ArrayList的sublist注意

 void testArrayList(){
         String []appname ={"联系人","相机","电话","收音机","手电筒","更多"};
         String s_appname = null;
         List<Map<String, Object>>  gv_applist = new ArrayList<Map<String,Object>>();
         for(int i=0; i<appname.length;i++) {

             s_appname = appname[i];
             Map<String, Object> map = new HashMap<String, Object>();
             map.put("appname", s_appname);
             gv_applist.add(map);
          }

         List<Map<String, Object>>  templist1 = new ArrayList<Map<String, Object>>();
         templist1 = gv_applist.subList(0, 4);
         System.out.println(templist1.size());//输出4
 //        gv_applist.remove(2);
         templist1.size();//报错 java.util.ConcurrentModificationException

         List<Map<String, Object>>  templist2 = new ArrayList<Map<String, Object>>(gv_applist.subList(0, 4));
         System.out.println(templist2.size());//输出4
         gv_applist.remove(2);
         System.out.println(templist2.size());//输出4,这种方式子链表不受母链表影响，母链表可以任意操作

         templist2.remove(2);
         System.out.println(templist2.size());//输出3

     }