A problem is easy

描述When Teddy was a child , he was always thinking about some simple math problems ,such as “What it’s 1 cup of water plus 1 pile of dough ..” , “100 yuan buy 100 pig” .etc..

One day Teddy met a old man in his dream , in that dream the man whose name was“RuLai” gave Teddy a problem :

Given an N , can you calculate how many ways to write N as i * j + i + j (0 < i <= j) ?

Teddy found the answer when N was less than 10…but if N get bigger , he found it was too difficult for him to solve.
Well , you clever ACMers ,could you help little Teddy to solve this problem and let him have a good dream ?

 

输入

The first line contain a T(T <= 2000) . followed by T lines ,each line contain an integer N (0<=N <= 10^11).

输出

For each case, output the number of ways in one line

样例输入

2
1
3

样例输出

0
1

 import java.util.Scanner;
 
 public class Main {
     public static void main(String[] args) {
         Scanner scanner=new Scanner(System.in);
         int T;
         int number;
         int i;
         int count;
 
         T=scanner.nextInt();
         while(true){
             if(T==0)
                 break;
             T--;
 
             number=scanner.nextInt();
 
             count=0;
             number++;
             for(i=2;i*i<=number;i++){
                 if(number%i==0)
                     count++;
             }
             System.out.println(count);
         }
     }
 }