[LC] 1048. Longest String Chain
Given a list of words, each word consists of English lowercase letters.
Let's say word1
is a predecessor of word2
if and only if we can add exactly one letter anywhere in word1
to make it equal to word2
. For example, "abc"
is a predecessor of "abac"
.
A word chain is a sequence of words [word_1, word_2, ..., word_k]
with k >= 1
, where word_1
is a predecessor of word_2
, word_2
is a predecessor of word_3
, and so on.
Return the longest possible length of a word chain with words chosen from the given list of words
.
Example 1:
Input: ["a","b","ba","bca","bda","bdca"]
Output: 4
Explanation: one of the longest word chain is "a","ba","bda","bdca".
class Solution {
public int longestStrChain(String[] words) {
Arrays.sort(words, (a, b) -> a.length() - b.length());
// map is used as space for dp best[i] = 1 + best[i- 1]
Map<String, Integer> map = new HashMap<>();
int res = 0;
for (String word: words) {
map.put(word, 1);
for (int i = 0; i < word.length(); i++) {
String prev = word.substring(0, i) + word.substring(i + 1);
int curLen = map.get(word);
if (map.containsKey(prev) && map.get(prev) + 1 > curLen) {
map.put(word, map.get(prev) + 1);
}
}
res = Math.max(res, map.get(word));
}
return res;
}
}
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