C - Common Subsequence
C - Common Subsequence
Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u
Description
The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Input
abcfbc abfcab
programming contest
abcd mnp
Output
4
2
0
Sample Input
abcfbc abfcab
programming contest
abcd mnp
Sample Output
4
2
0 //求两个字符串的最长公共子序列长度 //虽然是 dp 序列水题,但是我第一次做不会,没想到转移方程 代码里写的很清楚了,31ms dp[i][j]表示0到i-1跟0到j-1的最长公共子序列长度
#include <stdio.h>
#include <string.h> char a[];
char b[];
int dp[][]; int max(int x,int y)
{return x>y?x:y;} int main()
{
int i,j;
while(scanf("%s%s",a,b)!=EOF)
{
int la=strlen(a),lb=strlen(b);
for (i=;i<=lb;i++)
dp[][i]=;
for (i=;i<=la;i++)
dp[i][]=;
for (i=;i<=la;i++)
{
for (j=;j<=lb;j++)
{
if (a[i-]==b[j-])
dp[i][j]=dp[i-][j-]+;
else
dp[i][j]=max(dp[i-][j],dp[i][j-]);
}
}
printf("%d\n",dp[la][lb]);
}
return ;
}
C - Common Subsequence的更多相关文章
- 动态规划求最长公共子序列(Longest Common Subsequence, LCS)
1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与 ...
- LintCode Longest Common Subsequence
原题链接在这里:http://www.lintcode.com/en/problem/longest-common-subsequence/ 题目: Given two strings, find t ...
- [UCSD白板题] Longest Common Subsequence of Three Sequences
Problem Introduction In this problem, your goal is to compute the length of a longest common subsequ ...
- LCS(Longest Common Subsequence 最长公共子序列)
最长公共子序列 英文缩写为LCS(Longest Common Subsequence).其定义是,一个序列 S ,如果分别是两个或多个已知序列的子序列,且是所有符合此条件序列中最长的,则 S 称为已 ...
- Longest Common Subsequence
Given two strings, find the longest common subsequence (LCS). Your code should return the length of ...
- LCS POJ 1458 Common Subsequence
题目传送门 题意:输出两字符串的最长公共子序列长度 分析:LCS(Longest Common Subsequence)裸题.状态转移方程:dp[i+1][j+1] = dp[i][j] + 1; ( ...
- Common Subsequence LCS
题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/F 题目: Description A subsequ ...
- poj 1458 Common Subsequence
Common Subsequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 46387 Accepted: 19 ...
- Longest Increasing Common Subsequence (LICS)
最长上升公共子序列(Longest Increasing Common Subsequence,LICS)也是经典DP问题,是LCS与LIS的混合. Problem 求数列 a[1..n], b[1. ...
- Common Subsequence(dp)
Common Subsequence Time Limit: 2 Sec Memory Limit: 64 MBSubmit: 951 Solved: 374 Description A subs ...
随机推荐
- 关于国内外CV领域牛人的博客链接 .
此文为转载文章,尊重知识产权http://blog.csdn.net/carson2005/article/details/6601109此为原文链接,感谢作者! 以下链接是关于计算机视觉(Compu ...
- leetcode题解:Search for a Range (已排序数组范围查找)
题目: Given a sorted array of integers, find the starting and ending position of a given target value. ...
- linux /etc/hosts 配置问题
在java code中获取本机IP的程序如下: import java.net.InetAddress; public class Test { public static void main(Str ...
- 2017.10.13 git提交时忽略不必要的文件或文件夹
参考来自:git学习六:git提交忽略不必要的文件或文件夹 1.应用场景 创建maven项目,使用git提交,有时需要忽略不必要的文件或文件夹,只保留一些基本. 例如如下截图,实际开发中我们只需提交: ...
- Win7如何配置java环境变量,运行环境
直接运行eclipse,弹出错误提示. 1 确保你安装了JDK,安装之后文件夹示例如下(jdk1.x.x取决于你安装的JDK版本) 2 系统,高级系统设置,高级,环境变量新建一个JAVA_HO ...
- 如何安装Android SDK Emulator
1 下载并安装JDK,可以到官方网站寻找自己的对应版本下载 http://www.oracle.com/technetwork/java/javase/downloads/jdk-7u1-downlo ...
- 在 Linux 系统下使用 PhotoRec & TestDisk 工具来恢复文件
当你在系统中有意或无意地使用 shift + delete 组合键.删除选项,或是清空回收站的方式来删除一个文件时,该文件的内容并没有从硬盘(或是其它存储设备)上直接销毁. 它仅仅是从系统的目录结构中 ...
- html实现网站全局按钮点击后置灰,不允许连续点击
<script> document.addEventListener("mouseup", upHandler, true); function upHandler(e ...
- 转: Genymotion使用及离线镜像的安装
Genymotion是一套完整的工具,它提供了Android虚拟环境.由于它比Android自带的模拟器要流畅好多,所以它简直就是开发者.测试人员.推销者甚至是游戏玩家的福音.支持Windows.Li ...
- Android_Fragment_Fragment详解
Android_Fragment_Fragment详解 分类: Android基础2013-10-03 08:23 92人阅读 评论(0) 收藏 举报 AndroidFragmentFragmen ...