Time Limit: 1000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu

[Submit]  
[Go Back]   [Status]

Description

Problem C: The Dragon of Loowater

Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear
of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major
problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a
knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted
to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!

Input Specification:

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of
knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.

The last test case is followed by a line containing:

0 0

Output Specification:

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:

Loowater is doomed!

Sample Input:

2 3
5
4
7
8
4
2 1
5
5
10
0 0

Output for Sample Input:

11
Loowater is doomed!

#include<iostream>
#include<algorithm>
using namespace std;
int a[20010],b[20010],i,j,k,m,n,sn;
int main()
{
while(cin>>m>>n)
{
if(n==0&&m==0)
break;
sn=0;
for(i=0;i<m;i++)
cin>>a[i];
for(i=0;i<n;i++)
cin>>b[i];
sort(a,a+m);
sort(b,b+n);
j=0;
for(i=0;i<n;i++)
{
if(b[i]>=a[j])
{
sn+=b[i];
if(++j==m)
break;
} }
if(j<m)
cout<<"Loowater is doomed!"<<endl;
else cout<<sn<<endl;
} return 0;
}

Dragon of Loowater的更多相关文章

  1. The Dragon of Loowater

      The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into ...

  2. uva-----11292 The Dragon of Loowater

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  3. uva 11292 Dragon of Loowater (勇者斗恶龙)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  4. UVA它11292 - Dragon of Loowater

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  5. UVA 11292 Dragon of Loowater(简单贪心)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  6. 贪心/思维题 UVA 11292 The Dragon of Loowater

    题目传送门 /* 题意:n个头,m个士兵,问能否砍掉n个头 贪心/思维题:两个数组升序排序,用最弱的士兵砍掉当前的头 */ #include <cstdio> #include <c ...

  7. Uva11292--------------(The Dragon of Loowater)勇者斗恶龙 (排序后贪心)

    ---恢复内容开始--- 题目: Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major ...

  8. [ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]

    Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shor ...

  9. UVa 11292 - Dragon of Loowater(排序贪心)

    Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...

随机推荐

  1. Python并发编程-进程的几个方法

    join()方法 from multiprocessing import Process import time def func(arg1,arg2): print('*'*arg1) time.s ...

  2. FastReport.Net使用:[28]数据合并

    基础数据 1.拖动数据源中的数据列到报表设计器中,获得一张简单的报表. 2.下面使用两种方法将期中考试和期末考试的成绩合并到一行显示 合并数据(分组方法) 1.按学生名字和科目来进行分组,成绩文本框咱 ...

  3. openssl-0.9.8k_WIN32(RSA密钥生成工具

    韩梦飞沙  韩亚飞  313134555@qq.com  yue31313  han_meng_fei_sha openssl-0.9.8k_WIN32(RSA密钥生成工具

  4. 范浩强treap 普通平衡树

    增加Split(分裂),Merge(合并)操作,非常好写,时间也不比普通treap慢什么. #include<bits/stdc++.h> using namespace std; str ...

  5. bzoj 3784

    第三道点分治. 首先找到黄学长的题解,他叫我参考XXX的题解,但已经没有了,然后找到另一个博客的简略题解,没看懂,最后看了一个晚上黄学长代码,写出来然后,写暴力都拍了小数据,但居然超时,....然后改 ...

  6. CountDownLatch源码分析

    CountDownLatch.Semaphore(信号量)和ReentrantReadWriteLock.ReadLock(读锁)都采用AbstractOwnableSynchronizer共享排队的 ...

  7. bzoj 2038 小Z的袜子 莫队算法

    题意 给你一个长度序列,有多组询问,每次询问(l,r)任选两个数相同的概率.n <= 50000,数小于等于n. 莫队算法裸题. 莫队算法:将序列分为根号n段,将询问排序,以L所在的块为第一关键 ...

  8. 更新teaching中fdSubjectID为null的老数据

    UPDATE wkwke.tbTeachingV3 teaching SET teaching.fdSubjectID = (                    SELECT fdValue FR ...

  9. redis细节

    Redis对于Linux是官方支持的,安装和使用没有什么好说的,普通使用按照官方指导,5分钟以内就能搞定.详情请参考: http://redis.io/download 但有时候又想在windows下 ...

  10. activemq 消息传送测试

    activemq 5.10.0,topic   messagelength字符 20000011     发送时间 接收时间 传送时间 毫秒 1 1443067284128 1443067288325 ...