[LeetCode] 58. Length of Last Word_Easy tag: String
Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Input: "Hello World"
Output: 5
就先利用s.strip()将前后的space去掉, 然后再用split(' ') 将最后的word的length得到并返回.
Code
class Solution:
def lengthOfLastWord(self, s):
s = s.strip()
if not s: return 0
return len(s.split(' ')[-1])
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