Python列表中的字典按照该字典下的键值进行排序

列表中的字典按照该字典下的键值进行排序

这算是排序中比较复杂的一种情况吧，多重嵌套，按照某种规则进行排序。
如下面这个json（注：这里这是该列表中的一个项）:

[
    {
        "stat": {
            "question_id": 1339,
            "question__article__live": null,
            "question__article__slug": null,
            "question__title": "Team Scores in Football Tournament",
            "question__title_slug": "team-scores-in-football-tournament",
            "question__hide": false,
            "total_acs": 348,
            "total_submitted": 656,
            "frontend_question_id": 1212,
            "is_new_question": true
        },
        "status": null,
        "difficulty": {
            "level": 2
        },
        "paid_only": true,
        "is_favor": false,
        "frequency": 0,
        "progress": 0
    },
    {
        "stat": {
            "question_id": 1337,
            "question__article__live": null,
            "question__article__slug": null,
            "question__title": "Design Skiplist",
            "question__title_slug": "design-skiplist",
            "question__hide": false,
            "total_acs": 748,
            "total_submitted": 1261,
            "frontend_question_id": 1206,
            "is_new_question": false
        },
        "status": null,
        "difficulty": {
            "level": 3
        },
        "paid_only": false,
        "is_favor": false,
        "frequency": 0,
        "progress": 0
    }
]

list里面是字典，字典里面还是字典，加入按照frontend_question_id进行排序，提供两种方法：

# 方法1，注：原列表为list1，排序后list2
list2 = sorted(list1, key=lambda x : x['stat']['question_id'])

# 方法2
list1.sort(key=lambda x: x["stat"]['question_id'])

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参考: python中列表排序，字典排序，列表中的字典排序