PKU1008

题名：玛雅历

题意：历法转换 。

代码：

// 1008.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"

#include <iostream>
using namespace std;
class data
{
public:
    char day[];
    char mon[];
    char year[];
};

int main(int argc, char* argv[])
{
    int num=;
    cin>>num;
    char temp[]={};
    data *s=new data[num];
    for (int i=;i<num;i++)
    {
        cin>>s[i].day>>s[i].mon>>s[i].year;
    }
    cout<<num<<endl;
    string *sday=new string[];
    int tmon=,tday=;
    int count=;
    int o=,p=;
    string ma[]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
    while()//计算Tzolkin历表对应一年中的天数
    {
        o++;
        p++;
        if(o>)
            o=;
        if(p>)
            p=;
        char temp[];
        sprintf(temp,"%d ",o);
        sday[count]=temp;
        sday[count]+=ma[p-];
        count++;
        if(count==)
            break;

    }
    string HaabMonDic[]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
    for (int i=;i<num;i++)
    {
        int day=atoi(s[i].day)+;
        string month=s[i].mon;
        int imonth=;
        string year=s[i].year;
        int iyear=atoi(year.c_str());
        for (int j=;j<;j++)
        {
            if(month.compare(HaabMonDic[j])==)
            {
                imonth=j;
                break;
            }
        }
        int allday=iyear*+imonth*+day;
        int tyear=allday/;
        int tt=allday%;
        if(tt==)//如果是最后一天，需要转换
        {
            tyear--;
            tt=;
        }
        printf("%s %d\n",sday[tt-].c_str(),tyear);
    }
    delete []sday;
    delete []s;
    return ;

}

总结：想当然，忘记要转换的历法最后一天要特殊处理，第一种历法实际上是有19个月。马虎粗心大意，哎