BZOJ 3781 莫队

    思路:不能再裸的裸题-- //By SiriusRen #include <cmath> #include <cstdio> #include <algorithm> ...

  10. SQL try catch处理

    ALTER PROC usp_AccountTransaction @AccountNum INT, @Amount DECIMAL AS BEGIN BEGIN TRY --Start the Tr ...