【KMP】Cyclic Nacklace
KMP算法
next[]深入了解,做到这题才真正明白next[]的用法,希望后面的题目能理解的更深刻。
Problem Description
As Christmas is around the corner, Boys are busy in choosing christmas presents to send to their girlfriends. It is believed that chain bracelet is a good choice. However, Things are not always so simple, as is known to everyone, girl's fond of the colorful decoration to make bracelet appears vivid and lively, meanwhile they want to display their mature side as college students. after CC understands the girls demands, he intends to sell the chain bracelet called CharmBracelet. The CharmBracelet is made up with colorful pearls to show girls' lively, and the most important thing is that it must be connected by a cyclic chain which means the color of pearls are cyclic connected from the left to right. And the cyclic count must be more than one. If you connect the leftmost pearl and the rightmost pearl of such chain, you can make a CharmBracelet. Just like the pictrue below, this CharmBracelet's cycle is 9 and its cyclic count is 2:Now CC has brought in some ordinary bracelet chains, he wants to buy minimum number of pearls to make CharmBracelets so that he can save more money. but when remaking the bracelet, he can only add color pearls to the left end and right end of the chain, that is to say, adding to the middle is forbidden. CC is satisfied with his ideas and ask you for help.
Input
Output
Sample Input
3
aaa
abca
abcde
Sample Output
0
2
5
Author
Source
#include<stdio.h>
#include<string.h>
char a[]; //要开够大小
int Next[];
void getNext(int len){
int i=,j=-;
Next[]=-;
while(i<len){
if(j==-||a[i]==a[j]){i++; j++; Next[i]=j; }
else j=Next[j];
}
}
int main()
{
int n,cir,len;
scanf("%d",&n);
while(n--)
{
scanf("%s",a);
len=strlen(a);
getNext(len);
cir=len-Next[len]; //循环节
if(len!=cir&&len%cir==)
printf("0\n");
else
printf("%d\n",cir-len%cir);
}
return ;
}
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