leetcode-mid-dynamic programming- Longest Increasing Subsequence-NO
不会。。。
参考:
思路类似于coin那个题,for循环中在满足条件时就及时更新当下位置的信息
def lengthOfLIS(nums):
"""
:type nums: List[int]
:rtype: int
"""
if nums==[]:
return
N = len(nums)
Dp = []*N
print(N,Dp)
for i in range(N-):
for j in range(,i+):
if nums[i+]>nums[j]:
Dp[i+] = max(Dp[i+],Dp[j]+)
return max(Dp)
leetcode-mid-dynamic programming- Longest Increasing Subsequence-NO的更多相关文章
- [Leetcode] Binary search, DP--300. Longest Increasing Subsequence
Given an unsorted array of integers, find the length of longest increasing subsequence. For example, ...
- [LeetCode] 673. Number of Longest Increasing Subsequence 最长递增序列的个数
Given an unsorted array of integers, find the number of longest increasing subsequence. Example 1: I ...
- LeetCode 673. Number of Longest Increasing Subsequence
Given an unsorted array of integers, find the number of longest increasing subsequence. Example 1: I ...
- Dynamic Programming | Set 3 (Longest Increasing Subsequence)
在 Dynamic Programming | Set 1 (Overlapping Subproblems Property) 和 Dynamic Programming | Set 2 (Opti ...
- [LeetCode] Longest Increasing Subsequence 最长递增子序列
Given an unsorted array of integers, find the length of longest increasing subsequence. For example, ...
- [LeetCode] 300. Longest Increasing Subsequence 最长递增子序列
Given an unsorted array of integers, find the length of longest increasing subsequence. Example: Inp ...
- [LeetCode] Number of Longest Increasing Subsequence 最长递增序列的个数
Given an unsorted array of integers, find the number of longest increasing subsequence. Example 1: I ...
- LeetCode 300. Longest Increasing Subsequence最长上升子序列 (C++/Java)
题目: Given an unsorted array of integers, find the length of longest increasing subsequence. Example: ...
- Leetcode 300 Longest Increasing Subsequence
Given an unsorted array of integers, find the length of longest increasing subsequence. For example, ...
- leetcode@ [300] Longest Increasing Subsequence (记忆化搜索)
https://leetcode.com/problems/longest-increasing-subsequence/ Given an unsorted array of integers, f ...
随机推荐
- 定位class时空格注意
class属性中间的空格并不是空字符串,那是间隔符号,表示的是一个元素有多个class的属性名称,那定位的时候取其中的一个就行(并且要唯一) Selenium2+python自动化73-定位的坑:cl ...
- springboot(十五)-Runner启动器
Runner启动器 如果你想在Spring Boot启动的时候运行一些特定的代码,你可以实现接口ApplicationRunner或者CommandLineRunner,这两个接口实现方式一样,它们都 ...
- knative 安装
knative 安装 本文安装版本 knative 0.6. 准备 安装 knative 前需要事先安装 Kubernetes 集群 和 Istio. 安装 下载安装所需要的文件.以下选择的是全安装, ...
- 使用 dataset 管理数据(官网)
ECharts 4 开始支持了 dataset 组件用于单独的数据集声明,从而数据可以单独管理,被多个组件复用,并且可以基于数据指定数据到视觉的映射.这在不少场景下能带来使用上的方便. ECharts ...
- iconv_close - 关闭字符转换描述符
总览 (SYNOPSIS) #include <iconv.h> int iconv_close (iconv_t cd); 描述 (DESCRIPTION) iconv_close 函数 ...
- [转载]【转】乘法器的Verilog HDL实现
乘法器如果直接用*来实现的话,会消耗很多的资源.所以有了串行和并行两种实现思路.用串行的话,8位一般会有8位以上的延迟,但是消耗的资源是最少的.低速数据处理比较适合.并行也就是流水线方法,以时间换 ...
- 2017 ICPC 南宁 L 带权最大递增子序列
#include<cstdio> #include<iostream> #include<cstring> #include<cmath> #inclu ...
- java面向对象1-面向对象概念
面向对象概念-类与对象的关系 封装:指隐藏对象的属性和实现细节,仅对外提供公共访问方式,private-构造方法/构造器-this关键字-static关键字(javadoc制作工具类) -代码块 继承 ...
- iOS中延迟执行和取消的几种方式
公用延迟执行的方法: - (void)delayMethod { NSLog(@"delayMethodEnd"); } 方法一.performSelector 方法 1.延迟执行 ...
- 【SaltStack官方版】—— STORING JOB RESULTS IN AN EXTERNAL SYSTEM
STORING JOB RESULTS IN AN EXTERNAL SYSTEM After a job executes, job results are returned to the Salt ...