不会。。。

参考:

思路类似于coin那个题,for循环中在满足条件时就及时更新当下位置的信息

def lengthOfLIS(nums):
"""
:type nums: List[int]
:rtype: int
"""
if nums==[]:
return
N = len(nums)
Dp = []*N
print(N,Dp)
for i in range(N-):
for j in range(,i+):
if nums[i+]>nums[j]:
Dp[i+] = max(Dp[i+],Dp[j]+)
return max(Dp)

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