hdu5353

模拟，，，

每个人有一些糖果，每两个人之间只能给一个糖果，问最后是否能让所有人的糖果数量相同，只要确定一个糖果的流向其他的就能够确定。

马虎了，卡了好几天，心塞塞的。。。

#include<iostream>

#include<string.h>

#include<stdio.h>

using namespace std;

const int maxa = ;

int biaoji[maxa];

int vis[maxa];

int put[maxa][];

int ans(int a[], int n){

    int sta;

    int o = ;

    for(int i =;i < n; i++){

        if(a[i] > ){

            sta = i;

            break;

        }

    }

    memset(vis, , sizeof(vis));

    int len = ;

    int last = ;

    for(int k = sta;; k++){

        if(len++ > n*) break;

        int i = k % n;

        if(vis[i] == ){

            last = ;

            continue;

        }

        if(last ==  && a[i] == ){

            last = ;

            continue;

        }

        if(a[i] > ){

            last = ;

            put[o][] = i;

            put[o++][] = (i+)%n;

            vis[i] = ;

            a[i] --, a[(i+)%n] ++;

        }else if(a[i] < ) last = ;

    }

    /*for(int i =0 ;i < n; i++){

        printf("%d ", a[i]);

    }puts("");*/

    len = ;

    last = ;

    for(int i = sta; ; i--){

        i = (i%n+n*)%n;

        if(len++ > n*) break;

        if(vis[(i+n-)%n] == )continue;

        if(a[i] > ){

            put[o][] = i;

            put[o++][] = (i+n-)%n;

            vis[(i+n-)%n] = ;

            a[i] --;

            a[(i-+n)%n] ++;

        }

    }

    for(int i = ;i < n; i++){

        if(a[i] != ) return ;

    }

    puts("YES");

    printf("%d\n", o);

    for(int i = ;i  < o; i++){

        printf("%d %d\n", put[i][]+, put[i][]+);

    }return ;

}

int ans1(int a[], int n){

    int sta;

    int o = ;

    for(int i =;i < n; i++){

        if(a[i] > ){

            sta = i;

            break;

        }

    }

    memset(vis, , sizeof(vis));

    int len = ;

    int last = ;

    for(int i = sta; ; i--){

        i = (i%n+n)%n;

        if(last ==  && a[i] == ){

            last = ;

            continue;

        }

        if(len++ > n*) break;

        if(vis[(i+n-)%n] == ){

            last = ;

            continue;

        }

        if(a[i] > ){

            put[o][] = i;

            put[o++][] = (i+n-)%n;

            vis[(i+n-)%n] = ;

            a[i] --;

            a[(i-+n)%n] ++;

        }else if(a[i] < ){

            last = ;

        }

    }

    /*for(int i =0 ;i < n; i++){

        printf("%d ", a[i]);

    }puts("");*/

    len = ;

    last = ;

    for(int k = sta;; k++){

        if(len++ > n*) break;

        int i = k % n;

        if(vis[i] == )continue;;

        if(a[i] > ){

            last = ;

            put[o][] = i;

            put[o++][] = (i+)%n;

            vis[i] = ;

            a[i] --, a[(i+)%n] ++;

        }

    }

    for(int i = ;i < n; i++){

        if(a[i] != ) return ;

    }

    puts("YES");

    printf("%d\n", o);

    for(int i = ;i  < o; i++){

        printf("%d %d\n", put[i][]+, put[i][]+);

    }return ;

}

int a[maxa], b[maxa], c[maxa];

int main(){

    int t;

    scanf("%d", &t);

    while(t--){

        memset(biaoji, , sizeof(biaoji));

        int n;

        scanf("%d", &n);

        long long sum = ;

        int ok = ;

        for(int i = ;i < n; i++){

            scanf("%d", &a[i]);

            sum += a[i];

        }

        for(int i = ; i < n; i++){

            if(a[i] != a[i-]){

                ok = ;

                break;

            }

        }

        int ook = ;

        for(int i = ;i  < n; i++){

            b[i] = a[i] - sum/n;

            c[i] = b[i];

            if(c[i] > )biaoji[i] = ;

            else biaoji[i] = ;

            if(b[i] >  || b[i] < -) ook =;

