数dp多少个0-n多少0-9

#include <bits/stdc++.h>
using namespace std;
const int N = 15;
int n;
int dp[N][N][N];
int a[N],f[N];
int main() {
	freopen("in.txt", "r", stdin);
	freopen("out.txt", "w", stdout);
	for (int t = 0; t < 23; t++) {
		scanf("%d", &n);
		int k = 0;
		while (n) {
			a[k++] = n % 10;
			n /= 10;
		}
		int d = 1;
		memset(dp, 0, sizeof dp);
		for (int i = 0; i < k; i++) {
			for (int j = 0; j < 10; j++) {
				for (int y = 0; y < 10; y++) {
					if (i > 0) {
						for (int x = 0; x < 10; x++) {
							dp[i][j][y] += dp[i - 1][x][y];
						}
					}
					if (j == y) {
						dp[i][j][y] += d;
					}
				}
			}
			d *= 10;
		}
		memset(f, 0, sizeof f);
		for (int i = 0; i < 10; i++)
			for (int j = 0; j < k; j++)
				for (int x = 0; x < a[j]; x++)
					f[i] += dp[j][x][i];
		int x = 1, y = 0;
		for (int i = 0; i < k; i++) {
			f[a[i]] += y + 1;
			y += x*a[i];
			f[0] -= x;
			x *= 10;
		}
                f[0]++;
		for (int i = 0; i < 10; i++)
			printf(i == 9 ? "%d\n" : "%d ", f[i]);
	}
}