go语言json转map

package util
import (
	"encoding/json"
	"fmt"
)
// json转map函数，通用
func JSONToMap(str string) map[string]interface{} {
	var tempMap map[string]interface{}
	err := json.Unmarshal([]byte(str), &tempMap)
	if err != nil {
		panic(err)
	}
	return tempMap
}

• 如果map中含有数组，并且数组中是数字，需要求和，如何去做

rain = "{\"reqTime\":\"201911141554\",\"startTime\":\"201911141555\",\"endTime\":\"201911141755\",\"series\":[0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.07,0.14,0.32,0.51,0.72,0.92,1.11,1.28,1.41,1.5,1.53,1.5,1.41,1.28,1.11,0.92,0.72,0.51,0.32,0.14,0.07,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0],\"amendNow\":\"多云\",\"amendNowwen\":\"Cloudy\",\"amendNowwcode\":\"01\",\"msg\":\"1小时后会有雪，出门记得带伞\"}"
	fmt.Println(rain)
	// Json转map，  map[string]interface{}
	rainMap := util.JSONToMap(rain)    //
	// 降雨量之和
	sum := 0.00
	// 遍历map中的series数组，降雨量相加
	for _, num := range rainMap["series"].([]interface{}) {
		sum += num.(float64) // 这里使用断言
	}
        fmt.Println(sum)   // 结果为 17.490000000000002

• 如果是多层的json，请参考我的另一篇博客：
  
  (json后的)多层map取值

• 另外感谢网友解决了我的问题：https://www.golangtc.com/t/5628a59fb09ecc56ca000165