leetcode 297二叉树的序列化与反序列化

to_string(x) 将数字x转化为string

atoi(x) 将char转化为int

stoi(x) 将string 转化为int

采用中序遍历的顺序存储，NULL用#表示，以，分隔，O(n)time O(n) space

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
 
/**
使用先序递归序列来进行序列化与反序列化
to_string转化为string以逗号分隔；递归终点x->val==NULL
 
getline(s,str,',');每次读取','之前的字符串；递归终点str=="#"
**/
class Codec {
public:
 
    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
        if(root==NULL)
            return "#";
        else
            return to_string(root->val)+","+serialize(root->left)+","+serialize(root->right);
    }
 
    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        if(data=="#")
            return NULL;
        stringstream s(data);
        return makedeserialize(s);
    }
    TreeNode* makedeserialize(stringstream&s){
        string str;
        getline(s,str,',');
        if(str=="#")
            return NULL;
 
        TreeNode* root=new TreeNode(stoi(str));
        root->left=makedeserialize(s);
        root->right=makedeserialize(s);
 
        return root;
    }
};
 
// Your Codec object will be instantiated and called as such:
// Codec codec;
// codec.deserialize(codec.serialize(root));

采用层序遍历的顺序，储存每一层的值，不存在的或者NULL值用#代替，每个位置以'/'结束

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Codec {
public:
 
    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
        string res;
        queue<TreeNode*> q;
        q.push(root);
        int flag=;
        while(flag){
            flag=;
            int k=q.size();
            for(int i=;i<k;i++){
                TreeNode* p=q.front();
                q.pop();
                if(p==NULL){
                    res.push_back('#');
                    q.push(NULL);
                    q.push(NULL);
                }else{
                    int value=p->val;
                    if(value<) {res.push_back('-');value=-value;}
                    stack<char> s;
                    if(value==) s.push('');
                    while(value){
                        int e=value%;
                        s.push(e+'');value=value/;
                    }
                    while(!s.empty()){
                        res.push_back(s.top());s.pop();
                    }
                    q.push(p->left);
                    q.push(p->right);
                    if(p->left||p->right) flag=;
                }
                res.push_back('/');
            }
        }
        cout<<res<<endl;
        return res;
    }
 
    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        if(data.size()==) return NULL;
        if(data.size()==&&data[]=='#')return NULL;
        int len=data.size();
        vector<TreeNode*> v;
        for(int i=;i<len;i++){
            if(data[i]=='/')continue;
            TreeNode* p=NULL;
 
            if(data[i]!='#'){
                int value=;
                int flag=;
                if(data[i]=='-') {flag=-;i++;}
                while(data[i]!='/'){
                    value=*value+data[i]-'';
                    i++;
                }
                value=flag*value;
                p=new TreeNode(value);
            }
 
            v.push_back(p);
        }
        for(int i=;i<(v.size()-)/;i++){
            if(v[i]!=NULL){
                v[i]->left=v[*i+];
                v[i]->right=v[*i+];
            }
        }
        return v[];
    }
};
 
// Your Codec object will be instantiated and called as such:
// Codec codec;
// codec.deserialize(codec.serialize(root));

测试例子如下：

样例通过为47/48，一个深度为1000的偏二叉树没有通过；