模拟 HDOJ 5095 Linearization of the kernel functions in SVM

题目传送门

 /*
     题意：表达式转换
     模拟：题目不难，也好理解题意，就是有坑！具体的看测试样例。。。
 */
 #include <cstdio>
 #include <algorithm>
 #include <iostream>
 #include <cstring>
 #include <cmath>
 #include <string>
 #include <vector>
 #include <queue>
 #include <map>
 #include <set>
 #include <ctime>
 #include <cstdlib>
 using namespace std;
 const int MAXN = 1e4 + ;
 const int INF = 0x3f3f3f3f;
 char s[] = {'p', 'q', 'r', 'u', 'v', 'w', 'x', 'y', 'z'};
 int main(void)        //HDOJ 5095 Linearization of the kernel functions in SVM
 {
     //freopen ("F.in", "r", stdin);
     int t;    scanf ("%d", &t);
     while (t--)
     {
         int a[];    bool first = false;    int j = -;
         for (int i=; i<=; ++i)    scanf ("%d", &a[i]);
         for (int i=; i<=; ++i)
         {
             j++;
             if (!a[i])    continue;
             if (a[i] >  && first)    putchar ('+');
             if (a[i] == -)
             {
                 if (i < )    putchar ('-');
                 else    printf ("-1");
             }
             else
             {
                 if (a[i] == )
                 {
                     if (i == )    putchar ('');
                 }
                 else printf ("%d", a[i]);
             }
             first = true;
             if (j <= )    printf ("%c", s[j]);
         }
         if (!first)    printf ("");
         puts ("");
     }
     return ;
 }
 /*
 21
 0 46 3 4 -5 -22 -8 -32 24 27
 2 31 -5 0 0 12 0 0 -49 12
 0 1 0 0 0 0 0 0 0 -1
 0 0 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0 0 1
 1 -1 1 -1 1 1 1 1 1 0
 0 46 3 4 -5 -22 -8 -32 24 27
 2 31 -5 0 0 12 0 0 -49 12
 0 0 0 0 0 0 0 0 0 0
 1 2 3 4 5 6 7 8 9 10
 -1 2 3 -5 8 3 0 6 9 20
 1 -1 1 1 1 -1 -1 -1 0 0
 10000 123 123 123 456 12354 123 12345  45 10110
 0 0 0 1 2 3 -1 -2 -3 56
 0 0 0 -1 -2 0 0 1 23 45
 */
 /*
 46q+3r+4u-5v-22w-8x-32y+24z+27
 2p+31q-5r+12w-49z+12
 q-1
 0
 1
 p-q+r-u+v+w+x+y+z
 46q+3r+4u-5v-22w-8x-32y+24z+27
 2p+31q-5r+12w-49z+12
 0
 p+2q+3r+4u+5v+6w+7x+8y+9z+10
 -p+2q+3r-5u+8v+3w+6y+9z+20
 p-q+r+u+v-w-x-y
 10000p+123q+123r+123u+456v+12354w+123x+12345y+45z+10110
 u+2v+3w-x-2y-3z+56
 -u-2v+y+23z+45
 -u-2v+y+23z+45
 -u-2v+y+23z+45
 -u-2v+y+23z+45
 -u-2v+y+23z+45
 -u-2v+y+23z+45
 -u-2v+y+23z+45
 */