Problem 6

Problem 6

# Problem_6.py
"""
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum
找出100一下的所有自然数的平方和与这些自然数的和的平方之间的差数.
"""
sum_of_squares = sum([i*i for i in range(1, 101)])
square_of_sum = pow(sum([i for i in range(1, 101)]), 2)
 
print(square_of_sum, '-', sum_of_squares, '=', square_of_sum-sum_of_squares)