Description

Once upon a time in a country far away lived a king and he had a big kingdom. He was a very clever king but he had one weakness -- he could count only up to three.         Nevertheless, he did not consider this to be a really great drawback, since he had a lot of wizards who could count up to one hundred (and some of them, people said, even up to one thousand), so it was all right. But one day the grief came to the kingdom as the outnumbering barbarians started to approach from all sides. And the king then had to make the most important decision in his life. He had to choose which of his sons to make generals that he would send to the borders of the country to lead the army.         However, the king knew that though some of his sons were clever, just like he was, some of them were quite stupid and could only lower army spirits with their wrong decisions. More precisely, he knew about each of his sons his mental potential -- an integer number ranging from minus three to three (remember, that the king could count only up to three). He also knew that the chance of his army defeating barbarians was proportional to the sum of some powers of mental potentials of those of his sons that he would make generals (the power exponent was a positive integer number, the same for all his sons and not exceeding three either). Thus he had to choose such a combination of his sons to lead the army, that this sum would be maximal possible.         However, the king himself could not make all apropriate calculations since, for example, the second power of the number not exceeding three (which is its square) could be greater than three, and therefore he asked you, his most intellegent wizard, to solve this problem.      

Input

The first line of the input file contains the number of the sons of the king (integer number less or equal to one hundred). The second line contains the positive integer number not exceeding three, the exponent in the formula used to calculate the chance of defeating barbarians. The third line contains the list of mental potentials of king’s sons -- all integer numbers, not greater than three by their absolute value.      

Output

Output the only number -- the maximal possible chance of defeating barbarians measured as the sum described.      

Sample Input

3
3
2 -1 1

Sample Output

9

Hint

In the example above the king should choose his first and third sons to be the generals. In this case the chance to defeat barbarians, which is the sum of cubes of mental potentials of these sons, is eight plus one, that is nine.
没看明白题的意思!!!该题是求n个数的k次平方和的最大值!!注意k为偶数时,正负数的k次方都为正数,要计算在其中!!
 
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
int n,b,a,s=;
cin>>n;
cin>>a;
for(int i=;i<n;i++){
cin>>b;
if(b>||(b<&&a%==))s+=pow((double)b,a);
}
cout<<s;
//system("pause");
return ;
}

E - The King的更多相关文章

  1. BZOJ 1087: [SCOI2005]互不侵犯King [状压DP]

    1087: [SCOI2005]互不侵犯King Time Limit: 10 Sec  Memory Limit: 162 MBSubmit: 3336  Solved: 1936[Submit][ ...

  2. [bzoj1087][scoi2005]互不侵犯king

    题目大意 在N×N的棋盘里面放K个国王,使他们互不攻击,共有多少种摆放方案.国王能攻击到它上下左右,以及左上 左下右上右下八个方向上附近的各一个格子,共8个格子. 思路 首先,搜索可以放弃,因为这是一 ...

  3. King's Quest —— POJ1904(ZOJ2470)Tarjan缩点

    King's Quest Time Limit: 15000MS Memory Limit: 65536K Case Time Limit: 2000MS Description Once upon ...

  4. 【状压DP】bzoj1087 互不侵犯king

    一.题目 Description 在N×N的棋盘里面放K个国王,使他们互不攻击,共有多少种摆放方案.国王能攻击到它上.下.左.右,以及左上.左下.右上.右下八个方向上附近的各一个格子,共8个格子. I ...

  5. ZOJ 2334 Monkey King

    并查集+左偏树.....合并的时候用左偏树,合并结束后吧父结点全部定成树的根节点,保证任意两个猴子都可以通过Find找到最厉害的猴子                       Monkey King ...

  6. ACM ICPC 2015 Moscow Subregional Russia, Moscow, Dolgoprudny, October, 18, 2015 K. King’s Rout

    K. King's Rout time limit per test 4 seconds memory limit per test 512 megabytes input standard inpu ...

  7. BZOJ-1087 互不侵犯King 状压DP+DFS预处理

    1087: [SCOI2005]互不侵犯King Time Limit: 10 Sec Memory Limit: 162 MB Submit: 2337 Solved: 1366 [Submit][ ...

  8. POJ1364 King

    Description Once, in one kingdom, there was a queen and that queen was expecting a baby. The queen p ...

  9. [Educational Codeforces Round 16]A. King Moves

    [Educational Codeforces Round 16]A. King Moves 试题描述 The only king stands on the standard chess board ...

  10. codeforces A. Rook, Bishop and King 解题报告

    题目链接:http://codeforces.com/problemset/problem/370/A 题目意思:根据rook(每次可以移动垂直或水平的任意步数(>=1)),bishop(每次可 ...

随机推荐

  1. PHP学习笔记二十五【类的继承】

    <?php //定义父类 class Stu{ public $name; protected $age; protected $grade; private $address;//私有变量不会 ...

  2. GO语言基础

    Go语言开发 一.Linux下搭建Go开发环境 首先下载Go语言的开发安装包,不管是在官方网站或者国内的Golang镜像都是可以的,注意区分64位和32位的安装包. 下载完安装包之后tar zxvf进 ...

  3. QT中的OpcDa 客户端 实现

    前段时间开发Windows下的设备端软件接触到了OPC DA,虽然现在有了更强大的OPC UA,但是为了兼容一些老的设备,不得不硬着头皮去啃这个老掉牙的已经过时了的技术.本来只是想粗略了解一下,简单写 ...

  4. 用git提交代码步骤

    1.git add XXXX2.git commit - 'xxx'3.git stash4. //git pull --rebase 4. git rebase origin/develop git ...

  5. python保留指定文件、删除目录其他文件的功能(2)

    在(1)中脚本实现了保留指定文件的功能,但不能删除空目录,在此补上删除空目录的方法 def DeleteEmptyDir(path): for i in range(1,100): for paren ...

  6. (?m)使用实例

    示例sql: # User@Host: zjzc_app[zjzc_app] @ [10.22.18.164] Id: 6069153 # Query_time: 153.908486 Lock_ti ...

  7. android连续点击两次返回键退出代码

    private long exitTime = 0; @Overridepublic boolean onKeyDown(int keyCode, KeyEvent event) { if(keyCo ...

  8. MongoDb C/java driver

    1,在linux下安装客户端连接windows下 的MongoDBServer.

  9. Raphaël—JavaScript Library

    Raphaël-JavaScript Library What is it? Raphaël is a small JavaScript library that should simplify yo ...

  10. 徐汉彬:亿级Web系统搭建—单机到分布式集群

    当一个Web系统从日访问量10万逐步增长到1000万,甚至超过1亿的过程中,Web系统承受的压力会越来越大,在这个过程中,我们会遇到很多的问题.为了解决这些性能压力带来问题,我们需要在Web系统架构层 ...