【Leetcode_easy】690. Employee Importance
problem
题意:所有下属和自己的重要度之和,所有下属包括下属的下属即直接下属和间接下属。
solution:DFS;
/*
// Employee info
class Employee {
public:
// It's the unique ID of each node.
// unique id of this employee
int id;
// the importance value of this employee
int importance;
// the id of direct subordinates
vector<int> subordinates;
};
*/
class Solution {
public:
int getImportance(vector<Employee*> employees, int id) {
unordered_map<int, Employee*> mymap;//err.
for(auto employee:employees) mymap[employee->id] = employee;
return helper(id, mymap);
}
int helper(int id, unordered_map<int, Employee*> m) {
int res = m[id]->importance;
for(auto num:m[id]->subordinates)//err.
{
res += helper(num, m);
}
return res;
}
};
solution:BFS;
完
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