1、设计算法,对带头结点的单链表实现就地逆置。并给出单链表的存储结构(数据类型)的定义。

#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <ctime>
using namespace std; typedef char ElemType; typedef struct Node{
ElemType data;
struct Node *next;
}Node, *LinkList; LinkList CreateList()
{
LinkList L;
ElemType c;
L = (LinkList)malloc(sizeof(Node));
L->next = NULL;
Node *p , *tail;
tail = L;
c = getchar();
while(c != '#')
{
p = (Node *)malloc(sizeof(Node));
p->data = c;
tail->next = p;
tail = p;
c = getchar();
}
tail->next = NULL;
return L;
} void ShowList(LinkList L)
{
Node *p;
p = L->next;
while(p != NULL)
{
cout << p->data << " ";
p = p->next;
}
cout << endl;
} void ReverseList(LinkList L)
{
Node *p, *q;
p = L->next;
L->next = NULL;
while(p != NULL)
{
q = p->next;
p->next = L->next;
L->next = p;
p = q;
} } int main()
{
LinkList L;
L = CreateList();
ShowList(L); ReverseList(L);
ShowList(L);
return 0;
}

2、编写递归算法,将二叉树中所有结点的左、右子树相互交换。并给出算法中使用的二叉树的存储结构(数据类型)的定义。

typedef struct BiNode
{
char data;
struct BiNode *left;
struct BiNode *right;
}BiNode, *BiTree;
BiNode* Exchange(BiNode* T)
{
BiNode* p;
if(NULL==T || (NULL==T->lchild && NULL==T->rchild))
return T;
p = T->lchild;
T->lchild = T->rchild;
T->rchild = p;
if(T->lchild)
{
T->lchild = Exchange(T->lchild);
}
if(T->rchild)
{
T->rchild = Exchange(T->rchild);
}
return T;
}

3、折半查找算法。

#include<iostream>
#include<cstdio>
using namespace std;
int search(int *array, int n, int target)
{
int low = 0;
int high = n - 1;
if( low > high ) return -1;
while( low <= high )
{
int mid = low + ( high - low ) / 2;
if( array[mid] < target ) low = mid + 1;
else if( array[mid] > target ) high = mid - 1;
else return mid;
}
}
int main()
{
int a[] = {1,2,3,4,5,6,7,8,9};
cout<<search(a,9,4)<<endl;
return 0;
}

4、数据结构课本P74,习题2、13

void DeleteNode( ListNode *s)
    {//删除单循环链表中指定结点的直接前趋结点
      ListNode *p, *q;
      p=s;
      while( p->next->next!=s)
       p=p->next;
      //删除结点
      q=p->next;
      p->next=q->next;
      free(p); //释放空间
    }

5、统计叶子结点数。P168

#include<iostream>
#include<queue>
#include <cstdlib>
#include <cstdio>
using namespace std;
typedef struct BiNode
{
char data;
struct BiNode *left;
struct BiNode *right;
}BiNode, *BiTree;
int sum = 0;
void CreateBinaryTree(BiTree &T)//二叉树建立 abc,,de,g,,f,,,
{
//T = (BiNode*) malloc (sizeof(BiNode));
T = new BiNode;
cin >> T->data;
if(T->data == ',')
{
T = NULL;
}
if(T != NULL)
{
CreateBinaryTree(T->left);
CreateBinaryTree(T->right);
}
}
void PreOrder(BiTree T)//前序遍历
{
if(T != NULL)
{
cout << T->data;
PreOrder(T->left);
PreOrder(T->right);
}
}
void InOrder(BiTree T)//中序遍历
{
if(T != NULL)
{
InOrder(T->left);
cout << T->data;
InOrder(T->right);
}
}
void PostOrder(BiTree T)//后序遍历
{
if(T != NULL)
{
PostOrder(T->left);
PostOrder(T->right);
cout << T->data;
}
}
void LevOrder(BiTree T)//层次遍历
{
if(T != NULL)
{
BiTree p = T;
queue<BiTree>que;
que.push(p);
while(!que.empty())
{
p = que.front();
cout << p->data;
que.pop();
if(p->left != NULL)
{
que.push(p->left);
}
if(p->right != NULL)
{
que.push(p->right);
}
}
}
}
int Size(BiTree T)//计算二叉树节点数
{
if(T != NULL)
{
if(T->left == NULL && T->right == NULL)
{
sum++;
}
Size(T->left);
Size(T->right);
}
return sum;
}
int Deep(BiTree T)//计算二叉树深度
{
int m, n;
if(T == NULL) return 0;
m = Deep(T->left);
n = Deep(T->right);
if(m > n) return m + 1;
else return n + 1;
}
int main(void)
{
BiTree T;
CreateBinaryTree(T); cout << "前序遍历结果为:" << endl;
PreOrder(T);
cout << endl << endl; cout << "中序遍历结果为:" << endl;
InOrder(T);
cout << endl << endl; cout << "后序遍历结果为:" << endl;
PostOrder(T);
cout << endl << endl; cout<<"层次遍历结果为:"<<endl;
LevOrder(T);
cout << endl << endl; cout << "二叉树叶节点个数为:" << Size(T)<<endl;
cout << "二叉树深度数为:" << Deep(T) << endl;
system("pause");
return 0;
}

