http://acm.hdu.edu.cn/showproblem.php?pid=3038

How Many Answers Are Wrong

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3648 Accepted Submission(s):
1401

Problem Description
TT and FF are ... friends. Uh... very very good friends
-________-b

FF is a bad boy, he is always wooing TT to play the following
game with him. This is a very humdrum game. To begin with, TT should write down
a sequence of integers-_-!!(bored).

Then, FF can
choose a continuous subsequence from it(for example the subsequence from the
third to the fifth integer inclusively). After that, FF will ask TT what the sum
of the subsequence he chose is. The next, TT will answer FF's question. Then, FF
can redo this process. In the end, FF must work out the entire sequence of
integers.

Boring~~Boring~~a very very boring game!!! TT doesn't want to
play with FF at all. To punish FF, she often tells FF the wrong answers on
purpose.

The bad boy is not a fool man. FF detects some answers are incompatible. Of course, these contradictions make it difficult to calculate the sequence.

However, TT is a nice and lovely girl. She doesn't have the heart to be hard on FF. To save time, she guarantees that the answers are all right if there is no logical mistakes indeed.

What's more, if FF finds an answer to be wrong, he will ignore it when judging next answers.

But there will be so many questions that poor FF can't make sure whether the current answer is right or wrong in a moment. So he decides to write a program to help him with this matter. The program will receive a series of questions from FF together with the answers FF has received from TT. The aim of this program is to find how many answers are wrong. Only by ignoring the wrong answers can FF work out the entire sequence of integers. Poor FF has no time to do this job. And now he is asking for your help~(Why asking trouble for himself~~Bad boy)

 
Input
Line 1: Two integers, N and M (1 <= N <= 200000, 1 <= M <= 40000). Means TT wrote N integers and FF asked her M questions.

Line 2..M+1: Line i+1 contains three integer: Ai, Bi and Si. Means TT answered FF that the sum from Ai to Bi is Si. It's guaranteed that 0 < Ai <= Bi <= N.

You can assume that any sum of subsequence is fit in 32-bit integer.

 
Output
A single line with a integer denotes how many answers are wrong.
 
Sample Input
10 5
1 10 100
7 10 28
1 3 32
4 6 41
6 6 1
 
Sample Output
1
 
题目大意:有m句话,从第x个数加到第y个是和为w,问错误的有几句
 
y比x - 1 多w
r[i] 表示这句话的状态
 
         r[x] + w - r[y]
rx<-------------------ry
                                 
 ↑ r[x]                       ↑r[y]
               w
 x<-------------------y
(x - 1)
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
#include<ctype.h>
#define N 200010 int f[N], r[N]; int Find(int x)
{
int k = f[x];
if(x != f[x])
f[x] = Find(f[x]);
r[x] = r[x] + r[k];
return f[x];
} int main()
{
int i, n, m, x, y, w, rx, ry, ans;
while(scanf("%d%d", &n, &m) != EOF)
{
ans = ;
for(i = ; i <= n ; i++)
{
f[i] = i;
r[i] = ;
}
while(m)
{
m--;
scanf("%d%d%d", &x, &y, &w);
x--;
rx = Find(x), ry = Find(y);
if(rx != ry)
{
f[ry] = rx;
r[ry] = w + r[x] - r[y];
}
else
{
if(w != r[y] - r[x])
ans++;
}
}
printf("%d\n", ans);
}
return ;
}

hdu 3038 How Many Answers Are Wrong的更多相关文章

  1. HDU 3038 How Many Answers Are Wrong 【YY && 带权并查集】

    任意门:http://acm.hdu.edu.cn/showproblem.php?pid=3038 How Many Answers Are Wrong Time Limit: 2000/1000 ...

  2. HDU 3038 - How Many Answers Are Wrong - [经典带权并查集]

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3038 Time Limit: 2000/1000 MS (Java/Others) Memory Li ...

