Uniform Generator 分类: HDU 2015-06-19 23:26 11人阅读 评论(0) 收藏
Uniform Generator
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 21176 Accepted Submission(s): 8294
Problem Description
Computer simulations often require random numbers. One way to generate pseudo-random numbers is via a function of the form
seed(x+1) = [seed(x) + STEP] % MOD
where ‘%’ is the modulus operator.
Such a function will generate pseudo-random numbers (seed) between 0 and MOD-1. One problem with functions of this form is that they will always generate the same pattern over and over. In order to minimize this effect, selecting the STEP and MOD values carefully can result in a uniform distribution of all values between (and including) 0 and MOD-1.
For example, if STEP = 3 and MOD = 5, the function will generate the series of pseudo-random numbers 0, 3, 1, 4, 2 in a repeating cycle. In this example, all of the numbers between and including 0 and MOD-1 will be generated every MOD iterations of the function. Note that by the nature of the function to generate the same seed(x+1) every time seed(x) occurs means that if a function will generate all the numbers between 0 and MOD-1, it will generate pseudo-random numbers uniformly with every MOD iterations.
If STEP = 15 and MOD = 20, the function generates the series 0, 15, 10, 5 (or any other repeating series if the initial seed is other than 0). This is a poor selection of STEP and MOD because no initial seed will generate all of the numbers from 0 and MOD-1.
Your program will determine if choices of STEP and MOD will generate a uniform distribution of pseudo-random numbers.
Input
Each line of input will contain a pair of integers for STEP and MOD in that order (1 <= STEP, MOD <= 100000).
Output
For each line of input, your program should print the STEP value right- justified in columns 1 through 10, the MOD value right-justified in columns 11 through 20 and either “Good Choice” or “Bad Choice” left-justified starting in column 25. The “Good Choice” message should be printed when the selection of STEP and MOD will generate all the numbers between and including 0 and MOD-1 when MOD numbers are generated. Otherwise, your program should print the message “Bad Choice”. After each output test set, your program should print exactly one blank line.
Sample Input
3 5 15 20 63923 99999
Sample Output
3 5 Good Choice 15 20 Bad Choice 63923 99999 Good Choice
小小的空格PE好几次,基础不扎实啊
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cstring>
using namespace std;
const int Max=110000;
bool vis[Max];
int main()
{
int STEP,MOD;
while(cin>>STEP>>MOD)
{
memset(vis,false,sizeof(vis));
vis[0]=true;
int sum=0;
int ans=1;
while(1)
{
sum=(sum+STEP)%MOD;
if(vis[sum])
{
break;
}
else
{
vis[sum]=true;
ans++;
}
}
if(ans<MOD)
{
printf("%10d%10d Bad Choice\n\n",STEP,MOD);
}
else
{
printf("%10d%10d Good Choice\n\n",STEP,MOD);
}
}
return 0;
}
版权声明:本文为博主原创文章,未经博主允许不得转载。
Uniform Generator 分类: HDU 2015-06-19 23:26 11人阅读 评论(0) 收藏的更多相关文章
- 认识C++中的临时对象temporary object 分类: C/C++ 2015-05-11 23:20 137人阅读 评论(0) 收藏
C++中临时对象又称无名对象.临时对象主要出现在如下场景. 1.建立一个没有命名的非堆(non-heap)对象,也就是无名对象时,会产生临时对象. Integer inte= Integer(5); ...
- 动态链接库(DLL) 分类: c/c++ 2015-01-04 23:30 423人阅读 评论(0) 收藏
动态链接库:我们经常把常用的代码制作成一个可执行模块供其他可执行文件调用,这样的模块称为链接库,分为动态链接库和静态链接库. 对于静态链接库,LIB包含具体实现代码且会被包含进EXE中,导致文件过大, ...
- Windows7下QT5开发环境搭建 分类: QT开发 2015-03-09 23:44 65人阅读 评论(0) 收藏
Windows7下QT开法环境常见搭配方法有两种. 第一种是:QT Creator+QT SDK: 第二种是:VS+qt-vs-addin+QT SDK: 以上两种均可,所需文件见QT社区,QT下载地 ...
- short-path problem (Floyd) 分类: ACM TYPE 2014-09-01 23:58 100人阅读 评论(0) 收藏
#include <cstdio> #include <iostream> #include <cstring> using namespace std; cons ...
