【Kata Daily 190919】Sort Out The Men From Boys（排序）

题目：

Scenario

Now that the competition gets tough it will Sort out the men from the boys .

Men are the Even numbers and Boys are the odd  

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Task

Given an array/list [] of n integers , Separate The even numbers from the odds , or Separate the men from the boys  

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Notes

• Return an array/list where Even numbers come first then odds

• Since , Men are stronger than Boys , Then Even numbers in ascending order While odds in descending .

• Array/list size is at least *4*** .

• Array/list numbers could be a mixture of positives , negatives .

• Have no fear , It is guaranteed that no Zeroes will exists . 

• Repetition of numbers in the array/list could occur , So (duplications are not included when separating).

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Input >> Output Examples:

menFromBoys ({7, 3 , 14 , 17}) ==> return ({14, 17, 7, 3})

Explanation:

Since , { 14 } is the even number here , So it came first , then the odds in descending order {17 , 7 , 3} .

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menFromBoys ({-94, -99 , -100 , -99 , -96 , -99 }) ==> return ({-100 , -96 , -94 , -99})

Explanation:

• Since , { -100, -96 , -94 } is the even numbers here , So it came first in ascending order , *then** *the odds in descending order { -99 }

• Since , (Duplications are not included when separating) , then you can see only one (-99) was appeared in the final array/list .

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menFromBoys ({49 , 818 , -282 , 900 , 928 , 281 , -282 , -1 }) ==> return ({-282 , 818 , 900 , 928 , 281 , 49 , -1})

Explanation:

• Since , {-282 , 818 , 900 , 928 } is the even numbers here , So it came first in ascending order , then the odds in descending order { 281 , 49 , -1 }

• Since , (Duplications are not included when separating) , then you can see only one (-282) was appeared in the final array/list .

题目很长，其实大意就是：找出list中的偶数和奇数的不重复组合，偶数进行升序，奇数进行降序排列

解题办法：

def men_from_boys(arr):
    return sorted([i for i in set(arr) if i%2==0]) + sorted([i for i in set(arr) if i%2!=0], reverse=True)

其他解题思路：

def men_from_boys(arr):
    men = []
    boys = []
    for i in sorted(set(arr)):
        if i % 2 == 0:
            men.append(i)
        else:
            boys.append(i)
    return men + boys[::-1]

知识点：

1、去除重复项使用set()

2、排序使用sorted(list, reverse=False)

3、奇数偶数获取