  3. hdu 3038 How Many Answers Are Wrong(并查集的思想利用)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3038 题意:就是给出n个数和依次m个问题,每个问题都是一个区间的和,然后问你这些问题中有几个有问题,有 ...

  4. HDU 3038 How Many Answers Are Wrong(带权并查集)

    传送门 Description TT and FF are ... friends. Uh... very very good friends -________-b FF is a bad boy, ...

  5. hdu 3038 How Many Answers Are Wrong ( 带 权 并 查 集 )

    How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Ja ...

  6. HDU 3038 How Many Answers Are Wrong (并查集)

    How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Ja ...

  7. HDU 3038 How Many Answers Are Wrong (并查集)---并查集看不出来系列-1

    Problem Description TT and FF are ... friends. Uh... very very good friends -________-bFF is a bad b ...

  8. HDU 3038 How Many Answers Are Wrong(带权并查集,真的很难想到是个并查集!!!)

    How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Ja ...

  9. HDU 3038 How Many Answers Are Wrong(种类并查集)

    题目链接 食物链类似的题,主要是在于转化,a-b的和为s,转换为b比a-1大s.然后并查集存 此节点到根的差. 假如x的根为a,y的根为b: b - y = rank[y] a - x = rank[ ...

随机推荐

  1. CSS+DIV问题!DIV的最小高度问题!

    DIV层的最小高度问题!就是一个DIV有个最小高度,但是如果DIV层中的内容很多,DIV的高度会根据内容而进行拉长!要求IE6.IE7还有firefox都要兼容!我试了很多网上的方法都不好用!请测试后 ...

  2. chrome调试、移动端调试

    chrome 32版本后,添加 DevTools for Mobile 插件就可远程手机调试 DevTools for Mobile插件安装https://support.google.com/chr ...

  3. 8天学通MongoDB——第八天 驱动实践

    作为系列的最后一篇,得要说说C#驱动对mongodb的操作,目前驱动有两种:官方驱动和samus驱动,不过我个人还是喜欢后者, 因为提供了丰富的linq操作,相当方便. 官方驱动:https://gi ...

  4. iOS开发:插件记录

    进入沙盒的插件 https://github.com/TongeJie/ZLGotoSandboxPlugin 图片提示的插件 https://github.com/ksuther/KSImageNa ...

  5. LA 5059 (找规律 SG函数) Playing With Stones

    题意: 有n堆石子,两个人轮流取,每次只能取一堆的至少一个至多一半石子,直到不能取为止. 判断先手是否必胜. 分析: 本题的关键就是求SG函数,可是直接分析又不太好分析,于是乎找规律. 经过一番“巧妙 ...

  6. 编写爬虫(spider)的预备知识:用java发送HTTP请求

    使用原生API来发送http请求,而不是使用apache的库,原因在于这个第三方库变化实在太快了,每个版本都有不小的变化.对于程序员来说,使用它反而会有很多麻烦,比如自己曾经写过的代码将无法复用. 原 ...

  7. 【转】Android 如何在Eclipse中查看Android API源码 及 support包源码

    原文网址:http://blog.csdn.net/vipzjyno1/article/details/22954775 当我们阅读android API开发文档时候,上面的每个类,以及类的各个方法都 ...

  8. Android如何调用第三方SO库

    问题描述:Android如何调用第三方SO库:已知条件:SO库为Android版本连接库(*.so文件),并提供了详细的接口说明:已了解解决方案:1.将SO文件直接放到libs/armeabi下,然后 ...

  9. date.plugin.js 日期插件

    //定义命名空间 var DatePlugin; if (!DatePlugin) DatePlugin = {}; /*整理时间:2015-05-28*/ var defaultFormat = & ...

  10. Java与WCF交互(一):Java客户端调用WCF服务

    最近开始了解WCF,写了个最简单的Helloworld,想通过java客户端实现通信.没想到以我的基础,居然花了整整两天(当然是工作以外的时间,呵呵),整个过程大费周折,特写下此文,以供有需要的朋友参 ...