HDU-3605-Escape(最大流, 状态压缩)

链接:

https://vjudge.net/problem/HDU-3605

题意:

2012 If this is the end of the world how to do? I do not know how. But now scientists have found that some stars, who can live, but some people do not fit to live some of the planet. Now scientists want your help, is to determine what all of people can live in these planets.

思路:

1e5个人,每个人都连边会T, 考虑每个人的状态,选10个星球,最多1024中选择,吧人转换程选择,压缩成1024中情况.

连到星球,在跑最大流即可.

代码:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <vector>
//#include <memory.h>
#include <queue>
#include <set>
#include <map>
#include <algorithm>
#include <math.h>
#include <stack>
#include <string>
#define MINF 0x3f3f3f3f
using namespace std;
typedef long long LL;
const int MAXN = 1e4+10;
const int INF = 1e9;
struct Edge
{
    int from, to, cap;
};
vector<Edge> edges;
vector<int> G[MAXN];
int Dis[MAXN], Vis[MAXN];
int Peo[MAXN];
int n, m, s, t, d;
void AddEdge(int from, int to, int cap)
{
    edges.push_back(Edge{from, to, cap});
    edges.push_back(Edge{to, from, 0});
    G[from].push_back(edges.size()-2);
    G[to].push_back(edges.size()-1);
}
bool Bfs()
{
    //Bfs构造分层网络
    memset(Dis, -1, sizeof(Dis));
    queue<int> que;
    que.push(s);
    Dis[s] = 0;
    while (!que.empty())
    {
        int u = que.front();
        que.pop();
//        cout << u << endl;
        for (int i = 0;i < G[u].size();i++)
        {
            Edge & e = edges[G[u][i]];
            if (e.cap > 0 && Dis[e.to] == -1)
            {
                que.push(e.to);
                Dis[e.to] = Dis[u]+1;
            }
        }
    }
    return (Dis[t] != -1);
}
int Dfs(int u, int flow)
{
    //flow 表示当前流量上限
    if (u == t)
        return flow;
    int res = 0;
    for (int i = 0;i < G[u].size();i++)
    {
        Edge & e = edges[G[u][i]];
        if (e.cap > 0 && Dis[u]+1 == Dis[e.to])
        {
            int tmp = Dfs(e.to, min(flow, e.cap)); //  递归计算顶点 v
            flow -= tmp;
            e.cap -= tmp;
            res += tmp;
            edges[G[u][i]^1].cap += tmp;
            if (flow == 0)
                break;
        }
    }
    if (res == 0)
        Dis[u] = -1;
    return res;
}
int MaxFlow()
{
    int res = 0;
    while (Bfs())
    {
        res += Dfs(s, INF);
    }
    return res;
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    while (cin >> n >> m)
    {
        memset(Peo, 0, sizeof(Peo));
        s = 1023+m+1, t = 1023+m+2;
        for (int i = 0;i <= t;i++)
            G[i].clear();
        edges.clear();
        int w;
        for (int i = 1;i <= n;i++)
        {
            int res = 0;
            for (int j = 0;j < m;j++)
            {
                cin >> w;
                res += (1<<j)*w;
            }
//            cout << res << endl;
            Peo[res]++;
        }
        for (int i = 1;i <= m;i++)
        {
            cin >> w;
            AddEdge(1023+i, t, w);
        }
        for (int i = 0;i <= 1023;i++)
        {
            if (Peo[i] == 0)
                continue;
            AddEdge(s, i, Peo[i]);
            int tmp = i;
            int cnt = 1;
            while (tmp)
            {
                if (tmp&1)
                {
                    AddEdge(i, 1023+cnt, Peo[i]);
                }
                tmp >>= 1;
                cnt++;
            }
        }
        int res = MaxFlow();
        if (res == n)
            cout << "YES" << endl;
        else
            cout << "NO" << endl;
    }
    return 0;
}
/*
 2 2
 1 1
 0 1
 2 2
 */