题目描述:

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

解题思路:

递归法。

代码描述:

/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean hasPathSum(TreeNode root, int sum) {
if(root == null)
return false;
if(root.left == null && root.right == null && root.val == sum)
return true;
return hasPathSum(root.left, sum - root.val) || hasPathSum(root.right, sum - root.val);
}
}

  

Java [Leetcode 112]Path Sum的更多相关文章

  1. [LeetCode] 112. Path Sum 路径和

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  2. leetcode 112. Path Sum 、 113. Path Sum II 、437. Path Sum III

    112. Path Sum 自己的一个错误写法: class Solution { public: bool hasPathSum(TreeNode* root, int sum) { if(root ...

  3. [LeetCode] 112. Path Sum ☆(二叉树是否有一条路径的sum等于给定的数)

    Path Sum leetcode java 描述 Given a binary tree and a sum, determine if the tree has a root-to-leaf pa ...

  4. [LeetCode] 112. Path Sum 二叉树的路径和

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  5. Java for LeetCode 112 Path Sum

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  6. leetcode 112 Path Sum ----- java

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  7. LeetCode 112. Path Sum (二叉树路径之和)

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  8. Leetcode 112. Path Sum

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  9. [Leetcode]112. Path Sum -David_Lin

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

随机推荐

  1. list 去掉重复的值

    去除List列表中重复值(3种解决方法)public static void main(String[] args) { String[] ar = { "dd", "c ...

  2. Corner case

    A corner case (or pathological case) is a problem or situation that occurs only outside of normal op ...

  3. hdu 3336 Count the string(思维可水过,KMP)

    题目 以下不是KMP算法—— 以下是kiki告诉我的方法,好厉害的思维—— 就是巧用标记,先标记第一个出现的所有位置,然后一遍遍从标记的位置往下找. #include<stdio.h> # ...

  4. POJ 2771 Guardian of Decency(求最大点独立集)

    该题反过来想:将所有可能发生恋爱关系的男女配对,那么可以带出去的人数应该等于这个二分图的最大独立集 先要做一下预处理,把不符合要求的双方先求出来, company[i][j]表示i.j四个标准都不符合 ...

  5. POJ 2400 Supervisor, Supervisee(KM)

    題目鏈接 題意 :N个部门和N个员工,每个部门要雇佣一个工人,部门对每个工人打分,从1~N,1表示很想要,N表示特别不想要,每个工人对部门打分,从1~N.1表示很想去这个部门,N表示特别不想去这个部门 ...

  6. ssh 公钥

    以前做ssh key登录方式时都是用的root帐号,基本都是无往不利的,权限采用默认即可.今天实验中两台机器帐号都是nianzong,一个普通的帐号.按照如下步骤: A机器:ssh-keygen -t ...

  7. Meteor 简介

    简介 先来活动一下大脑.假设你坐在电脑面前,在两个窗口中打开同一个文件夹. 在其中一个窗口中删除一个文件,另一个窗口中的这个文件会消失吗? 不用实际操作你也知道肯定会消失的.在本地文件系统中的操作,不 ...

  8. hdu1233

    http://acm.hdu.edu.cn/showproblem.php?pid=1233 最小生成树,kruskal算法 #include<stdio.h> #include<m ...

  9. Java学习笔记之:Java String类

    一.引言 字符串广泛应用在Java编程中,在Java中字符串属于对象,Java提供了String类来创建和操作字符串. 创建字符串最简单的方式如下: String str= "Hello w ...

  10. photoshop:调整图层之色相/饱和度

    色相/饱和度:快速调色及调整图片色彩浓淡明暗 面板主要参数:色相.饱和度.明度 色相用来改变颜色:顺序按红-黄-绿-青-蓝-洋红 饱和度用来控制色彩浓淡 明度控制色彩明暗 勾选“着色”,图片会变成单色 ...