PAT005 Path in a Heap
题目:
Insert a sequence of given numbers into an initially empty min-heap H. Then for any given index i, you are supposed to print the path from H[i] to the root.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N and M (<=1000) which are the size of the input sequence, and the number of indices to be checked, respectively. Given in the next line are the N integers in [-10000, 10000] which are supposed to be inserted into an initially empty min-heap. Finally in the last line, M indices are given.
Output Specification:
For each index i in the input, print in one line the numbers visited along the path from H[i] to the root of the heap. The numbers are separated by a space, and there must be no extra space at the end of the line.
Sample Input:
5 3
46 23 26 24 10
5 4 3
Sample Output:
24 23 10
46 23 10
26 10
分析:主要是考查最小堆的建立。
代码:
typedef struct heapNode {
int elements[];
int size;
int capacity;
} MinHeapNode;
MinHeapNode *createHeap(int maxSize)
{
MinHeapNode *heap = (MinHeapNode *)malloc(sizeof(MinHeapNode));
heap->size = ;
heap->capacity = maxSize;
heap->elements[] = -; // 哨兵
return heap;
}
void insertToMinHeap(MinHeapNode *heap, int item)
{
if (heap->size == heap->capacity) {
return; // 堆已满,无法插入
}
int i = ++heap->size;
for (; heap->elements[i / ] > item; i /= ) {
heap->elements[i] = heap->elements[i / ];
}
heap->elements[i] = item;
}
int main()
{
// 接受输入
int itemNum, indexNum;
scanf("%d %d", &itemNum, &indexNum);
MinHeapNode *heap = createHeap(itemNum);
for (int i = ; i < itemNum; i++) {
int item;
scanf("%d", &item);
insertToMinHeap(heap, item);
}
int a[indexNum];
for (int i = ; i < indexNum; i++) {
int index;
scanf("%d", &index);
a[i] = index;
}
for (int i = ; i < indexNum; i++) {
int searchIndex = a[i];
int flag = ;
while (searchIndex > ) {
if (flag) {
printf("%d", heap->elements[searchIndex]);
flag = ;
} else {
printf(" %d", heap->elements[searchIndex]);
}
searchIndex /= ;
}
printf("\n");
}
}
运行结果:

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