题目:

Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:

  • All numbers (including target) will be positive integers.
  • Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1a2 ≤ … ≤ ak).
  • The solution set must not contain duplicate combinations.

For example, given candidate set 2,3,6,7 and target 7,
A solution set is:
[7]

[2, 2, 3]

题解

还是老问题,用DFS找解决方案,不同点是,这道题: The same repeated number may be chosen from C unlimited number of times.

所以,每次跳进递归不用都往后挪一个,还可以利用当前的元素尝试。

同时,这道题还要判断重复解。用我之前介绍的两个方法:

}  
     
          ArrayList<ArrayList<Integer>> res){  
                                            res.add(                      }
         
                                    item.add(candidates[i]);
                          helper(candidates,newtarget,i,item,res);            }  
     }