Union and Intersection of two sorted lists 并集和交集
跟面试官确认是arrayList还是singly-linked list
/*
Union 并集:两个升序的list a, b, 返回其并集(升序排序)
*/
public class UnionTwoSortedLists {
public List<Integer> union(List<Integer> a, List<Integer> b) {
List<Integer> result = new ArrayList<>();
// Use two index variables i and j, initial values i = 0, j = 0
int i = 0, j = 0;
while (i < a.size() && j < b.size()) {
// If a.get(i) < b.get(j) then add a.get(i) to result and increment i.
if (a.get(i) < b.get(j)) {
result.add(a.get(i));
i++;
}
// If b.get(j) < a.get(i) then add b.get(j) to result and increment j.
else if (b.get(j) < a.get(i)) {
result.add(b.get(j));
j++; }
// If both are same then add any to result and increment both i and j.
else {
result.add(b.get(j));
i++;
j++;
}
}
/* handle the case a.size()!= b.size(), add remaining elements of the larger array */
while (i < a.size()){
result.add(a.get(i));
i++;
}
while (j < b.size()){
result.add(b.get(j));
j++;
}
return result;
} public static void main(String[] args) {
List<Integer> l1 = new ArrayList<>();
l1.add(1);
l1.add(2);
l1.add(3);
List<Integer> l2 = new ArrayList<>();
l2.add(2);
l2.add(3);
UnionTwoSortedLists test = new UnionTwoSortedLists();
for(int n : test.union(l1,l2)){
System.out.println(n);
}
}
}
/*
Intersection 交集:两个升序的list a, b, 返回其交集(升序排序)
*/
public class IntersectionTwoSortedLists { public List<Integer> intersection(List<Integer> a, List<Integer> b) {
List<Integer> result = new ArrayList<>();
// Use two index variables i and j, initial values i = 0, j = 0
int i = 0, j = 0;
while (i < a.size() && j < b.size()) {
// If a.get(i) < b.get(j) then increment i.
if (a.get(i) < b.get(j)) {
i++;
}
// If b.get(j) < a.get(i) then increment j.
else if (b.get(j) < a.get(i)) {
j++; }
// If both are same then add any to result and increment both i and j.
else {
result.add(b.get(j));
i++;
j++;
}
}
return result;
} public static void main(String args[]) {
List<Integer> l1 = new ArrayList<>();
l1.add(1);
l1.add(2);
l1.add(3);
List<Integer> l2 = new ArrayList<>();
l2.add(2);
l2.add(5);
IntersectionTwoSortedLists test = new IntersectionTwoSortedLists();
for (int n : test.intersection(l1, l2)) {
System.out.println(n);
}
}
}
followup1: 上述问题是2个list, 求问n个list的union和intersection
Union and Intersection of two sorted lists 并集和交集的更多相关文章
- [LeetCode] Merge k Sorted Lists 合并k个有序链表
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这 ...
- [LeetCode] Merge Two Sorted Lists 混合插入有序链表
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing t ...
- [LintCode] Intersection of Two Linked Lists 求两个链表的交点
Write a program to find the node at which the intersection of two singly linked lists begins. Notice ...
- [LintCode] Merge Two Sorted Lists 混合插入有序链表
Merge two sorted (ascending) linked lists and return it as a new sorted list. The new sorted list sh ...
- No.023:Merge k Sorted Lists
问题: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexit ...
- Merge k Sorted Lists
1. Merge Two Sorted Lists 我们先来看这个 问题: Merge two sorted linked lists and return it as a new list. The ...
- 71. Merge k Sorted Lists
Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and descr ...
- 【leetcode】Merge k Sorted Lists
Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and descr ...
- Merge Two Sorted Lists
Merge Two Sorted Lists https://leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked ...
随机推荐
- Leetcode 题解 Combinations:回溯+求排列组合
罗列出从n中取k个数的组合数组. 首先,求C(n,k)这个实现,很粗糙,溢出也不考虑,好的方法也不考虑.笨蛋.心乱,上来就写.. 另外,发现在递归中,不能申请太大的数组?貌似不是这个问题,是我自己越界 ...
- Review CSS Selectors
Throughout this lesson, you learned how to select HTML elements with CSS and apply styles to them. L ...
- mysql 字符串数字转换
1 方法一:SELECT CAST('123' AS SIGNED); 2 方法二:SELECT CONVERT('123',SIGNED); 3 方法三:select '123'+1
- English Pronunciation Analysis | Advanced English Conversation
English Pronunciation Analysis | Advanced English Conversation Share Tweet Share Tagged With: Ben Fr ...
- Java如何创建参数个数不限的函数
可变的参数类型,也称为不定参数类型.英文缩写是varargus,还原一下就是variable argument type.通过它的名字可以很直接地看出来,这个方法在接收参数的时候,个数是不定的. pu ...
- 微信定时获取token
为了使第三方开发者能够为用户提供更多更有价值的个性化服务,微信公众平台开放了许多接口,包括自定义菜单接口.客服接口.获取用户信息接口.用户分组接口.群发接口等,开发者在调用这些接口时,都需要传入一个相 ...
- JAVAWEB 一一ibatis(框架)
,升级版是mybatis,在配置文件里写sql语句对字段进行CURD) jar包 sqlMapConfig <?xml version="1.0" encoding=&quo ...
- thymeleaf 的内置对象
- 利用monkeyrunner、python脚本来做多设备多apk适配ui界面截屏的自动化测试
http://www.cnblogs.com/youxilua/archive/2011/11/25/2262715.html
- lombok @Builder注解使用的例子、反编译之后的代码详解
lombok的@Builder实际是建造者模式的一个变种,所以在创建复杂对象时常使用 这里对lombok的@Builder和@Data组合的使用示例 import lombok.Builder; im ...