In C++, this pointer is passed as a hidden argument to all non-static member function calls. The type of this depends upon function declaration. If the member function of a class X is declared const, the type of this is const X* (see code 1 below), if the member function is declared volatile, the type of this is volatile X* (see code 2 below), and if the member function is declared const volatile, the type of this is const volatile X* (see code 3 below).

  Code 1

  1. 1 #include<iostream>
  2. 2 class X
  3. 3 {
  4. 4 void fun() const
  5. 5 {
  6. 6 // this is passed as hidden argument to fun().
  7. 7 // Type of this is const X*
  8. 8 }
  9. 9 };

  Code 2

  1. 1 #include<iostream>
  2. 2 class X
  3. 3 {
  4. 4 void fun() volatile
  5. 5 {
  6. 6 // this is passed as hidden argument to fun().
  7. 7 // Type of this is volatile X*
  8. 8 }
  9. 9 };

  Code 3

  1. 1 #include<iostream>
  2. 2 class X
  3. 3 {
  4. 4 void fun() const volatile
  5. 5 {
  6. 6 // this is passed as hidden argument to fun().
  7. 7 // Type of this is const volatile X*
  8. 8 }
  9. 9 };

  补充:

  (1)In an ordinary nonconst member function, the type of this is a const pointer to the class type. We may change the value to which this points but cannot change the address that this holds. In a const member function, the type of this is a const pointer to a const class - type object. We may change neither the object to which this points nor the address that this holds.

  (2)What is the purpose of a volatile member function in C++?【from stackoverflow】

  

  References:http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1905.pdf

  Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
      

  转载请注明:http://www.cnblogs.com/iloveyouforever/  

  2013-11-26  09:32:58

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