题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2483

组织一棵Trie 记录每个节点有多少串经过 统计最大值

由于只出现0,1,于是建立一个字典树,每一次到达一个节点,就在这个节点加上深度,然后ans求解最大的节点附加值就可以了。注意初始化

 #include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <vector>
#include <cstdlib>
#include <iomanip>
#include <cmath>
#include <ctime>
#include <map>
#include <set>
#include <queue>
using namespace std;
#define lowbit(x) (x&(-x))
#define max(x,y) (x>y?x:y)
#define min(x,y) (x<y?x:y)
#define MAX 100000000000000000
#define MOD 1000000007
#define pi acos(-1.0)
#define ei exp(1)
#define PI 3.141592653589793238462
#define INF 0x3f3f3f3f3f
#define mem(a) (memset(a,0,sizeof(a)))
#define maxnode 100000
typedef long long ll;
ll gcd(ll a,ll b){
return b?gcd(b,a%b):a;
}
bool cmp(int x,int y)
{
return x>y;
}
const int N=;
const int mod=1e9+;
int n;
struct Trie
{
int ch[maxnode][];
int val[maxnode];
int sz=,ans=;
void init(){sz=;
ans=;
memset(ch[],,sizeof(ch[]));
memset(val,,sizeof(val));
}
int idx(char c){
return c-'';
}
void insert(char* s,int len){
int u=;
for(int i=;i<len;i++){
int v=idx(s[i]);
if(!ch[u][v]){
memset(ch[sz],,sizeof(ch[sz]));
ch[u][v]=sz++;
}
u=ch[u][v];
val[u]+=(i+);
ans=max(ans,val[u]);
}
}
};
struct Trie trie;
char s[maxnode];
int main()
{
int t;
cin>>t;
while(t--){
trie.init();
cin>>n;
while(n--){
cin>>s;
trie.insert(s,strlen(s));
}
cout<<trie.ans<<"\n";
}
return ;
}

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