java 面向过程实现万年历

 public class Test {

     /**
      * @param args
      */
     public static void main(String[] args) {
         // TODO Auto-generated method stub
         // 定义变量
         int year, mouth;
         int day = 0;
         String cuowu;
         Scanner sc = new Scanner(System.in);
         int[] day1 = new int[] { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
         int[] day2 = new int[] { 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
         int week, dayNum = 0;

         // 输出
         System.out.println("*******************欢迎使用万年历****************\n");
         System.out.print("请选择年份：");
         // 判断是否输入我们需要的数据
         while (true) {
             if (sc.hasNextInt()) {
                 year = sc.nextInt();
                 if (year >= 1900) {
                     break;
                 } else {
                     System.out.print("输入数据不对请重新输入(1900年以后的年份)");
                 }
             } else {
                 System.out.print("数据类型错误请重新输入");
                 cuowu = sc.next();
             }
         }

         System.out.println();
         System.out.print("请选择月份：");
         while (true) {
             if (sc.hasNextInt()) {
                 mouth = sc.nextInt();
                 if (mouth > 0 && mouth < 13) {
                     break;
                 } else {
                     System.out.print("输入数据不对请重新输入(1~12)");
                 }
             } else {
                 System.out.print("数据类型错误请重新输入");
                 cuowu = sc.next();
             }
         }
         System.out.println();
         // 计算该年距离1900年1月1日有几天
         for (int i = 1900; i < year; i++) {
             if ((i / 400 == 0) || (i / 4 == 0 && i / 100 != 0)) {
                 day += 366;
             } else {
                 day += 365;
             }
         }
         // System.out.println(day);
         // 计算选择月份1日距离1900年1月1日有几天
         for (int i = 1; i < mouth; i++) {
             if ((year % 400 == 0) || ((year % 100 != 0) && (year % 4 == 0))) {
                 day += day2[i - 1];
             } else {
                 day += day1[i - 1];
             }
         }
         // System.out.println(day);
         // 计算该月第一天是星期几由于1900年1月1日是星期一，而我们打印从星期天开始，所以day+1
         week = (day + 1) % 7;
         // System.out.println(week);
         // 赋值dayNum该月有几天
         switch (mouth) {
         case 1:
         case 3:
         case 5:
         case 7:
         case 8:
         case 10:
         case 12:
             dayNum = 31;
             break;
         case 4:
         case 6:
         case 9:
         case 11:
             dayNum = 30;
             break;
         case 2:
             if ((year % 400 == 0) || ((year % 100 != 0) && (year % 4 == 0))) {
                 dayNum = 29;
             } else {
                 dayNum = 28;
             }
             break;
         default:
             break;
         }
         // 输出
         System.out.println("\t\t\t" + year + "年" + mouth + "月");
         System.out.println("星期日\t星期一\t星期二\t星期三\t星期四\t星期五\t星期六");
         for (int i = 0; i < week; i++) {
             System.out.print("" + "\t");
         }
         for (int i = 1; i <= dayNum; i++) {
             System.out.print(i + "\t");
             if ((week + i) % 7 == 0) {
                 System.out.println();
             }
         }

     }

 }