【leetcode】Basic Calculator III
题目如下:
Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . The expression string contains only non-negative integers, +, -, *, / operators , open ( and closing parentheses ) and empty spaces . The integer division should truncate toward zero. You may assume that the given expression is always valid. All intermediate results will be in the range of [-2147483648, 2147483647]. Some examples: "1 + 1" = 2
" 6-4 / 2 " = 4
"2*(5+5*2)/3+(6/2+8)" = 21
"(2+6* 3+5- (3*14/7+2)*5)+3"=-12 Note: Do not use the eval built-in library function.
解题思路:算法上没有什么技术难度,无非就是要考虑各种情况。我的方法是用两个栈分别保存运算符号和非运算符号(包括数字和括号)。遇到右括号后,往前找左括号,遇到乘号或者除号,直接计算出结果。
代码如下:(写的很乱,也没心情优化了)
class Solution(object):
operator = []
num = []
def calcMandD(self,v):
if len(self.operator) == 0 or len(self.num) == 0:
return False
if (self.operator[-1] == '*' or self.operator[-1] == '/') and (self.num[-1] != '(' and self.num[-1] != ')'):
if self.operator[-1] == '*' :
tmp = int(self.num[-1]) * int(v)
self.num[-1] = str(tmp)
else:
tmp = int(self.num[-1]) / int(v)
self.num[-1] = str(tmp)
del self.operator[-1]
return True
return False
def calcParentheses(self):
t1 = self.num[-1]
del self.num[-1] tn = []
to = [] tn.append(t1) while self.num[-1] != '(':
t2 = self.num[-1] to.insert(0, self.operator[-1])
tn.insert(0, t2)
del self.operator[-1]
del self.num[-1]
del self.num[-1] #del ( t1 = tn[0]
del tn[0]
while len(tn) > 0:
t2 = tn[0]
if to[0] == '+':
t1 = int(t1) + int(t2)
elif to[0] == '-':
t1 = int(t1) - int(t2)
del to[0]
del tn[0]
return str(t1)
#self.num.append(str(t1))
def calcAandM(self):
t1 = self.num[0]
del self.num[0]
while len(self.num) > 0:
t2 = self.num[0]
if self.operator[0] == '+':
t1 = int(t1) + int(t2)
elif self.operator[0] == '-':
t1 = int(t1) - int(t2)
del self.operator[0]
del self.num[0]
return int(t1) def calculate2(self, s):
n = ''
for i in s:
if i == ' ':
continue
if i == '+' or i == '-' or i == '*' or i == '/':
if n != '':
if self.calcMandD(n) == False:
self.num.append(n)
n = ''
self.operator.append(i)
continue
if i == '(':
if n != '':
self.num.append(n)
n = ''
self.num.append(i)
continue
if i == ')':
if n != '':
if self.calcMandD(n) == False:
self.num.append(n)
n = ''
ret = self.calcParentheses()
while len(self.operator) >0 and (self.operator[-1] == '*' or self.operator[-1] == '/') and (self.num[-1] != '(' and self.num[-1] != ')'):
if self.operator[-1] == '*':
#print self.num
#print self.operator
ret = int(self.num[-1]) * int(ret)
else:
ret = int(self.num[-1])/int(ret)
del self.operator[-1]
del self.num[-1]
self.num.append(ret) continue
if i>='' and i <= '':
n += i
if n!='':
if self.calcMandD(n) == False:
self.num.append(n) def calculate(self, s):
"""
:type s: str
:rtype: int
"""
self.operator = []
self.num = []
self.calculate2(s)
#print (self.operator)
#print (self.num)
return self.calcAandM()
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