        }

        if(ok == ){

            puts("YES\n0");

            continue;

        }

        if(sum % n !=  || ook){

            puts("NO");

            continue;

        }

        if(ans(b, n));

        else if(ans1(c, n));

        else puts("NO");

    }

}

/*

5

6

2 0 0  2 0 2

8

3 0 0 3 0 2 0 0

8

3 0 0 3 0 0 2 0

8

0 0 3 3 0 0 2 0

8

1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000001

*/

这是a过后花了二十分钟敲的不那么丑但依旧很丑的代码

#include<iostream>

#include<stdio.h>

#include<string.h>

using namespace std;

const int maxa = ;

int put[maxa][], vis[maxa];

int ans(int n, int a[]){

    int sta= ;

    for(int i = ;i < n; i++){

        if(a[i] > ){

            sta = i;

        }

    }

    memset(vis, , sizeof(vis));

    int len = , last = , o = ;

    for(int i = sta; ;i++){

        i = i%n;

        if(len++ > *n) break;

        if(vis[i] == ){

             last= ;

             continue;

        }

        if(last ==  && a[i] == ){

            last = ;

            continue;

        }

        if(a[i] > ){

            vis[i] = ;

            a[i] --, a[(i+)%n] ++;

            put[o][] = i;

            put[o][] = (i+)%n;

            o++;

        }else if(a[i] < ){

            last = ;

        }

    }

    len = , last = ;

    for(int i = sta; ; i--){

        i = (i+n)%n;

        if(len++ > n*) break;

        if(vis[(i+n-)%n] == ){

            last = ;

            continue;;

        }

        if(last ==  && a[i] == ){

            last = ;

            continue;

        }

        if(a[i] > ){

            vis[(i+n-)%n] = ;

            a[i] --, a[(i+n-)%n] ++;

            put[o][] = i;

            put[o][] = (i+n-)%n;

            o++;

        }else if(a[i] < ) last = ;

    }

    for(int i = ; i< n; i++){

        if(a[i]) return ;

    }

    puts("YES");

    printf("%d\n", o);

    for(int i =  ;i < o; i++){

        printf("%d %d\n", +put[i][], +put[i][]);

    }

    return ;

}

int ans1(int n, int a[]){

    int sta= ;

    for(int i = ;i < n; i++){

        if(a[i] > ){

            sta = i;

        }

    }

    memset(vis, , sizeof(vis));

    int len = , last = , o = ;

    for(int i = sta; ; i--){

        i = (i+n)%n;

        if(len++ > n*) break;

        if(vis[(i+n-)%n] == ){

            last = ;

            continue;;

        }

        if(last ==  && a[i] == ){

            last = ;

            continue;

        }

        if(a[i] > ){

            vis[(i+n-)%n] = ;

            a[i] --, a[(i+n-)%n] ++;

            put[o][] = i;

            put[o][] = (i+n-)%n;

            o++;

        }else if(a[i] < ) last = ;

    }

    len = , last = ;

    for(int i = sta; ;i++){

        i = i%n;

        if(len++ > *n) break;

        if(vis[i] == ){

             last= ;;continue;

        }

        if(last ==  && a[i] == ){

            last = ;

            continue;

        }

        if(a[i] > ){

            vis[i] = ;

            a[i] --, a[(i+)%n] ++;

            put[o][] = i;

            put[o][] = (i+)%n;

            o++;

        }else if(a[i] < ){

            last = ;

        }

    }

    for(int i = ; i< n; i++){

        if(a[i]) return ;

    }

    puts("YES");

    printf("%d\n", o);

    for(int i =  ;i < o; i++){

        printf("%d %d\n", +put[i][], +put[i][]);

    }

    return ;

}

int a[maxa], b[maxa], c[maxa];

int main(){

    int n, t;

    scanf("%d", &t);

    while(t--){

        scanf("%d", &n);

        long long sum = ;

        for(int i = ;i < n; i++){

            scanf("%d", &a[i]);

            sum += a[i];

        }

        if(sum % n){

            puts("NO"); continue;

        }

        for(int i = ;i < n; i++){

            b[i] = a[i] - sum /n;

            c[i] = b[i];

        }

        if(ans(n, b)) ;

        else if(ans1(n, c));

        else puts("NO");

    }

}

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