算法（Algorithms）第4版 练习 1.3.26

方法实现：

//1.3.26
    /**
     * remove all of the nodes in the list that have key as its item field
     *
     * @param list the linked list of T
     * @param key the T key
     *
     * @return void
     *
     */
    public static <T> void remove(LinkedList<T> list, T key) {
        Node<T> precurrent;
        precurrent = findPreNode(list, key);

        //remove all of the nodes
        while(precurrent.next != null) {

            if(precurrent.next == list.first)
                list.first = list.first.next;
            else
                precurrent.next = precurrent.next.next;

            precurrent = findPreNode(list, key);
        }

    }

    //1.3.26
    /**
     * find the node in the list whose item equals key
     *
     * @param key the T key
     *
     * @return return the previous node whose item equals key
     */
    private static <T> Node<T> findPreNode(LinkedList<T> list, T key) {
        Node<T> precurrent = new Node<T>();
        precurrent.next = list.first;

        while(precurrent.next != null && !precurrent.next.item.equals(key)) {
            precurrent = precurrent.next;
        }

        return precurrent;
    }

测试用例：

package com.qiusongde.linkedlist;

import edu.princeton.cs.algs4.StdIn;
import edu.princeton.cs.algs4.StdOut;

public class Exercise1326 {

    public static void main(String[] args) {

        String key = "to";

        LinkedList<String> list = new LinkedList<String>();

        while(!StdIn.isEmpty()) {
            String s = StdIn.readString();
            list.insertAtBeginning(s);
            StdOut.println("insertAtBeginning success: " + s);
            StdOut.println(list);
        }

        LinkedList.remove(list, key);
        StdOut.println("remove success:" + key);
        StdOut.println(list);

    }

}

输入数据：

to
be
or
not
to

结果1：

insertAtBeginning success: to
to
insertAtBeginning success: be
be to
insertAtBeginning success: or
or be to
insertAtBeginning success: not
not or be to
insertAtBeginning success: to
to not or be to
remove success:to
not or be 

结果2：

insertAtBeginning success: to
to
insertAtBeginning success: be
be to
insertAtBeginning success: or
or be to
insertAtBeginning success: not
not or be to
insertAtBeginning success: to
to not or be to
remove success:not
to or be to 

结果3：

insertAtBeginning success: to
to
insertAtBeginning success: be
be to
insertAtBeginning success: or
or be to
insertAtBeginning success: not
not or be to
insertAtBeginning success: to
to not or be to
remove success:qiu
to not or be to