- short-path problem (Dijkstra) 分类: ACM TYPE 2014-09-01 23:51 111人阅读 评论(0) 收藏
#include <cstdio> #include <iostream> #include <cstring> using namespace std; cons ...
- 树莓派安装mjpg-streamer视频监控 分类: Raspberry Pi 2015-04-12 23:41 144人阅读 评论(0) 收藏
原来使用Motion在树莓派上跑1280x720分辨率的三颗摄像头.占用内存太严重,关闭诸多功能之后还是不行.故转战mjpg-streamer. 首先安装所需软件 sudo apt-get insta ...
- 【从0到1学Web前端】CSS定位问题三(相对定位,绝对定位) 分类: HTML+CSS 2015-05-29 23:01 842人阅读 评论(0) 收藏
引子: 开始的时候我想先要解决一个问题,怎么设置一个div盒子撑满整个屏幕? 看下面的html代码: <body> <div id="father-body"&g ...
- 循环队列 分类: c/c++ 2014-10-10 23:28 605人阅读 评论(0) 收藏
利用线性表实现队列,为了有效利用空间,将其设计为循环结构,防止假溢出:牺牲一个存储单元以区分队空.队满. 设front队头,rear队尾,N为顺序表大小 队空:rear==front 队满:(rear ...
- 链表中用标兵结点简化代码 分类: c/c++ 2014-09-29 23:10 475人阅读 评论(0) 收藏
标兵结点(头结点)是在链表中的第一个结点,不存放数据,仅仅是个标记 利用标兵结点可以简化代码.下面实现双向链表中的按值删除元素的函数,分别实现 带标兵结点和不带标兵结点两版本,对比可见标兵结点的好处. ...
随机推荐
- Java socket中关闭IO流后,发生什么事?(以关闭输出流为例)
声明:该博文以socket中,关闭输出流为例进行说明. 为了方便讲解,我们把DataOutputstream dout = new DataOutputStream(new BufferedOutpu ...
- R语言putty中直接使用X11(Xming)绘图
1.下载Xming地址 http://pan.baidu.com/s/1o6ilisU,安装,推荐默认安装在C盘,推荐快捷方式放在与putty快捷方式同一个文件夹: 2.打开putty,在SSH的X1 ...
- Lintcode: Singleton && Summary: Synchronization and OOD
Singleton is a most widely used design pattern. If a class has and only has one instance at every mo ...
- 使用streaming window函数统计用户不同时间段平均消费金额等指标
场景 现在餐厅老板已经不满足仅仅统计历史用户消费金额总数了,他想知道每个用户半年,每个月,每天,或者一小时消费的总额,来店消费的次数以及平均金额. 给出的例子计算的是每5秒,每30秒,每1分钟的用户消 ...
- JSP-04- 实现数据的保存
.1 Session 一段时间内,单个客户与Web服务器的一连串相关的交换过程. Ø 4.1.1 应用的场景: 用户登录后保存用户状态 确定用户的唯一 Sessin.getId(); Ø ...
- Android SDK 安卓失败 提示: “Failed to fetch URL…” 的错误提示
解决方法: 1. 打开Tools 选择 options 将 第一个复选框勾上. (尝试一下,如果还是失败,参考2) 2. 打开本地host 文件, 在最后一行添加 ...
- 用VS2010编C#程序扫盲 2
0.正则表达式:http://www.runoob.com/csharp/csharp-regular-expressions.html 1.异常处理: try { // 引起异常的语句 } catc ...
- [OrangePi] Backup internal EMMC to SD Card
Boot your Orange PI board from EMMC without SD Card inserted login insert your SD Card Run: sudo ins ...
- [转]乐死我了,怎么样成为一个全栈程序员(Full Stack Developer),附我想专注的语言
受苏格拉底大神的启迪,我也来谈谈全栈.禅师:成为全栈工程师,这个问题等于如何成为全才,有可能吗码农:有可能,不过可能性比较低,因为达芬奇这类人毕竟是百年一遇的奇才.不过,因为我热爱这个行业,也有一定天 ...
- php使用过滤器filter_var轻松验证邮箱url和ip地址等
以前使用php的时候还不知道有过滤器filter这玩意,那时候判断邮箱.url和ip地址格式是否符合都是用正则表达式.后来随着使用的逐渐深入,才知道在php中也可以使用内置的函数库过滤器filter来 ...