leetcode_712. Minimum ASCII Delete Sum for Two Strings
https://leetcode.com/problems/minimum-ascii-delete-sum-for-two-strings/
给定两个string s1,s2,从s1和s2中删除一些字符,使s1和s2相同,并且要求删除的所有字符的ASCLL码之和最小。
解法:
找出s1和s2的公共子串,并使得其ASCLL码之和最大,最用s1,s2所有字符ASCLL码之和减去最大子串的ASCLL码之和,即为需要删掉的最小ASCLL码值。
求ASCLL码之和最大的公共子串与求两字符串最长公共子串的方法相同。
class Solution{
public:
int minimumDeleteSum(string s1, string s2){
int sum1=, sum2=;
for(int i=; i<s1.size(); i++)
sum1 += s1[i];
for(int i=; i<s2.size(); i++)
sum2 += s2[i];
vector<vector<int> > dp(s1.size()+,vector<int>(s2.size()+, ));
for(int i=; i<s1.size(); i++)
for(int j=; j<s2.size(); j++)
if(s1[i] == s2[j])
dp[i+][j+] = max(dp[i+][j+], dp[i][j]+s1[i]*);
else
dp[i+][j+] = max(dp[i+][j+], max(dp[i][j+],dp[i+][j]));
return sum1 +sum2 - dp[s1.size()][s2.size()];
}
};
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