hdoj--1051--Wooden Sticks(LIS)
Wooden Sticks
prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.
You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is
a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).
sticks in the test case, and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one
or more spaces.
3
5
4 9 5 2 2 1 3 5 1 4
3
2 2 1 1 2 2
3
1 3 2 2 3 1
2
1
3
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<iostream>
#include<algorithm>
using namespace std;
struct node
{
int l,w;
}s[10010];
int dp[10010];
int cmp(node s1,node s2)
{
if(s1.l<s2.l)
return 1;
else if(s1.l==s2.l)
return s1.w<s2.w;
return 0;
}
int main()
{
int t;
cin>>t;
while(t--)
{
int n;
cin>>n;
memset(dp,0,sizeof(dp));
for(int i=0;i<n;i++)
scanf("%d%d",&s[i].l,&s[i].w),dp[i]=1;
sort(s,s+n,cmp);
int maxx=0;
for(int i=0;i<n;i++)
{
for(int j=0;j<i;j++)
{
if(s[i].w<s[j].w&&dp[i]<dp[j]+1)
dp[i]=dp[j]+1;
}
maxx=max(maxx,dp[i]);
}
printf("%d\n",maxx);
}
return 0;
}
hdoj--1051--Wooden Sticks(LIS)的更多相关文章
- HDOJ.1051 Wooden Sticks (贪心)
Wooden Sticks 点我挑战题目 题意分析 给出T组数据,每组数据有n对数,分别代表每个木棍的长度l和重量w.第一个木棍加工需要1min的准备准备时间,对于刚刚经加工过的木棍,如果接下来的木棍 ...
- HDOJ 1051. Wooden Sticks 贪心 结构体排序
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) To ...
- HDOJ 1051. Wooden Sticks
题目 There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The ...
- HDU 1051 Wooden Sticks (贪心)
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) To ...
- 1051 Wooden Sticks
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- HDU 1051 Wooden Sticks 贪心||DP
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- HDU - 1051 Wooden Sticks 贪心 动态规划
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- hdu 1051:Wooden Sticks(水题,贪心)
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- 杭电 1051 Wooden Sticks
Description There is a pile of n wooden sticks. The length and weight of each stick are known in adv ...
- HDU 1051 Wooden Sticks【LIS】
题意:给出n个木头的重量wi,长度li,如果满足w[i+1]>=w[i]且l[i+1]>=l[i],则不用耗费另外的加工时间,问至少需要多长时间加工完这些木头. 第一次做这一题目也没有做出 ...
随机推荐
- html/css常用合集
1. 消除inline-block元素间的换行间隙问题: {font-size:0;} 兼容IE6/7浏览器的方法:letter-spacing属性. 2.让两个inline-block的div顶 ...
- A - I Wanna Be the Guy
Problem description There is a game called "I Wanna Be the Guy", consisting of n levels. L ...
- 查找DLL,并复制出来
Subst b: %windir%\assembly 执行完后,会发现硬盘分区多了个B盘,打开后看到了所有assembly下的DLL,于是在这里就搜到了Microsoft.ReportViewer.P ...
- chrome打开控制台状态下,没有人为打断点,自动进入断点模式的解决方法
如下图所示:在控制台去掉Sources -> XHR/fetch Breakpoints -> Any XHR or fetch 的勾
- Android学习——碎片Fragment的使用
一.碎片的简单用法(实现在一个活动中添加两个碎片,并让这两个碎片平分活动空间) 1.新建一个FragmentTest项目: 新建一个左侧碎片布局left_fragment.xml,代码如下:(只放置一 ...
- Java学习-课堂总结
一.字符串比较方式 1)‘==’ 地址值比较 2) equals()方法 内容比较 二.String类的两种实例化方式 1)String str=“Hello”: 2 ...
- 【Oracle】DBA_AUDIT_TRAIL表SES_ACTIONS字段对应的操作列表
SES_ACTIONS字段共包含16个字符,初始状态都为“-”,当被审计的对象被操作后,SES_ACTIONS会在相应的位置作出标识,标识为“S”的代表操作成功,标识为“F”的代表操作失败,16个位置 ...
- VHDL_LIB之DFF
1 D-Flip-Flop with async reset or set library IEEE; use ieee.std_logic_1164.all; entity FFD is gener ...
- sql变量需要加小括号
declare @num int select top (@num) * from A --注意,使用变量来查询的时候,单个变量需要使用()
- Java中数组的概念与特点
数组概念: 数组其实也是一个容器,可以用来存储固定个数相同类型的数据数组的定义 数组中存储的数据叫做元素 特点: 1.数组是引用数据类型 2.数组的长度是固定的,也就是说可以存储固定个数的数据 3.数 ...