计算机学院大学生程序设计竞赛(2015’12)The Country List
The Country List
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2464 Accepted Submission(s): 576
annoyed for a long time.
Some countries’ names look so similar that he can’t distinguish them. Such as: Albania and Algeria. If two countries’ names have the same length and there are more than 2 same letters in the same position of each word, CC cannot distinguish them. For example:
Albania and AlgerIa have the same length 7, and their first, second, sixth and seventh letters are same. So CC can’t distinguish them.
Now he has received a name list of countries, please tell him how many words he cannot distinguish. Note that comparisons between letters are case-insensitive.
Each case begins with an integer n (0 < n < 100) indicating the number of countries in the list.
The next n lines each contain a country’s name consisted by ‘a’ ~ ‘z’ or ‘A’ ~ ‘Z’.
Length of each word will not exceed 20.
You can assume that no name will show up twice in the list.
3 Denmark GERMANY China 4 Aaaa aBaa cBaa cBad
2 4
总是望着曾经的空间发呆,那些说好不分开的朋友不在了,转身,陌路。 熟悉的,安静了, 安静的,离开了, 离开的,陌生了, 陌生的,消失了, 消失的,陌路了。
- #include <stdio.h>
- #include <stdlib.h>
- #include <string.h>
- int da[105]= {0};
- void bijiao(int n,char c[105][30])
- {
- int i,j,t=0,q;
- for(i=0; i<n; i++)
- for(j=0; j<n; j++)
- {
- t=0;
- if(strcmp(c[i],c[j])==0)continue;
- if(strlen(c[i])==strlen(c[j]))
- {
- for(q=0; q<(int)strlen(c[i]); q++)
- {
- if(c[i][q]==c[j][q])t++;
- }
- if(t>2)
- {
- da[i]=1;
- da[j]=1;
- }
- }
- }
- }
- void xiaoxie(char c[30])
- {
- int n=strlen(c),i;
- for(i=0; i<n; i++)
- {
- if(c[i]>='A'&&c[i]<='Z')c[i]+=32;
- }
- }
- int main()
- {
- int n,i,j;
- char c[105][30];
- while(~scanf("%d",&n)&&n)
- {
- j=0;
- getchar();
- for(i=0; i<n; i++)da[i]=0;
- for(i=0; i<n; i++)
- {
- gets(c[i]);
- xiaoxie(c[i]);
- }
- bijiao(n,c);
- for(i=0; i<n; i++)j+=da[i];
- printf("%d\n",j);
- }
- return 0;
- }
@执念 "@☆但求“❤”安★
下次我们做的一定会更好。。。。
为什么这次的题目是英文的。。。。QAQ...
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