1118 Birds in Forest (25 分)
Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pair of birds, tell if they are on the same tree.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive number N (≤104) which is the number of pictures. Then N lines follow, each describes a picture in the format:
K B1 B2 ... BK
where K is the number of birds in this picture, and Bi's are the indices of birds. It is guaranteed that the birds in all the pictures are numbered continuously from 1 to some number that is no more than 104.
After the pictures there is a positive number Q (≤104) which is the number of queries. Then Q lines follow, each contains the indices of two birds.
Output Specification:
For each test case, first output in a line the maximum possible number of trees and the number of birds. Then for each query, print in a line Yes
if the two birds belong to the same tree, or No
if not.
Sample Input:
4
3 10 1 2
2 3 4
4 1 5 7 8
3 9 6 4
2
10 5
3 7
Sample Output:
2 10
Yes
No
分析:并查集,水题。
/** * Copyright(c) * All rights reserved. * Author : Mered1th * Date : 2019-02-27-20.04.59 * Description : A1118 */ #include<cstdio> #include<cstring> #include<iostream> #include<cmath> #include<algorithm> #include<string> #include<unordered_set> #include<map> #include<vector> #include<set> using namespace std; ; int father[maxn]; int findFather(int x){ int a=x; while(x!=father[x]){ x=father[x]; } while(a!=father[a]){ int z=a; a=father[a]; father[z]=x; } return x; } void Union(int a,int b){ int faA=findFather(a); int faB=findFather(b); if(faA!=faB){ father[faB]=faA; } } int main(){ #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif ; scanf("%d",&n); ;i<maxn;i++) father[i]=i; ;i<n;i++){ scanf("%d%d",&k,&t); maxin=max(maxin,t); ;j<k-;j++){ scanf("%d",&t1); maxin=max(maxin,t1); Union(t,t1); } } set<int> tree; ;i<=maxin;i++){ tree.insert(findFather(i)); } printf("%d %d\n",tree.size(),maxin); int query,u,v; scanf("%d",&query); ;i<query;i++){ scanf("%d%d",&u,&v); if(findFather(u)==findFather(v)) printf("Yes\n"); else printf("No\n"); } ; }
1118 Birds in Forest (25 分)的更多相关文章
- 【PAT甲级】1118 Birds in Forest (25分)(并查集)
题意: 输入一个正整数N(<=10000),接着输入N行数字每行包括一个正整数K和K个正整数,表示这K只鸟是同一棵树上的.输出最多可能有几棵树以及一共有多少只鸟.接着输入一个正整数Q,接着输入Q ...
- [并查集] 1118. Birds in Forest (25)
1118. Birds in Forest (25) Some scientists took pictures of thousands of birds in a forest. Assume t ...
- 1118. Birds in Forest (25)
Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in ...
- PAT A 1118. Birds in Forest (25)【并查集】
并查集合并 #include<iostream> using namespace std; const int MAX = 10010; int father[MAX],root[MAX] ...
- PAT题解-1118. Birds in Forest (25)-(并查集模板题)
如题... #include <iostream> #include <cstdio> #include <algorithm> #include <stri ...
- PAT甲级——1118 Birds in Forest (并查集)
此文章 同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/89819984 1118 Birds in Forest ...
- PAT 1118 Birds in Forest [一般]
1118 Birds in Forest (25 分) Some scientists took pictures of thousands of birds in a forest. Assume ...
- 1118 Birds in Forest (25 分)
Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in ...
- PAT 1118 Birds in Forest
Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in ...
随机推荐
- python str使用笔记(更新)
判断字符串是否以某个串为结尾: str.endswith(strtmp) 返回True/False >>> strs='aba' >>> strs.endswith ...
- What is the $ symbol used for in JavaScript
It doesn't mean anything special. But because $ is allowed in identifier names, many Javascript libr ...
- maven(二)
1.1 Maven的好处 节省空间 对jar包做了统一管理 依赖管理 一键构建 可跨平台 应用在大型项目可提高开发效率 1.2 Maven安装部署配置 1.3 Maven的仓库 ...
- PyMongo 常见问题
PyMongo是线程安全的吗PyMongo是线程安全的,并且为多线程应用提供了内置的连接池 PyMongo是进程安全的吗PyMongo不是进程安全的,如果你在fork()中使用MongoClient实 ...
- 汇编入门基础与helloworld
一个存储器拥有128个存储单元,可存储128个byte(字节),一个bite则又是由8个二进制位即bit(比特)组成,bit是计算机的最小信息单位. 总线分为地址总线,控制总线,数据总线 一个cpu有 ...
- IntelliJ快捷键笔记
1.查找文件:Ctrl+Shift+N 2.大小写转换:Ctrl+Shift+U 3.get/set方法快捷键:Alt+Insert 4. 查看类继承关系:Ctrl+H或者Ctrl+Shift+Alt ...
- Singer 学习十一 配置以及状态管理
配置和状态文件通过提供身份验证信息,开始时间和有关以前调用的信息,帮助为Taps和Targets提供上下文 配置文件 配置文件包含tap 运行需要的信息,通常包含API,以及数据源的凭据 特殊字段 s ...
- oracle-db安装
在LINUX平台上手动创建多个实例(oracle11g) http://blog.csdn.net/sunchenglu7/article/details/39676659 安装完桌面与数据库软件后, ...
- 深入详解美团点评CAT跨语言服务监控(五)配置与数据库操作
CAT配置 在CAT中,有非常多的配置去指导监控的行为,每个配置都有相应的配置管理类来管理,都有一个配置名, 配置在数据库或者配置文件中都是以xml格式存储,在运行时会被解析到具体实体类存储.我们选取 ...
- Morris
Morris /*Morris遍历树: *一:如果一个结点有左子树会到达此节点两次(第二次到达结点的时候左子树的所有结点都遍历完成),第一次遍历左子树最后 * 节点为nullptr,第二次遍历指向他自 ...