6、顺序表的合并。

#define MAXSIZE 100
typedef int ElemType; typedef struct SeqList
{
ElemType elem[MAXSIZE];
int last;
}SeqList;
void mergeList(SeqList *LA, SeqList * LB, SeqList *LC)
{
int i, j, k;
i = j = k = 0;
while (i <= LA->last && j <= LB->last)
{
if (LA->elem[i] <= LB->elem[j])
{
LC->elem[k++] = LA->elem[i++];
}
else
{
LC->elem[k++] = LB->elem[i++];
}
}
while (i <= LA->last)
{
LC->elem[k++] = LA->elem[i++];
}
while (j <= LB->last)
{
LC->elem[k++] = LB->elem[j++];
}
LC->last = LA->last + LB->last + 1;
}

data structure test的更多相关文章

  1. [LeetCode] All O`one Data Structure 全O(1)的数据结构

    Implement a data structure supporting the following operations: Inc(Key) - Inserts a new key with va ...

  2. [LeetCode] Add and Search Word - Data structure design 添加和查找单词-数据结构设计

    Design a data structure that supports the following two operations: void addWord(word) bool search(w ...

  3. [LeetCode] Two Sum III - Data structure design 两数之和之三 - 数据结构设计

    Design and implement a TwoSum class. It should support the following operations:add and find. add - ...

  4. Finger Trees: A Simple General-purpose Data Structure

    http://staff.city.ac.uk/~ross/papers/FingerTree.html Summary We present 2-3 finger trees, a function ...

  5. Mesh Data Structure in OpenCascade

    Mesh Data Structure in OpenCascade eryar@163.com 摘要Abstract:本文对网格数据结构作简要介绍,并结合使用OpenCascade中的数据结构,将网 ...

  6. ✡ leetcode 170. Two Sum III - Data structure design 设计two sum模式 --------- java

    Design and implement a TwoSum class. It should support the following operations: add and find. add - ...

  7. leetcode Add and Search Word - Data structure design

    我要在这里装个逼啦 class WordDictionary(object): def __init__(self): """ initialize your data ...

  8. Java for LeetCode 211 Add and Search Word - Data structure design

    Design a data structure that supports the following two operations: void addWord(word)bool search(wo ...

  9. HDU5739 Fantasia(点双连通分量 + Block Forest Data Structure)

    题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5739 Description Professor Zhang has an undirect ...

  10. LeetCode Two Sum III - Data structure design

    原题链接在这里:https://leetcode.com/problems/two-sum-iii-data-structure-design/ 题目: Design and implement a ...

随机推荐

  1. P2871 [USACO07DEC]手链Charm Bracelet(01背包模板)

    题目传送门:P2871 [USACO07DEC]手链Charm Bracelet 题目描述 Bessie has gone to the mall's jewelry store and spies ...

  2. 条款03:尽可能使用const

    目录 1. 总结 2. const对象 3. const函数返回值和函数参数 4. const成员函数 const成员函数的重要性 bitwise constness logical constnes ...

  3. 【JavaWeb学习】过滤器Filter

    一.简介 Filter也称之为过滤器,它是Servlet技术中最激动人心的技术,WEB开发人员通过Filter技术,对web服务器管理的所有web资源:例如Jsp, Servlet, 静态图片文件或静 ...

  4. pqsql 防注入

    在数据库查询时经常会遇到根据传入的参数查询内容的情况,传入的参数有可能会带有恶意代码,比如or 1=1,这样where判断为true,就会返还所有的记录.为了解决这个问题,可以在参数外面包一层单引号, ...

  5. Python使用requests爬取一个网页并保存

    #导入 requests模块import requests #设置请求头,让网站监测是浏览器 headers = { 'user-agent': 'Mozilla/5.0 (Windows NT 6. ...

  6. Beetlex实现完整的HTTP协议

    在传统网络服务中扩展中需要处理Bytes来进行协议的读写,这种原始的处理方式让工作变得相当繁琐复杂,出错和调试的工作量都非常大:组件为了解决这一问题引用Stream读写方式,这种方式可以极大的简化网络 ...

  7. java反序列化php序列化的对象

    最近工作中遇到一个需要解析php序列化后存入DB的array, a:4:{i:0;a:2:{s:11:"province";s:8:"0016";s:7:&qu ...

  8. BZOJ4559&P3270[JLoi2016]成绩比较

    题目描述 \(G\)系共有\(n\)位同学,\(M\)门必修课.这\(N\)位同学的编号为\(0\)到\(N-1\)的整数,其中\(B\)神的编号为\(0\)号.这\(M\)门必修课编号为\(0\)到 ...

  9. eclipse开发工具内打开某js文件总是用记事本方式打开的问题

    问题现象: 开发时不知道按到了什么快捷键,导致在某js文件内点击某调用方法时莫名其妙的用记事本方式打开了该js文件,试了几次都是这样.索性将该js文件关掉重新打开,结果双击该文件还是弹出了一个记事本, ...

  10. Pandas中merge和join的区别

    可以说merge包含了join的操作,merge支持通过列或索引连表,而join只支持通过索引连表,只是简化了merge的索引连表的参数 示例 定义一个left的DataFrame left=pd.D ...