Suppose there are M people, including you, playing a special card game. At the beginning, each player receives N cards. The pip of a card is a positive integer which is at most N*M. And there are no two cards with the same pip. During a round, each player chooses one card to compare with others. The player whose card with the biggest pip wins the round, and then the next round begins. After N rounds, when all the cards of each player have been chosen, the player who has won the most rounds is the winner of the game. 
Given your cards received at the beginning, write a program to tell the maximal number of rounds that you may at least win during the whole game. 

InputThe input consists of several test cases. The first line of each case contains two integers m (2 <= m <= 20) and n (1 <= n <= 50), representing the number of players and the number of cards each player receives at the beginning of the game, respectively. This followed by a line with n positive integers, representing the pips of cards you received at the beginning. Then a blank line follows to separate the cases.

The input is terminated by a line with two zeros. 
OutputFor each test case, output a line consisting of the test case number followed by the number of rounds you will at least win during the game. 
Sample Input

2 5
1 7 2 10 9 6 11
62 63 54 66 65 61 57 56 50 53 48 0 0

Sample Output

Case 1: 2
Case 2: 4 题意:模拟打牌,m个人,每人n张牌。点数1-n*m,出得最大的那个人赢一局,问你最多赢几局 题解:贪心,我出大的,对面出最小的,我出小的,对面最小但比我大的



#include<iostream>
#include<algorithm>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstdlib>
#include<queue>
using namespace std;
#define PI 3.14159265358979323846264338327950
bool a[];
int main()
{
int m=,n=,count=,t;
while(scanf("%d %d",&m,&n) && (m||n))
{
count++;
int i=;
int win=,big=;
memset(a,,sizeof(a));
for(i=;i<n;i++)
{
scanf("%d",&t);
a[t]=;
}
for(i=n*m;i>;i--)
{
if (a[i])
{
if (big==)
++win;
else
big--;
}
else
big++;
}
printf("Case %d: %d\n",count,win);
}
return ;
}

hdu-1338 game predictions(贪心题)的更多相关文章

  1. Saving HDU(hdu2111,贪心)

    Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total ...

  2. HDU 4442 Physical Examination(贪心)

    HDU 4442 Physical Examination(贪心) 题目链接http://acm.split.hdu.edu.cn/showproblem.php?pid=4442 Descripti ...

  3. 【ZROI 537】贪心题 题解

    [ZROI 537]贪心题 题解 Link Solution 最大的一边直接放到一起贪心即可 着重讲小的一边 已知对于二分图匹配,其答案即为最大流 令时间集合为 \(T = {1,2,3,\dots, ...

  4. HDU 5303 Delicious Apples (贪心 枚举 好题)

    Delicious Apples Time Limit: 5000/3000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Other ...

  5. HDU 4334——Trouble——————【贪心&水题】

    Trouble Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Su ...

  6. HDU—2021-发工资咯(水题,有点贪心的思想)

    作为杭电的老师,最盼望的日子就是每月的8号了,因为这一天是发工资的日子,养家糊口就靠它了,呵呵  但是对于学校财务处的工作人员来说,这一天则是很忙碌的一天,财务处的小胡老师最近就在考虑一个问题:如果每 ...

  7. HDU 6034 Balala Power! (贪心+坑题)

    题意:给定一个 n 个字符串,然后问你怎么给 a-z赋值0-25,使得给定的字符串看成26进制得到的和最大,并且不能出现前导0. 析:一个很恶心的题目,细节有点多,首先是思路,给定个字符一个权值,然后 ...

  8. HDU 1338 Game Prediction【贪心】

    解题思路: 给出 n  m 牌的号码是从1到n*m 你手里的牌的号码是1到n*m之间的任意n个数,每张牌都只有一张,问你至少赢多少次 可以转化为你最多输max次,那么至少赢n-max次 而最多输max ...

  9. hdu 5455 Fang Fang 坑题

    Fang Fang Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5455 ...

随机推荐

  1. standby checking script 3则 V1 shell 脚本

    ---1 #!/bin/sh export ORACLE_SID=hdbexport ORACLE_BASE=/db/hdbdg/app/product/databaseexport ORACLE_H ...

  2. .md文件插图片,不建议使用绝对地址。

    一 主要有两种方法,一种绝对地址,一种相对地址. 而百度的话,全都是说绝对地址的. 但是,有很大的弊端啊 orz 二 先说绝对地址 ![image](https://github.com/AngelS ...

  3. Git 忽略規則及 .gitignore 規則不生效的辦法

    Git忽略规则: 在git中如果想忽略掉某个文件,不让这个文件提交到版本库中,可以使用修改根目录中 .gitignore 文件的方法(如果没有这个文件,则需自己手工建立此文件).这个文件每一行保存了一 ...

  4. 微信开发 config:invalid url domain

    当遇到config:invalid url domain 有2种可能 1.没有配置url. 2.url配置错误.配置url如http://write.blog.csdn.NET/,就要这样配置writ ...

  5. 使用PowerShell 获取azure image publisher offer sku 信息

    使用azure powershell 获取指定区域的可用镜像 publisher offer sku信息 param ( [parameter(Mandatory = $false)] $Locati ...

  6. -oN ,-oX,-oG

    -oN ,正常输出 -oX, xml输出 nmap  192.168.9.12 -oX TEST.xml -oG grep输出 html文件可读性比xml文件要好,将xml转换成html     xs ...

  7. ADO.Net——增、删、改、查

    数据访问 对应命名空间:System.Data.SqlClient; SqlConnection:连接对象 SqlCommand:命令对象 SqlDataReader:读取器对象 CommandTex ...

  8. HTTP协议初探

    HTTP协议初探 HTTP协议初探 什么是http协议? 遵守协议的双方 再来回答什么是http协议 抓到这两段文本 可以总结出以下规律 HTTP 请求命令(动作,谓词 ,METHOD) GET 和 ...

  9. 有一个无效 SelectedValue,因为它不在项目列表中

    “Drp_XX”有一个无效 SelectedValue,因为它不在项目列表中 出现以上异常的原因肯定是将DrowDownList控件的SelectedValue属性赋值为一个列表中不存在的值.那么我们 ...

  10. MovieReview—Transformers.The.Last.Knight.(变形金刚5:最后的骑士.)

     Gorgeous Effect & Bad Plot   I can only say that the movie's effects are shocking. However, the ...